I am trying to recreate this functionality on my website where you can drag a background image around and when you get ot the edges of the image it bounces back to the edge of that corrosponding side. have a look at the site in question - [url]
So far i have recreated the top left and right edges using
Code:
Here is how i thought the bottom would work
Code:
I have a gallery that has back/next links below the main image, but I want them to be on each side of the image instead.
My current code looks like this:
Code:
<center>
<br class='clearit' />
<div id="main_image_wrapper">
[Code]...
I'm just not sure how to best do this. And I want the links centered to the height of the image.
Am just starting a new site and this morning noticed my header background image (logo) was missing.
Started out with normal CSS/HTML navigation menu.
www.westernwebdesign.com.au/pelican/index.html
Then I added a Vista buttons navigation menu:
http://www.westernwebdesign.com.au/p...cal/index.html
and the logo was gone. Not exactly sure at what point it disappeared yesterday as I didn't notice it missing until this morning. The navigation is about the only point of difference so I think this is the issue but have no idea why.
$('.collapse').click(
function(){
/*THIS*/ $('#loadingSymbol').css('background-image','url("ajax-loader.gif")');
triggerReset();
$('.identRow').each(
[Code]...
But /*THIS*/ and /*THAT*/ never happen. Is there a way of doing a callback, so that when the background image has changed, do the below functions. Then end with changing it to nothing again?
I am trying to modify some script that uses bounces the background hover - i would like for it to fade in and out rather than bounce.. here is the original script.
Code:
And here is the script that I somewhat modified but it did not work
Code:
I have an ajax call that sends some data to process.php and return back the image name. In process.php I returned the name as follows:
echo "image.png";
The ajax call is:
var $chart = $( '#chart' );
var $test = $( '#test' );
[Code]....
so from test div i get the path printed right: (./images/image.png), but I don't get the image to be desplayed
I am building a simple t-shirt creator app for my shop and I am using the interface.js library: [URL].. docs/drag to drag/drop and re-size the graphic on the shirt background image.
Once the user has chosen a spot to put the graphic, how do I save the background image of the t-shirt with the image they dropped in the correct spot? Like, to merge the two graphics in place?
I want to create Google Custom Search TextBox that has background image and image disappears on onmouseclick and appears back on onmouseout.
View 1 Replies View RelatedI have a div set up like this
<div id='y' style='background-image: url(./randomcolor.php?ibase=
<?
php echo $entity
->
[code]....
I am having an issue with setting the background-image of a another div #x to the background image of #y.Correct me if I am wrong but I think you would do this in a simple case by saying
$
(
'#x'
).
[code]....
So when it does it, it is getting the URL of the generator (I logged it. what is actually being passed is [URL] This would require a server call to generate a new image, In this particular application, even if it wasn't exactly the image y had it would be acceptable. But it's not doing it. It is not getting any image at all. Am I doing something wrong, i.e. is it supposed to just work? I would think not, since the page has already been rendered. This is almost an ajax situation but I don't know how to do it for an image. I don't really want to generate a new image anyway, I'd be very happy to get the one that's already there. How would I access the actual image already attached to y and not do another server call?
On sorting out a drag&drop script. I'm a bit of a rookie with programming, so I found this script somewhere and I managed to implement it in my code...unfortunately now I need to slightly modify the code.
I have this drag&drop script that moves some images around the screen, but I'd like to assign an event - document.getElementById("XXXXX").onclick = blablabla - to each of those images.
The problem is that, of course, every time I click on the image to drag it around, this activates the link. With a doubleclick event everything works smooth, however it's a solution I don't quite like.
I was thinking about a way to control the code so that while the image moves the link is somehow "not active", but if the user simply clicks without dragging then it activates the .onclick function
I have the following piece of code in the head section of my page, which is the actual code for dragging the elements
function Browser() {
i want to change the background image of a webpage every few seconds to a different image... i've written this code but it doesnt seem to work.
<script language="Javascript">
window.onload = backgroundchange();
function backgroundchange()[code]...
I have this working fine, and I can append the preloaded image to a hidden div then fade the div in for a smooth effect.
Problem is I want to set this preloaded image as a css background image, not as a <img /> in a container. But if when the image is loaded, instead of .prepend() I do .css() and set the css property of a background-image to be the preloaded images URL, then when it carries on with displaying it the browser loads the image again. Rather than using the preloaded one.
I want the image to be a background image as I want it centered in the page background, even if it is too large for the viewport.
I have a LARGE, hi-resolution image that I am trying to use as the background for a page. Because it is so large, it takes a while to download. Because of this, I wanted to load the image behind-the-scenes and show it once it is downloaded.
To accomplish this, I'm using the following JQuery code:
This code clearly downloads an image and appends it to my DIV element. However, I really want to set this downloaded image to the background-image CSS property of my DIV. The reason why is because I have content inside the DIV that should serve as the foreground.
How do I dynamically download an image, fade it in, and use it as a background?
I need to get the image name that is the end of the background-image example [code]i just need the name and file extension, example:[code]
View 7 Replies View RelatedManaged to get stuck over something that should be very simple.
I'm wanting to write the src attribute of an img tag on the client-side.
Doctype is XHTML 1.0 Transitional
In the head, I'm loading a js function that generates the src path. I want to call it and have it re-write the src in an img element with a specific id.
I'm trying to write a function to determine whether or not an image exists.
Most people recommend setting the onload event handler. That works like a
charm except that side-effective actions seem to be impossible. I can, as
nearly as I can tell, run alert and opera.postError (I test on IE, firefox,
and opera by the way). I've tried using the 'this' while in the event
handler, setting this.name, test.name, window.document.getElementById(test's
id).name. I just can't seem to find any means of using side effects inside
the event handler.
Below are several examples of things I've tried so far:
I'd like to see and use a javascript to resize an image.
I've creating a site and I'd like that only this image will be resizable automatically based on resolutions (800x600, 1024x768, 1280x1024, ecc...)...
I'm trying to flip an image horizontally on the client side. Is it possible to rotate or change the orientation of an image by using JavaScript or CSS2?
View 3 Replies View RelatedI have been using the JQuery Cycle plugin on my website and love it! It has so many options and seems customizable to do basically anything. My question is about the previous and next buttons. At the moment I am using next:'#next2, .pics img', prev:'#prev2', to make previous and next arrows underneath the image as well as use the image itself a "next" button. I would like to remove the arrows underneath the image and just use left and right halves of the image as a previous and next button. Previous being the left half and next being the right half of course. I've been searching for this being posted before and have not found any discussions on it. Also, the JQuery Slideviewer does what I'm trying to accomplish: JQuery Slideviewer Demo
if(zeroLeft >= pictWidth/2) { var uiprev = ui.parent().prev().find("a"); (jQuery(uiprev).length != 0)? uiprev.trigger("click") : ui.parent().parent().find("a:last").trigger("click"); } else { var uinext = ui.parent().next().find("a"); (jQuery(uinext).length != 0)? uinext.trigger("click") : ui.parent().parent().find("a:first").trigger("click"); }
Is there a way to incorporate this type of button in JQuery Cycle? It seems easy enough to make the image a next button I feel like dividing it between the two shouldn't be that much more difficult.
I'm busy creating a website and I've implemented a gallery of sorts using this script below to make it move the images, however when it gets to the end of the cycle of images it reads the last image as the last one to reach the left hand side which is obviously quite unattractive. So all I would like to know is if there is someone who can alter this code to make it so the last image is read on the right of the block thus resulting in no blank blocks. You can view it in action at http://mcphotography.co.za/corporate.html.
Code:
var Spry;
if (!Spry) Spry = {};
[code]....
I want to create the form button similar to this: [url]
I use an OnClick to switch the image but the if else statement just doent let me switch back to the original image, i not sure where i have gone wrong...
Below are the html and js thumnails:
[url]
[url]
I am trying to get the images on this page to revert back to the original photo after hover releases. I am assuming this is a simple fix, but I am no programmer and just did this in dreamweaver.[URL]
View 1 Replies View RelatedI would like to know what code I need to add to the Javascript below so that the images displayed will show a "<back and next button>" under each image, like on: http://www.msn.com Code:
View 4 Replies View RelatedI don't have much experience with JavaScript, but this is so simple I can't understand why it doesn't work. Basically, when the user clicks the image of a gray arrow it switched to a green arrow and vice verca.
<SCRIPT TYPE="text/javascript">
function swaparrows() {
var x=document.images
x[0].src="../images/green-arrow.jpg";
}
</SCRIPT>
<img src="../images/gray-arrow.jpg"
But that only works once of course, I want users to be able to switch back as well, so I changed the function to what I thought would work:
function swaparrows() {
var x=document.images
if (x[0].src=="../images/gray-arrow.jpg") {
x[0].src="../images/green-arrow.jpg";
}
if (x[0].src=="../images/green-arrow.jpg") {
x[0].src="../images/gray-arrow.jpg";
} }
but it doesn't. I am used to PHP, but as far as I know IF statement works the same way.
I have created a very simple gallery using javascript, which just has numbered links to different images.I wanted a gallery like ery simple I wasn't sure how to build the next and back buttons
View 13 Replies View Relatedprovide javascript to create something like the image below: Things I can't workout are:
1. top and bottom background colors as the above image
2. add two text
3. border color same as top background color
[Code]....