JQuery :: Why Can't Get A Background Image To Remain On Div During Mouseout

Apr 24, 2009

This should be the easiest thing in the world - set a background image for a div on mouseover. I'm working on a color picker for a clothing store. The customer can choose any of 20 colors. The colors are represented on screen by 20 tiny divs, each with a background color. When the customer wants to see a particular color variation, for the clothing, they mouse over the div with that color. A background image is then set that highlights that div, showing it is choosen. This background image should remain till another color div is mouseover-ed. The image appears on hover, then disappears on mouseout. I can not figure out why it disappears on mouseout. I've tried several variations of the following jQuery code, but the back ground image still disappears on mouseout. I also removed the background image from the hover rule in the style sheet - it made no difference.

// 04-24-09 - the little color divs have this styling:
//
// div.color-row div:hover{
// background: url(../img/bg-color.gif) no-repeat;

[Code].....

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Dynamically Enlarge Image On Mouseover And Mouseout?

Aug 26, 2007

I need help with a java script that increases image size and decreases on mouseover and mouseout for multiple images per page. In an html page.

This script that I have tried to modify is for one image.

Here is the html page code:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-us">
<head>

[Code]....

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May 12, 2010

I have a div set up like this

<div id='y' style='background-image: url(./randomcolor.php?ibase=
<?
php echo $entity
->

[code]....

I am having an issue with setting the background-image of a another div #x to the background image of #y.Correct me if I am wrong but I think you would do this in a simple case by saying

$
(
'#x'
).

[code]....

So when it does it, it is getting the URL of the generator (I logged it. what is actually being passed is [URL] This would require a server call to generate a new image, In this particular application, even if it wasn't exactly the image y had it would be acceptable. But it's not doing it. It is not getting any image at all. Am I doing something wrong, i.e. is it supposed to just work? I would think not, since the page has already been rendered. This is almost an ajax situation but I don't know how to do it for an image. I don't really want to generate a new image anyway, I'd be very happy to get the one that's already there. How would I access the actual image already attached to y and not do another server call?

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I've been given the task of mantaining and fixing a website which I
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I'm using Internet Explorer 5.5 and 6.x. Specifically, the problem is that navigation menues (written in javascript) don't disappear when the mouse moves outside of the area of the menues (some of the menues are nested two and three levels). As long as the mouse cursor remains *within* the options of the menues, the option under the mouse cursor is highlighted and the corresponding
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good.

As I said before, the problem arises when the mouse pointer moves *out*
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+ sub-sub-menu (if available) remain visible treading any underlying
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As far as I could find out, the original programmer used some
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2. add two text
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[Code]....

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Code:

Here is how i thought the bottom would work

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[Code].....

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[Code]...

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Code:
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<head>[code].....

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P.S. this code works other than that so you can throw it in a notepad doc to see the page in action.

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[Code]...

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