Put A Script Action To A Button Tag?
Apr 11, 2009How do I put a script action to a button tag? I tried the below, but it doesn't work:
<BUTTON TYPE="button">
<IMG SRC="up_left.jpg" onclick="alert($('#myselect').val())"/>
</BUTTON>
How do I put a script action to a button tag? I tried the below, but it doesn't work:
<BUTTON TYPE="button">
<IMG SRC="up_left.jpg" onclick="alert($('#myselect').val())"/>
</BUTTON>
I am making a form in which i am using two radio button.Now i want that if i click on first radio button and after that i will click on submit button then page should go different page .If i click on 2nd radio button and after that i submit page then page should go on different page.
View 2 Replies View RelatedI have window containing a field.I was looking for a way to copy the value in the field and at the same time close the window.To close window i cleaned the copying code and insert this : 'javascript:window.close();' it worked perfectly too.But i don't know how to put the 2 codes in one line so that on click the button will copy the field value and close the window
View 1 Replies View RelatedThis is probably something simple that I am not aware of, but when I use append to add a <div> containing a button the button does not work. I've tried to test the appended div with an alert but the results come back as null as if there is nothing there even though the new div is visible on the page. Looking at the page source there is no new div present. Does this have something to do with the appended div not being registered with the DOM?
var newCartItem = "<div class='cartItem'>" + $(this).attr('id') + "<input class='deleteCartItem' type='button' value='Remove' /></div>";
$('#shoppingCartContents').append(newCartItem);
$('input.deleteCartItem').click(function()
[code]....
I want my submit button to link to different pages, based on the value of a particular variable (let's call it total).
So, if 18 < total < 20, the submit button should redirect to page1.html
If 16 < total < 18, the submit button should redirect to page2.html
If 14 < total < 16, the submit button should redirect to page3.html
I have created page1.html, page2.html....page10.html. how should I link my submit button (I have only *one* submit button) to different pages based on different conditions?
I have 2 radio button first is a and second is b.
If a is selected then the form action should be a.php or b is selected then b.php.
Any idea how to do this. I don't want to this in server side script.
I have a form like this:
<form id="my_form" method="post" action="">
Name: <br />
<input type="text" id="name" name="name" />
<input type="submit" id="submit1" value="Go to page 1" />
<input type="submit" id="submit2" value="Go to page 2" />
</form>
how can I change my action form so the form goes to Page1.htm with click on button1 and goes to Page2.htm to click on button2, and mantein the value inserted in textbox "name"?
how i can trigger two action in one form when user click a single button
View 8 Replies View RelatedI dont know much about the functionality on what causes some popups to trigger a browsers blocker and some not to.
Situation: I have an account information page (where users can edit their account details) one of the fields the user can edit comes at a cost. For billing I am using a 3rd party billing portal (standard form action pointing to the service & value is passed via post variable)
-user hits submit (not on the 3rd party billing form, my fake ajax button)a service is selected that cost $1 (lets say)verification DB is updated (no page reload)value field is updated in the 3rd party billing form to reflect the additional service I then initiate the form submit on the 3rd party billing form into a popup window I do not want to user to leave the site, I want the $1 billing window to pop up, they take care of it then close the window returning back to the site. In order to get the form to popup in a window I set the forms target to the popup window:
Code:
window.open("", paysys, "width=760,height=550"); functionality everything is working perfect, except most browsers catch the popped up window in their popup blockers. Anyone know how I can create a popup that isnt flagged by the browsers?
when the following code is used in my JSP page:
$('#myForm').bind('submit', function() {
$('#submit').attr('disabled', 'disabled');
});
it disables the submit button when my form is submitted (IDs are used). This action displays a result page. If the browser's Back button is pressed to change some of entered items, the submit button in Firefox is still disabled, while the same action in MSIE8 enables it again. I don't know if this is exactly JavaScript/browser/chache issue, how to get the submit button enabled 'automatically' Unfortunately the refresh button in Firefox doesn't help either (probably JSP issue) - I have to press Enter on the address bar which is not very obvious for every user.
Can JQuery toggle be use to switch divs on page load instead of having to click a button to start the action? What would I have to write in the header to make this happen if this is possible?
View 2 Replies View RelatedIs that possible when you click a child that the function on the parent don't run.
In these example, if I click on 'h2 > a
', both elements triggers functions ('h2' & 'a')
What I wan't is that if I click on 'h2 > a
[code]....
I need to know how stop a action hover and just the last action happen
View 2 Replies View RelatedI have come across a very interesting problem that seems to be impossible to solve. Basically a web application that I am working on relies on a JavaScript function called go to change the input named view to the page name and submit the form. This form's type is post, so no values are included in the actual URL string. There is also another input called action and it's value is view. This is to tell the application that the user would like to view a page. The problem is because of the variables being of method post, page refreshes and back and forwards return errors because the post variables view and action aren't sent with the required data. To somewhat solve this problem I have created a feature that tells the application that if the post value page is empty then to try and get a GET var called page. To insert this var into the go javascript function I simple add this code
document.go.action = document.go.action+"&page="+page;
This line basically adds &page=[page] to the action of the form. The problem is, this code doesn't work because action is also the name of a form element. Referencing document.go.action refers to the input element named action and not to the form's action. Changing the named of the action input value is out of the question (Way to much changing of code, and possible room for error). What can I do to change the action of the form without referencing the input named action. Here is my go form and the JavaScript code:
<form name="go" action"index.php?sid=123" method="post">
<input type="hidden" name="action" value="view" />
<input type="hidden" name="view" value="" />
</form>
[Code]....
how to assign multiple action with multiple submit button in the form.
View 2 Replies View RelatedI have a very weired problem (which is not easy to describe.. but I'll do my best):I have a html page with several forms , only one of the got the action="ComputeAndReturn" and the other forms got only name="" tag.the problem is that after i submit the form with the action , and than after a computatioon it returns to the original page, now... if i will submit any of the forms without the action=.they will act as if they were defined action="ComputeAndReturn" (altho they are not!)if they were defined from the first time with action="anything", and than i would submit the form with action="ComputeAndReturn" this problem would not appear (the other forms will keep their action="anything" and would not "imitate" the action= "Compute AndReturn" to them selfs...
any ideas how can i keep my forms without action="" , cause all i need them to do is be submitted to pass the submitted value to other form inside that page.[code]
I have an onunload event in the body tag. When it is activated I want to
know if a <a></a> href was clicked and which one. Is there some document
property or any other object available for such a thing?
I have a form which needs posting the php script below. (I sent my vars to a
cookie, which I have read correctly). This is the form command used in
hoping to process my information.
<form method="POST" action="scripts/WebContractor.php" name="bizinfo"
id="bizinfo">
Since most of this is new to me, please let me ramble in my thought process.
1. post the vars to a cookie
2. post the form pointing to the php script
3. read the vars in the php script
4. send the info from within the script
When I submit my form, I receive a dialog box stating the downloading this
file can be dangerous. What happens is the php script is downloaded to my
desktop - not executed. Code:
I have created a form for file upload based on cgi script. In form action attribute, i have called cgi script.
<form name="content" id="content" action="../cgi-bin/upload.cgi?upload_id=" method="POST" enctype="multipart/form-data" onsubmit="setValueforHidden(this)" target="xupload">
when the user presses the submit button(after form valdiation was over ) i have called the below api.
function StartUpload(f1)
{
var UID= Math.round ( 10000 * Math.random () ) + '0' + Math.round ( 10000 * Math.random() );
[Code]...
How can I verify if the action after my $.ajax call is done and if not perform until done?Sometimes it performs the action sometimes it doesn't, it loops the request in this case the action:
$('#osa_stocka_'+completo_count+'_'+d).html(rt);
Rest of the code.
var data='id='+$('#osa_stocka_'+completo_count+'_'+d).attr("title");
var dataString = 'status=checkopapstock&'+ data;
$.ajax({
[code]....
I am creating a navigation system for my site, all menues are hidden only their headings are appear on the site. When a visitor click on a heading its shows the navigation links. Its working smoothly.
The problem is when user open a navagation menu and click on a link to browse the next page/link, after loading the next page the menu got close and visitor need to reopen the desired menu. I want that the desired menu stay open while browsing the site and only closed when a visitor wants to close it. Code:
How do I set the ACTION variable of a form in javascript, i.e. I have some radios. If a user chooses radio one, the action is set to a script (script1.php), if he chooses radio two, action is set to another script (script2.php) and so on.
View 9 Replies View RelatedThe goal for this page is to have different news feeds load in different tabs. When MSNBC is clicked, I want the RSS feed to load. Right now, you have to click the MSNBC tab and then click "Hello" right below it.
I have applied the same onClick to the "MSNBC" tab as in the "Hello" link but the onClick doesn't work.
Is this a javascript issue or a CSS issue? Do I have to have the link within the same p?
Any workarounds or is there something I'm doing wrong?
I have a form with a name, and action, a post method.
In rare occasion I want the form action to be different to the default
action, so I do this: document.formName.action = "newURL";
This works fine under Mozilla, but does not work under IE5, 5.5 or 6,
it says: Object doesn't support this property or method.
Does anyone know what could be wrong?
I know how to invoke a URL with jQuery. How to do the reverse? Can a URL will lead to execute the following jQuery code just as the signin division is clicked?
View 1 Replies View RelatedWhen I run the following code, none of the set's are being done. Most important one for me is the action attribute.
<script type="text/javascript" language="JavaScript">
$().ready(function() {
var url = $("#aggurl").val();
alert(url);
[Code]....