How do I set the ACTION variable of a form in javascript, i.e. I have some radios. If a user chooses radio one, the action is set to a script (script1.php), if he chooses radio two, action is set to another script (script2.php) and so on.
View 9 Repliesmy spring mvc controller dumps a map variable to the jsp page.MyController.java
Map map=new HashMap();
map.put("optionMap",optionMap;//
value of variable optionMap is like//key=optionGroup1, value="<option value="abc">abc</option><option value="def">def</option>"
there is a single selector in the jsp page. which has two options "optionGroup1", and "optionGroup2" respectively.when user click optionGroup1, value of ptionMap.optiongGroup1 will be inserted in a multiple selector
jsp:
<select id="single">
<option value="optionGroup1">optionGroup1</option>
<option value="optionGroup2">optionGroup2</option>
</select>
[Code].....
Is that possible when you click a child that the function on the parent don't run.
In these example, if I click on 'h2 > a
', both elements triggers functions ('h2' & 'a')
What I wan't is that if I click on 'h2 > a
[code]....
I need to know how stop a action hover and just the last action happen
View 2 Replies View RelatedI have come across a very interesting problem that seems to be impossible to solve. Basically a web application that I am working on relies on a JavaScript function called go to change the input named view to the page name and submit the form. This form's type is post, so no values are included in the actual URL string. There is also another input called action and it's value is view. This is to tell the application that the user would like to view a page. The problem is because of the variables being of method post, page refreshes and back and forwards return errors because the post variables view and action aren't sent with the required data. To somewhat solve this problem I have created a feature that tells the application that if the post value page is empty then to try and get a GET var called page. To insert this var into the go javascript function I simple add this code
document.go.action = document.go.action+"&page="+page;
This line basically adds &page=[page] to the action of the form. The problem is, this code doesn't work because action is also the name of a form element. Referencing document.go.action refers to the input element named action and not to the form's action. Changing the named of the action input value is out of the question (Way to much changing of code, and possible room for error). What can I do to change the action of the form without referencing the input named action. Here is my go form and the JavaScript code:
<form name="go" action"index.php?sid=123" method="post">
<input type="hidden" name="action" value="view" />
<input type="hidden" name="view" value="" />
</form>
[Code]....
I have a very weired problem (which is not easy to describe.. but I'll do my best):I have a html page with several forms , only one of the got the action="ComputeAndReturn" and the other forms got only name="" tag.the problem is that after i submit the form with the action , and than after a computatioon it returns to the original page, now... if i will submit any of the forms without the action=.they will act as if they were defined action="ComputeAndReturn" (altho they are not!)if they were defined from the first time with action="anything", and than i would submit the form with action="ComputeAndReturn" this problem would not appear (the other forms will keep their action="anything" and would not "imitate" the action= "Compute AndReturn" to them selfs...
any ideas how can i keep my forms without action="" , cause all i need them to do is be submitted to pass the submitted value to other form inside that page.[code]
I have an onunload event in the body tag. When it is activated I want to
know if a <a></a> href was clicked and which one. Is there some document
property or any other object available for such a thing?
I have a form which needs posting the php script below. (I sent my vars to a
cookie, which I have read correctly). This is the form command used in
hoping to process my information.
<form method="POST" action="scripts/WebContractor.php" name="bizinfo"
id="bizinfo">
Since most of this is new to me, please let me ramble in my thought process.
1. post the vars to a cookie
2. post the form pointing to the php script
3. read the vars in the php script
4. send the info from within the script
When I submit my form, I receive a dialog box stating the downloading this
file can be dangerous. What happens is the php script is downloaded to my
desktop - not executed. Code:
I have created a form for file upload based on cgi script. In form action attribute, i have called cgi script.
<form name="content" id="content" action="../cgi-bin/upload.cgi?upload_id=" method="POST" enctype="multipart/form-data" onsubmit="setValueforHidden(this)" target="xupload">
when the user presses the submit button(after form valdiation was over ) i have called the below api.
function StartUpload(f1)
{
var UID= Math.round ( 10000 * Math.random () ) + '0' + Math.round ( 10000 * Math.random() );
[Code]...
How can I verify if the action after my $.ajax call is done and if not perform until done?Sometimes it performs the action sometimes it doesn't, it loops the request in this case the action:
$('#osa_stocka_'+completo_count+'_'+d).html(rt);
Rest of the code.
var data='id='+$('#osa_stocka_'+completo_count+'_'+d).attr("title");
var dataString = 'status=checkopapstock&'+ data;
$.ajax({
[code]....
I am creating a navigation system for my site, all menues are hidden only their headings are appear on the site. When a visitor click on a heading its shows the navigation links. Its working smoothly.
The problem is when user open a navagation menu and click on a link to browse the next page/link, after loading the next page the menu got close and visitor need to reopen the desired menu. I want that the desired menu stay open while browsing the site and only closed when a visitor wants to close it. Code:
The goal for this page is to have different news feeds load in different tabs. When MSNBC is clicked, I want the RSS feed to load. Right now, you have to click the MSNBC tab and then click "Hello" right below it.
I have applied the same onClick to the "MSNBC" tab as in the "Hello" link but the onClick doesn't work.
Is this a javascript issue or a CSS issue? Do I have to have the link within the same p?
Any workarounds or is there something I'm doing wrong?
I have a form with a name, and action, a post method.
In rare occasion I want the form action to be different to the default
action, so I do this: document.formName.action = "newURL";
This works fine under Mozilla, but does not work under IE5, 5.5 or 6,
it says: Object doesn't support this property or method.
Does anyone know what could be wrong?
I know how to invoke a URL with jQuery. How to do the reverse? Can a URL will lead to execute the following jQuery code just as the signin division is clicked?
View 1 Replies View RelatedWhen I run the following code, none of the set's are being done. Most important one for me is the action attribute.
<script type="text/javascript" language="JavaScript">
$().ready(function() {
var url = $("#aggurl").val();
alert(url);
[Code]....
How do I put a script action to a button tag? I tried the below, but it doesn't work:
<BUTTON TYPE="button">
<IMG SRC="up_left.jpg" onclick="alert($('#myselect').val())"/>
</BUTTON>
I have a form with two <button> elements. One button loads the page with the associated form data whilst the other triggers a download. IE6/7 does not handle <button> tags correctly. IE6 will submit all buttons regardless of which you click and uses the button content as the value, instead of the value as the value. IE7 submits just the clicked button, but still submits the content as the value, not the value.
To get around IE's issues with <button> I use JS to manipulate the DOM so hidden input fields are generated with the correct value and the button names are removed so they're not submitted at all.
This works, except in my specific situation for my download button. Because it triggers a download, the page you are on remains, and remains with the manipulated DOM, which means the form doesn't work properly anymore.
I would like to know if there's a trigger of some sort that would allow me to revert the DOM changes when the form is submitted but the page remains. I hope that makes sense. Oh, and there's no need to suggest using <input type="button" /> instead of <button>. That's not a solution.
i have a css/div box, and i have a login form. what im tryn to do is make it so that when i login, it it takes whats in the action of the form and shows it in the div box. the div box is like one of those cool popup boxes, it's done by using javascript and css.
anyway, the div box works. the login form works. i just haven't been able to figure out how to get it to appear in the div instead of into a new page.
here's my code:
<head><link rel="stylesheet" type="text/css" href="main.css" />
<link rel="stylesheet" type="text/css" href="popup.css" /></head>
<form name="Login" method="post" action="login/check.php">
<table border="0" cellpadding="0" cellspacing="0">
[Code].....
I am trying to get a form value on an action page using JavaScript to alert the value.
The below doesnt alert anything after I hit the submit button in the one.html page:
one.html
<form action="two.html" method="get" id="myform">
<input type="text" name="city">
<input type="submit">
[Code].....
I am trying to update a site that has a cookie feature enabled so that a certificate can be retrieved later on.I am using a form to collect and put the cookie, but I have to use two buttons to get the information stored and then direct the user on through to the rest of the site.My question is:Can I combine these functions into the same button? I have scoured the web for solutions, but I can't seem to find anyone doing this exact thing. I know that websites do this type of thing all of the time.
View 1 Replies View RelatedI am trying to get my action page to work where if the user selects yes to Employee radio button then it goes to a certain page, if not it goes to another page. It doesnt do anything on submit and when I do an alert on alert(document.myFrm.employee.action) for test only form submit it gives me Undefined message.
Please advise what I am doing wrong?
function mySelection()
{
if(document.myFrm.employee.value == "yes")
{
document.myFrm.employee.action='gotoEmployee.cfm'
}
else
{
document.myFrm.employee.action='secondPage.cfm'
}
}
...
<form name="myFrm" method="post" onSubmit="return mySelection();">
<input name="employee" type="radio" value="yes">
<input name="employee" type="radio" value="no">
...
i need three things to happen on a form submit at a same time.
1. download
2. sent mail.
3. redirect to another page
with the code below i can able to download and sent mail at a same time:
<form name="a" action="test/test/mail?test" method="post">
<input type="hidden" name="from-email" value="a@a.com">
<input type="hidden" name="next-url" value="download.exe">
<input type="hidden" name="subject" value="test download">
<input type="submit" value="Download" name="testdownload" title="fmdffppjk" class="button">
</form>
can anyone tell me how do i also redirect to another page on clicking the submit button.
I am making a form in which i am using two radio button.Now i want that if i click on first radio button and after that i will click on submit button then page should go different page .If i click on 2nd radio button and after that i submit page then page should go on different page.
View 2 Replies View RelatedI want to change a form action url based on user input, and I used hyperlink to submit a form (since I have lots of rows like this and each has different values passed to javascript select_claim() function.). But it doesn't work! I have very simple php code here, but the it is the javascript problem.
HTML Code:
<form action="" method="post" name="smForm" id="smForm">
<table>
[code].....
I'm having a bit of problem writing some javascript that will dynamically update the 'action' of a form when the form is submitted.
Its for an Image Upload script which performs a binary read on the uploaded image, meaning I have to POST the form, but must pass any additional parameters to the Image Upload script via the querystring.
Code:
My submitform() function needs to set the action of form5 to :
Code:
And submit the form.
To confirm that a CMS user really wants to delete a record, I have added some Java Script that was originally intended to confirm if a user wants to visit a new web page that takes a long time to download. The script provided two location.replace() options: 1) to visit the new page or 2) to return to the previous page. I want to modify it so that the options are 1) to continue on to the following deletion script or 2) reurn to the previous page. How do I set up option 1) to do this in the following script? Probably something else than location.replace().
Right now I have option 1) set to direct the user to the same deletion page where this script resides. But this will just loop the user back thru the same JavaScript. Again, I want the first option to just allow the user to continue on thru the rest of the deletion script. Code: