[URL] that is the code in all its basic form (just stripped out other html). I am trying to modify the form actions of the 3 forms when i click on the tabs at the top of the page. but only the action of the delete form (id=form-horse-delete) gets modified. the other 2 forms do not change. i am not sure what the problem is. in IE8, if i have the jquery modifying the action of the 2 forms (add/delete), it gives a JS error. if i take out the add/delete in jquery, there is no JS error.
I have come across a very interesting problem that seems to be impossible to solve. Basically a web application that I am working on relies on a JavaScript function called go to change the input named view to the page name and submit the form. This form's type is post, so no values are included in the actual URL string. There is also another input called action and it's value is view. This is to tell the application that the user would like to view a page. The problem is because of the variables being of method post, page refreshes and back and forwards return errors because the post variables view and action aren't sent with the required data. To somewhat solve this problem I have created a feature that tells the application that if the post value page is empty then to try and get a GET var called page. To insert this var into the go javascript function I simple add this code
This line basically adds &page=[page] to the action of the form. The problem is, this code doesn't work because action is also the name of a form element. Referencing document.go.action refers to the input element named action and not to the form's action. Changing the named of the action input value is out of the question (Way to much changing of code, and possible room for error). What can I do to change the action of the form without referencing the input named action. Here is my go form and the JavaScript code:
I have a very weired problem (which is not easy to describe.. but I'll do my best):I have a html page with several forms , only one of the got the action="ComputeAndReturn" and the other forms got only name="" tag.the problem is that after i submit the form with the action , and than after a computatioon it returns to the original page, now... if i will submit any of the forms without the action=.they will act as if they were defined action="ComputeAndReturn" (altho they are not!)if they were defined from the first time with action="anything", and than i would submit the form with action="ComputeAndReturn" this problem would not appear (the other forms will keep their action="anything" and would not "imitate" the action= "Compute AndReturn" to them selfs...
any ideas how can i keep my forms without action="" , cause all i need them to do is be submitted to pass the submitted value to other form inside that page.[code]
I am trying to update a site that has a cookie feature enabled so that a certificate can be retrieved later on.I am using a form to collect and put the cookie, but I have to use two buttons to get the information stored and then direct the user on through to the rest of the site.My question is:Can I combine these functions into the same button? I have scoured the web for solutions, but I can't seem to find anyone doing this exact thing. I know that websites do this type of thing all of the time.
I have window containing a field.I was looking for a way to copy the value in the field and at the same time close the window.To close window i cleaned the copying code and insert this : 'javascript:window.close();' it worked perfectly too.But i don't know how to put the 2 codes in one line so that on click the button will copy the field value and close the window
I'm using quick search plugin (URL...) in filtering rows in a group of tables.The problem is that the old vesion of Quick search may act on multiple tables as long they have the same table_id while the new vesion acts on the first table only.
1-the number of tables is very large (in some pages may be 500 tables).
2-the action of Quick search is applied automaticaly as the user type any text in the input text box. so i don't know any way to make a loop to call the function once for each table.
I have an web application (PHP backend) where I want to initiate multiple requests to the same server (to different php functions/files) and asynchronously update the response on the page (the call back function is same for all the requests).
What is the best solution for this ? Is it better to
a) call multiple server calls from the java script file? if so Do we create multiple http objects ? can someone point me to the few examples ?
b) call one Php service and have the php fork the multiple requests on the server side. I am not sure if this can be done multiple requests be done asynchronously on the server side ? and if so how to dynamically update teh resultant page as each request finishes?
I dont know much about the functionality on what causes some popups to trigger a browsers blocker and some not to.
Situation: I have an account information page (where users can edit their account details) one of the fields the user can edit comes at a cost. For billing I am using a 3rd party billing portal (standard form action pointing to the service & value is passed via post variable)
-user hits submit (not on the 3rd party billing form, my fake ajax button)a service is selected that cost $1 (lets say)verification DB is updated (no page reload)value field is updated in the 3rd party billing form to reflect the additional service I then initiate the form submit on the 3rd party billing form into a popup window I do not want to user to leave the site, I want the $1 billing window to pop up, they take care of it then close the window returning back to the site. In order to get the form to popup in a window I set the forms target to the popup window:
Code: window.open("", paysys, "width=760,height=550"); functionality everything is working perfect, except most browsers catch the popped up window in their popup blockers. Anyone know how I can create a popup that isnt flagged by the browsers?
I have a form which needs posting the php script below. (I sent my vars to a cookie, which I have read correctly). This is the form command used in hoping to process my information.
Since most of this is new to me, please let me ramble in my thought process.
1. post the vars to a cookie 2. post the form pointing to the php script 3. read the vars in the php script 4. send the info from within the script
When I submit my form, I receive a dialog box stating the downloading this file can be dangerous. What happens is the php script is downloaded to my desktop - not executed. Code:
I have a form with two <button> elements. One button loads the page with the associated form data whilst the other triggers a download. IE6/7 does not handle <button> tags correctly. IE6 will submit all buttons regardless of which you click and uses the button content as the value, instead of the value as the value. IE7 submits just the clicked button, but still submits the content as the value, not the value.
To get around IE's issues with <button> I use JS to manipulate the DOM so hidden input fields are generated with the correct value and the button names are removed so they're not submitted at all.
This works, except in my specific situation for my download button. Because it triggers a download, the page you are on remains, and remains with the manipulated DOM, which means the form doesn't work properly anymore.
I would like to know if there's a trigger of some sort that would allow me to revert the DOM changes when the form is submitted but the page remains. I hope that makes sense. Oh, and there's no need to suggest using <input type="button" /> instead of <button>. That's not a solution.
i have a css/div box, and i have a login form. what im tryn to do is make it so that when i login, it it takes whats in the action of the form and shows it in the div box. the div box is like one of those cool popup boxes, it's done by using javascript and css.
anyway, the div box works. the login form works. i just haven't been able to figure out how to get it to appear in the div instead of into a new page.
I want to change a form action url based on user input, and I used hyperlink to submit a form (since I have lots of rows like this and each has different values passed to javascript select_claim() function.). But it doesn't work! I have very simple php code here, but the it is the javascript problem.
HTML Code: <form action="" method="post" name="smForm" id="smForm"> <table>
I'm having a bit of problem writing some javascript that will dynamically update the 'action' of a form when the form is submitted.
Its for an Image Upload script which performs a binary read on the uploaded image, meaning I have to POST the form, but must pass any additional parameters to the Image Upload script via the querystring.
Code:
My submitform() function needs to set the action of form5 to :
I want to change attribute action in form. Problem is that in that form is also input with name action. Unfortunately renaming of that input is worst case because many servlets depend on it.
This works in konqueror but not in IE and Mozilla:
After clicking the link and reading the advertisement, I go on "logging in" on the first window. After I submit, the form data, username, password and all is submitted to a third party..
I have form/select which executes a function using onchange. No problem. However, when I validate the page with a strict HTML 4.01 doctype at http://validator.w3.org, it demands either an action or a method for the form?.
If I give it an empty action <form action="" ..... it validates OK. Is this acceptable or is there a better/standards correct way?
How does one make a DIV visible if a form action is taken, such as a Radio button selected?
But here is the thing: this DIV that is to become visible and invisible upon radio clicked does not contain a simple short Text message, but instead this DIV contains many Images for selection. I mean I know how to turn on/off a DIV via Javascript command:
Code JavaScript:
But again this DIV is to contain many images and the inputs for selecting one of these images so that Javascript command will just not cut it.
alright I'm writing form which calls out a function F1 onsubmit but I want it to do that based on what the user answers to the last question on the form
this question has a yes/no answer, if the answer is yes, I want it to call F1 as it would and the function basically sends the form contents to two different places, if the answer was no, I want it to just submit it to one place.. Code:
I want to make a form run a php file, but only when I select an item from the listbox. I can't seem to find the info online but I thought u guys might know, below is what I have that doesn't do anything on selecting an item from the listbox Code:<select name="prodcategory" onchange="javascript: form.action='reportmanual_getcategoryproducts.php';">
