How To Use Firebug
Dec 5, 2011I want to learn how to use firebug, but I can not find tutorials or material. Can someone please let me know, where can I find material for firebug ?
View 2 RepliesI want to learn how to use firebug, but I can not find tutorials or material. Can someone please let me know, where can I find material for firebug ?
View 2 Replieswhat do you use firebug for in connection with javascript?
Just want to explore new ways of using it.
Currently I use it to:
1. debug my scripts using console.log(), etc.
2. test small things in the built in 'live' console
I'm rookie when it comes to Ajax and jQuery an..The following url produces an xml-file that I want to use on my page:When I use firebug it seems like nothing comes back. What have I done wrong?
This is what my code looks like:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
[code]....
I recently learned about a new Javascript Debugger called FireBug. From what I've heard, it's pretty good. Here's the link: Code:
View 4 Replies View RelatedI have firebug installed in my firefox browser, but I can't get console.log, console.debug or console.trace to work. My console window remains empty despite all my efforts. For example I have some code which throws up an alert box ( alert ('here is an alert') so I know 100% that it is being executed. If I now place the line
console.log("please log this to the console");next to it, nothing gets written to the console. I also have firephp installed and this is logging to the console for my php code absolutely fine
How is firebug used to test javascript?
View 1 Replies View Relatedhow I could use firebug to step through massive amounts of javascript that were written by someone else. I'm trying to figure something out for work which has me stumped.
An old co-worker wrote some scripts based on prototype to show input fields on a form when certain options were selected on the previous input fields. I'm trying to duplicate his old code but for some reason it's just not working. I can see that the reason those input fields aren't showing up is because display:none is being added on to the element by the js on the second step after the breakpoint (break on attribute change in firebug). This happens on the working page as well but the working page has about 10 more steps afterwards that eventually remove that style.
I founded a error in jQuery, with my code. I can't understand the origin of this error: b is undefined
gb=/,/;R=Array.prototype.slice;var Ia=...=0,e=this.length;f<e;f++){d=b.length;
There is the two files used:
scripts.js
/**
* Lollabot JQuery
* last update: 10/09/2010
[Code].....
I can't see the requests of the forms by firebug to debug. Does anyone know if have any option or any way to do this?
View 3 Replies View RelatedWhenever firebug detects a js error on a page, it prevents you from interacting with the page, so you can't scroll, you can't click, you can't do anything except close the window.
View 3 Replies View RelatedI'm trying to output things to the Console to track errors but everytime I try:
console.log(values);
it says "Console is not Defined"
I have a basic html page
Code HTML4Strict:
<!DOCTYPE html>
<html lang="en">[code]....
I'm downloading jQuery and specifying it using the src attribute on the scropt tag from http://code.jquery.com/jquery-1.6.2.min.js and i'm getting that error.I've tried downloading jQuery and saving it locally and that works. However if i use the CDN it's giving me that error on firebug.
Is there a trick (with javascript or something) that can change a hidden value on a page directly from the browser without using "Firebug" software? for example: <input type="hidden" name="something" value="something_else"> I need to change "something_else" to "something_else_2"
View 2 Replies View RelatedI am getting an error according to firebug of 'id_con is undefined'.i have made sure all entries are correct and i cannot see how to fix this error. how to correct this error.
The error is occuring on this line:
Code:
Code:
Firebug gives me the below error message:
component.singularize is not a function [Break on this error] var component = component.singularize();
This is what I have:
var component = window.location.hash.replace('#', '');
var component = component.singularize();
alert("The component name is " + component);
[Code]....
I'm coding a simple hover-opacity thing for some images on my site on the navigation bar. Although I'm receiving this message in my Firebug. uncaught exception: Syntax error, unrecognized expression: . Here's the navigation code:
[Code]....
I noticed on the "script" menu for firebug when I click "show static and eval scripts" you can see my entire JS code un-obfuscated by firebug. The default option is just "show static scripts" which shows my code as it is - obfuscated.I was quite frankly horrified to discover this after shelling out on software to protect my work. Does anyone have any idea how I can stop firebug from showing this? Is it because im calling eval a couple times throughout the script?
View 3 Replies View RelatedI have a number of javascript files. Some my own and some which I got off the net in my application. First, there's jquery and then a bunch of plugins and finally, my own scripts to bind all the correct elements and get the page ready.
For some strange reason, none of the scripts get loaded when I load the page. However, once I open firebug to try to see what's happening, it works fine.
Can you see an ajax call in Firebug when using $.getJSON? If so, does it return the jsonobject correct? Maybe there are some enters or something in front of the json?
View 4 Replies View RelatedIs this a bug or a feature? In this code:
Code:
for (var ur=longestRow; ur>1; ur-- ) // adjust rows above it
{ console.log("going to call spaceRowAbove("+ur+")");
spaceRowAbove(ur);
}
If Firebug is enabled the message is logged and the function is executed.If Firebug is NOT enabled, the function is not executed.If the log statement is commented out, the function IS executed.Wouldn't it be more reasonable for the interpreter to ignore just the console call, rather than the whole loop?Or is it just me and my Firefox 3.5.5?
I've come across a strange issue with the console.log function in WebKit.Here is the code I have that is causing the issue:
Code:
var myArray = ['Brian', 'Kayla', 'Mom', 'Dad'];
myArray.shift();
console.log(myArray);[code].....
I'm confused by firebug's output under the tab 'Net' > All:I post this in the JS section, as I'm sure many js coders use firebug and my question pertains to firebug.I have an image which appears several times on my site - the same image each time, just displayed in different places.For each time the image is displayed, I see a separate call to fetch it from the server, with info on 'Queuing, waiting for response, receiving data' etc, all with the number of milliseconds shown.It looks like it's being downloaded multiple times rather than only once.
View 2 Replies View RelatedI have this web browser which opens up a website that has a drop down list showing values that the user can select. And when I the firebug to inspect the elements in the page, what shows in the inspection window is this: [code]What I'm supposed to do is to get the values and update them automatically to the database. I'm actually using HtmlUnit to do this project, and I've heard how I can use getElementById() to get the values. But I don't know how to start.
View 2 Replies View RelatedI have some half-working script I'm playing with that I half-understand (this is the real problem) which I'm having troube debugging because it always does work when I refresh.So whenever I step through my functions with Firebug everything does what I expect it to do: but if then I re-invoke my onchange event, not every step is taken and it's hard to see why because I can't "see" what it's doing after the page has loaded and the script run at least once.This is for hide-and-show in a form and all the other versions I see online are even less understandable than what I've got so far. So I figure I'd better debug the one I have.Anyone know how to re-watch a script onevent?
View 4 Replies View Related[url]
The code:
When I go to the site using FF5 or Safari 5, everything pulls up great. When I try to open the page using FF3.6 or IE8 none of the classes show up, I then up Firebug or IE Developer toolbar and refresh and the xml appears without failing.
I've a technical problem, i use jQuery Form Plugin and it's working well except for upload file. Effectively after uploading file we can't see any response in firebug. (You can see an example in the official website of jquery form plugin [URL] And in the response i call a script with
<script src="script.js" type="text/javascript"></script>
My page get this file well but i have a javascript error on the "$" of
$(document).ready(function() {...