Rounding Off Numbers
Jul 20, 2005Is there a script that will round off a number to a certain number of
decimal places?
Is there a script that will round off a number to a certain number of
decimal places?
I have to round a fractional value from a form input to either 0, 25, 50 or 75. I have succesfully tested the value and stripped the decimal place. If the value is for example .1, I round it to 0. If the value is say .2, I round it to .25. My problem is that when the value is > .75, my function is returning undefined. For the sake of brevity I will include only the relevant code.
var increments = new Array(0,25,50,75);
CharBefore = parseFloat(CharBefore); //the whole number
CharAfter = parseFloat(CharAfter); //the decimal
var x = parseFloat(increments.length - 1) ;
for ( i = 0; i <= x ; i++ ) {
var testValue = parseFloat(increments[i]);
if (CharAfter > testValue) { continue ; }
else {
var lowerValue = parseFloat(increments[i-1]);
if ((CharAfter > testValue) && (i==x)) {
median = (testValue + 100)/2 ;
if (CharAfter >= median) {
CharAfter = Ɔ'
CharBefore++;} //round up to next whole number
else { CharAfter = testValue; }
}
else {
median = (testValue + lowerValue)/2 ;
if (CharAfter >= median) { CharAfter = testValue; }
else { CharAfter = lowerValue; }
}
return CharBefore + '.' + CharAfter;
break;
}
} // End for loop
i have some file size in bytes, and i want to get it in KB or MB, with
one decimal digit, for example:1268777 -> 1.2 MB
now i can have 1.210000... my question is how do you can round this number properly, if i use Math.round(number), i only get 1 MB
The inputs for the fields of mth6, mth12, mth18, mth24, set50, set75, set 80 and set85.
I would like a way for it to round up to the nearest tenth.
IE:
from 2571 to 2580
from 148 to 150
ect.
any suggestions? Code:
I have a problem in my code which is as follows:
Code:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
[code]....
My problem here is that I am calculating the percentage values of a whole number and storing those values in text boxes respectively through javascript function.Now,what I need is that I want to round all the values to integer value such that the sum of integer values is equal to the final value.
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Code JavaScript:
var left_margin = $(this).css('margin-left').replace(/D/g,'');
So the above, get the left margin of the object, strip all but numbers and store into a variable. Easy, right? Here's what happened. Inserted the object into the DOM, Chrome returned 212px, which was converted to 212�*fine. Firefox on the other hand returned 212.5px, which was converted to 2125� not fine. I'm centering the element on the screen based on this number, so the additional 2000ish pixels is WAY off. My solution was to increase one of my initial values a single pixel in which both browsers return 213px�*but like I said this is only a bandaid solution. Not really understanding the value of .5 pixel, but looking into that. Is there a rounding function in jquery? Javascript I would have to strip the px from the string, convert to integer and THEN round.
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Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
[code]....
My problem here is that I am calculating the percentage values of a whole number and storing those values in text boxes respectively through javascript function.Now,what I need is that I want to round all the values to integer value such that the sum of integer values is equal to the final value.
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[Code]...
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[Code].....
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p7Left = Number(document.form1.elements["p7_left"].value);
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...
...
scoreLeft = Number(document.form1.elements["left_score"].value);
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The following HTML sample works perfect in IE. On click of the
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<html>
<body>
<script>
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</script>
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<!DOCTYPE html PUBLIC "-W3CDTD XHTML 1.0 TransitionalEN" "http:www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http:www.w3.org/1999/xhtml">
<head>
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[Code]...
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