How To Move Multiple Div Elements Together
Feb 22, 2010Is it possible to move multiple divs with absolute positioning down the page simultaneously by the same amount?
View 3 RepliesIs it possible to move multiple divs with absolute positioning down the page simultaneously by the same amount?
View 3 RepliesI'm trying to move a set of divs into their parent elements. Currently I'm using:
[Code]...
If my understanding is correct
Code JavaScript:
$("#foo").appendTo("#bar");
will adjust
Code HTML4Strict:
<div>
<p id="foo">My Foo!!!</p>
</div>
<div id="bar">
</div>
[Code]...
I have created a jquery sortable list page where the user can move and drop elements between lists. The lists are <li>. how to get serialize to work. Here is a link for a serialize script that I am trying to use. [URL] I program in classic asp and don't understand javascript particularly well.
View 2 Replies View RelatedI need to be able to move items that come from a database (no problem with that) between three multiple select boxes. I also need to be able to move the items up and down within individual boxes....
View 1 Replies View RelatedI am using jquery with the cookie plugin and I have multiple image buttons that can hide/show multiple elements. My question is how can I add a cookie to this code to remember whether each separate element is opened or closed?
The code,
$(document).ready(function() {
// choose text for the show/hide link - can contain HTML (e.g. an image)
var showText='<div class="expanddown"></div>';
var hideText='<div class="expandup"></div>';
// initialise the visibility check
var is_visible = false;
// append show/hide links to the element directly preceding the element with a class of "toggle"
$('.toggle').prev().append('<a href="#" class="togglelink">'+hideText+'</a>');
// capture clicks on the toggle links
$('a.togglelink').click(function() {
// switch visibility
is_visible = !is_visible;
// change the link depending on whether the element is shown or hidden
$(this).html( (!is_visible) ? hideText : showText);
// toggle the display - uncomment the next line for a basic "accordion" style
//$('.toggle').hide();$('a.toggleLink').html(showText);
$(this).parent().next('.toggle').slideToggle('fast');
// return false so any link destination is not followed
return false;
});
});
HTML,
<a class="togglelink" href="#"></a>
<div class="toggle">
Content
</div>
The javascript served banner is moved from #apple1 to #targetplace. Some times the banner is displayed on both places. Are two page impressions counted for this one page the banner is displayed? Executes the browser the javascript once or each time the javascript is moved?
View 6 Replies View RelatedI have 2 select boxes which are separated by the buttons "Choose" and "Remove"I have populated the 1st Select Box with 10 elements. I want the elements to move over to the 2nd Select Box when the user clicks "Choose"I have given the 1st Select Box an id of "firstBox," and the 2nd Select Box has an id of "secondBox"I am trying to write a function called "add" to move elements from the 1st box to the second. So far I have:
function add()
{
var y=document.getElementById("secondBox")
var x=document.getElementById("firstBox");[code].....
Still the elements from the first box are non populating in the second box.I have played around with "appendChild" but I cannot get that to work either.
I am trying to make a gui for clients to edit a php page that displays html and javascript.
I want the user to be able to move html elements around and even edit it like add effects like fade in and out etc.
Then after all the changes I want to overwrite the existing php file that does this for that user. how can you make such changes and then save it to a file?
It's an html / javascript editor but using a gui instead of allowing them to directly touch the code. It would be a security risk if I allow such a thing. So I need to program a interface that would make such changes and save them to file.
Like how can you delete and add new javascript code to the file?
I am trying to create an Image menu for a site I'm working on that is rather simple in essence. When the user hovers over a button I have the menu will move left or right depending. I have not got a great deal into it yet as I have become stuck, as I'm new I figured it would be easier to troubleshoot if I build up the program bit by bit.
[Code]...
I am doing a form for my site and would like to enable and disable a radio
button set depending on whether one of the choices on an outer radio button
set is checked. How can I refer to all the inputs of the inner radio button
set (they all share a common name) with javascript. I tried
document.getElementsByNames('thename') but it doesn't work. I know this is
because this method returns an array which you must then refer to by a
specific index number, unless there is another way. I would like to refer to
all of them at once and then set their disabled status to false.
I have a dynamically generated page (PHP), which contains an Explorer
like view of items. I would like to hide multiple <tr>'s by name, but
I can't figure out how thats done.
I have this code to hide one element by id
if (document.getElementById(id)){
document.getElementById(id).style.position = 'relative'
document.getElementById(id).style.display = 'none'
}
Anyone has a cod sample for looping through multiple elements and hide
them?
The short of it is that I am trying to change the background color of all elements with a particular class name. I know there is no getElementsByClassName (wouldn't it be nice if there were?), but is there a simple way to do it? Alternatively, is there a way to apply changes to multiple id's?
View 3 Replies View RelatedI have written a function to make visible elements with a certain id. however i intended it to be used to make visible multiple elements but it only appears to switch on the first element it comes to with that id. after that it appears to stop. i was wondering how i can adapt this function to make visible multiple elements, will i need a different way of referencing or can it be done through id?
function toggleLayer( layerID ) {
var style2 = document.getElementById( layerID );
if (style2.style.display == "block") {
style2.style.display = "none";
}
else {
style2.style.display = "block";
}
}
I have a rather old script that uses XMLHttpRequest to retrieve some
html and pops it into a div using innerHTML. I'd like to switch over to
using append child since not only is it standardized, but it'll save me
bandwidth in the long run. Code:
I've selected multiple tables and tried to use each for applying cornering to each table. Inside the callback function, I try to find the first/last table cells to apply cornering for each corner. However, when there are multiple tables it looks at _all_ the tr elements for the first/last rows. See example code:
// Add cornering to tables
$('table.corner-me').addClass('ui-corner-all').each(function(){
var $table = $(this);
$table.find('tr:first :first-child').addClass('ui-corner-tl');
[Code].....
Can someone explain to me the best way to loop through the geocode and marker (google maps) part of this code for all of the elements with the "address" class using jQuery (or javascript if need be). I tried wrapping the contents of the codeAddress function in $(".address").each(function () {... and replacing the getElementById with a jquery selector, but I still seem to be lost.
[Code]...
I have this query that does what I want it to do, find the class and remove an extra element within its parent:
$(".emptyTopNavOption").parent().children().first().remove();
But when there are multiple classes, it only deletes the first element in its query. As a successful test, I appended some CSS to ensure the query selected all classes and added a border to each element. So why does remove() not work? Is it a bug or is my query missing something?
I just started using jquery a few days ago and am already addicted.Now I am trying to figure out one thing which I can't seem to get answered by Google:I am building a dynamic website where at one place there will be an unclear number of div-elements. So there can be none, just one or several.The plan is to show them by a click on a button via slideDown(). So I wrapped them with another div.wrapper via wrapAll(). This works nicely for any number.Now the thing is: if my .wrapper has no specified height, the slideDown jumps - which doesn't look very nice.So I gave it a height:$('.wrapper').css({'height': $('div').outerHeight()});Presto, the animation works smoothly. But this works only if there's just one div.
View 2 Replies View RelatedI am putting together a validation function and am having trouble with targeting multiple elements.[code]an onclick event fires my validation function. If any of the fields are empty, the appropriate error message should display.This sort of works. If all of the fields are empty, only the error message of the first element is displayed, not all 3.
View 1 Replies View RelatedI am performing the same animation three different times on three different elements. Is there a more efficient way to do this?
Here's my code:
$('.tier1').animate({opacity:.2}, 500)
$('.tier2').animate({opacity:.2}, 500)
[code]....
I'm having a problem with the <CANVAS> element in JavaScript. here's what i'm trying to do: I need 3 different canvas elements for writing a signature to. they must all 3 be visible at the same time
My problem that i'm having is that i can't seem to get the code to work which will write to more than one canvas.
[Code]...
I have a form that I want to clone and add up to 5 duplicates with slight changes. The changes are:
Add a second question and another set of related radio buttons for only the duplicates. Change the title in the Header to increment by 1 ex. Header 1, Header 2...
I also would like to make the form elements "id" and "names" unique. Also, continue to use the add and remove button at the bottom.
I have included my existing code.
NOTE: for a visual, I mocked up the the original form and 1 copy of the fields in the html, not to be used.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
[Code]....
Normally I would just use document.getElementById to get anything I need but here is my problem:
I have a zip code control that I load using AJAX. it has city, state, country, county and zip code. This gets loaded within a business application and at one point you can have both a bill to and ship to address forms on the screen at the same time, loading my zip control with the same fields, same ids and same name. This forced me to now pass in the form name that contains the control.
I need to get to divs and spans within this form. Primarily as you type in a city or zip code, I am doing a hot search with a popup div that shows you results you can quickly choose from. The only time this becomes an issue is the situation I mentioned before when the zip code control is on the screen twice. I am not certain how to access the innerHTML of a span or div by way of the form name. Is this possible and if so what is the proper syntax?
Here is a very basic example at its simplest form of my problem.
<form name="frm_billto" id="frm_billto">
<span id="myspan">Hello</span>
</form>
<form name="frm_shipto" id="frm_shipto">
<span id="myspan">World</span>
</form>
In the above example because the control was loaded twice, I now have 2 spans with the same ID. I want the innerHTML of the each span based on the form they are in.
We wanted one control that we could use throughout the system that we could update in one place and the entire application be updated. Unfortunately we did not anticipate having it load more than once on the page.
I am working with this script below, to assign a couple images to move randomly (like a sparkle effect), appended to a element,
How do i append it to several elements and still have it work, because when i change
Code:
$('#onedivelement').append(this.n);
to let's say
Code:
$('div').append(this.n);
[Code]....
Is it possible to duplicate a few form elements on click of a button? For example if we have a form with the following fields:
1. Name
2. Address
and we have a button that says add a member
on clicking of which the same two fields above should be added:
1. Name
2. Address