JQuery :: Post Entire JQGRID Data To Server?
Jul 22, 2010I have a JQGRID table and when I click submit I wanna post entire grid data to server.
View 2 RepliesI have a JQGRID table and when I click submit I wanna post entire grid data to server.
View 2 RepliesI have a few values and variables that I want to post to a server
(without using a SUBMIT button). Is there a way to post data from
within javascript - do sockets or connections have to be open for this
to work?
I am loading the array data into jqgrid ,but it is giving some errors . point out the mistake in the code.
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>jqGrid Demos</title>
<script src="js/jquery.jqGrid.js" type="text/javascript"></script>
[Code].....
i had created a test page for showing a grid for a task demo. I am supposed to fill it with dummy data for now.i have been using jqgrid for quite some time and many of the pages are working on some live projects also,but today i was unable to populate the data from an array.i have created a test script for you people to see, here also i am facing the same problem, i dont remember what all was required to fill it as it has been quite some months since i worked on jquery.this is the link for the test page
View 2 Replies View RelatedI wonder if i can make the variable data which is [data] in jQuery.post( url, [data], [callback], [type] ) dynamic. for instance, this is the form i want to send,
PHP Code:
<form action="send_xml.php" method="post" enctype="multipart/form-data" id="form_send"><input type="checkbox" id="var_1" class="checkbox"/><input type="checkbox" id="var_2" class="checkbox"/></form>Â
[Code]...
the follwing script works fine on xampp at home:
$(".SFV_I").live('click',function(event)
{
whereVal=$(this).attr("whereVal");
[code]....
I am writing a small data entry screen that will post the form data to a page and return a message. But i cannot get the Success or Error functions working properly.
Here's the code where strData is the posted querystring of:
I'm not sure whether it should be in a form and using the onsubmit or click of a button.
I have created an entry form that I display in a modal dialog. I have two buttons on the form: "Add and close", and "Add and allow me to add another". However the only time my modal form will post back to the server is after the form has been closed. I want to do the following: The user opens the form in a modal dialog. The user enters data, and clicks the "Add and allow me to add another" button. The page sends the user input to the server, which adds the input to a database and updates a datagrid on the page. This updated datagrid is visible behind the modal form, so the user can see it happening in the background The form clears all input fields and the user goes again. Any code I write that calls the server (button click events, ajax calls, etc) are ignored, unless the modal form has been closed.
View 1 Replies View RelatedTEST .js
// JavaScript Document
$.post('http://example.com/test.php?image_no='+no_image, function(data) {
$('#gallery').html(data);
[code]....
I want to populate my client's webpage (Remote Server) automatically
through my Server and Database by having him just paste a javascript
on his webpage.
I have read up about Microsoft Remote Scripting but the documentation
states the following : "The server which you make remote scripting
calls must be the same server from which you requested the client page
containing the requests."
In my case , the client and server pages are on two seperate servers
which means that I cannot use MS Remote Scripting.Is there an alternate
approach in any scripting language ???
Any suggestions, tutorials , websites , code snippets will be
appreciated while i continue to research on this...
I'm trying to read a file (will be a firmware update) into a byte array or binary stream or stream of some sort, and then POST it to my server. Any suggestions on opening and reading files from within js? Note, the server is a development server and will not run PHP or CGI scripts for example. I just need to be able to open a file from within a js function.
Also, no ActiveX objects, this needs to be Cross Platform.
I have the following piece of code:
$.ajax({
data: someData,
url: submissionUrl,
[code]....
where someData is a vanilla object of key/value pairs, submissionUrl is a valid URL and ajaxSuccess/ajaxError are both functions.Using jQuery 1.5.1, the GET request is delivered to the server without the data. Using jQuery 1.4.4, the request contains the data.Has something changed in the way I should be assigning data to an ajax request in 1.5.1? The docs don't seem to suggest I'm doing anything incorrectly.
I am trying integrate an upload system from YouSendIt.com in to my companies forms. The code they give for integration is basically an iframe with a coded URL set for the source. Their server sends a postback using HTTP Post method but I am not sure how to access the data that is sent back. I do not need to display it but I need to use it for validation purposes in the rest of my form. The Iframe code is as such:
<iframe style="margin-left:20px;background-color:#ffffff;overflow-x:hidden;display:block" id="file_upload_iframe" name="file_upload_iframe" src="https://www.yousendit.com/v1/ibox.php?sitebox=1011503&sh=adeace4e28613bc36fb1fa3c6ef766ee&send_notification=false&custom_postback=true" width="600" height="250" marginwidth="0" align="middle" frameborder="0" allowtransparency="true"></iframe>
[Code]...
I am trying to make an ajax POST request but its not working. Code below:
var _HOMEDIR = "http://localhost/personal/index.php/home/";
$(document).ready(function() {
$("form").submit(function() {
var str = $("form").serialize();
[Code]....
<div>Hi jQuery,</div>
<div> </div>
<div>I'm trying to learn the json and ajax</div>
[code]....
I'm a total JS/jQuery newbie, and I'm having a problem using jQuery's load() to POST data to a remote PHP script and rewrite a DIV with whatever the server sent back.
Using a proxy in between, I can see that the JS script isn't sending anything, so I guess there's something wrong in the JS code I send to the browser [code]...
i want to send data(inputdata) using jQuery to a php script, the displaying the returned data(returndata) in a div but what happened that the (inputdata) don't get send this is my code it will explain it self better:
HTMLfile.HTML
<HTML>
<head>
<script type="text/javascript" src="jquery.js"></script>
<SCRIPT language="JavaScript">
function swapContent(inputdata){
[Code]...
I have some radio buttons and do a jquery post on click. Something like this: $.post("method", { value: value }, function(data) { alert(data); }); the value data does have the correct result, but my problem is the page doesn't refresh to that data.
View 2 Replies View RelatedI found this formwizard script example online but I don't know how to use the data with php for emailing and saving to database for example.The script attaches the result to <p id="data"></p> like this
firstname=&surname=&day=DD&month=MM&year=YYYY&lastFour=XXXX&countryPrefix=+358&areaCode=&phoneNumber=&email=jasonhoefie@hotmail.com&username=&password=&retypePassword=
Attachments
jquery-formwizard.zip
Size : 48.6 KB
Download : 422
I am trying to build a table from backend data and then perform a filter on it using the picnet table filter. After much messing about I have discovered that the problem lies with the table data returned from the server. As a test, all I want to do is get jQuery to make an alert when a table cell is clicked. I added a hard coded table cell at the beginning of the table and when I clicked on it, the alert appeared. However, clicking on any other cell had no effect.
[Code]....
I am new to all this but making good progress and having fun in the process. I have written quite a bit over recent weeks (including a few $.post / $.ajax calls) for various sites/applications but this one is really puzzling me. Here is a snippet of code that is causing me problems.
[Code]....
The problem is that execution jumps from line 2 to line 6 ... ignoring the function(data) and I am not sure why. I get the correct value of "team" arriving at the perl script .... and the perl writes the correct json back. I just can't think where else I need to look to debug this - as I said, I have done something similar 5-6 times over the last few weeks - all without a problem. So I am sure I am doing something stupid here.
I want to POST data to my personal website[code]...
If i run the code from my localhost it doesn't return anything
The script below works, but only returns one headline/url from the html list.I am coming from a procedural background and know there must be a better way to pass all the urls and headlines (the link text) to my PHP script, which populates my database, but even after reading 'Jquery in Action' I am flummoxed.how to attack this problem? The .each portion of my script does not seem to work as I expect it to. I have also tried append, which would seem to be a solution ... really all I need is the "which" value from the url, so passing a simple array of those values to PHP would suffice.
<SCRIPT>
$("#latest-news button").click(function () {
$.each(function()[code]....
Do i need to encode my data send through AJAX post? Ex.
var name = $("input#name").val();
var dataString = 'name='+ name;
///////////////////////////////////////////////
$.ajax({
[Code]....
since jQuery 1.4 I've a problem using $( selector ) in data for $.post My code:
settings = $.extend( {
attachTo: $( '.top h1' )
}, settings );
$.post( url, settings, function( str )
[Code]....
it working also fine with jQuery 1.4.*. I can't find changes in the changelog for jQuery 1.4 that could explain this behavior.
$.post, it calls a php file which retrieves data from my database and should return a JSON datatype result. I checked on firebug, and it does successfully retrieve the data in JSON format. I however cannot get it to display on screen. I want to populate input fields with the result accordingly.
Here's a chunk of my javascript: (this function is being triggered by a dropdown)
function updateBillingAddFields(address_book_id) {
jQuery.post("ajax_checkout_confirmation.php", {
address_book_id: address_book_id,
action: 'get_shipping_add_details'
}, function(data){
var form_element = document.forms['address'];
form_element.elements['entry_name'].value = data.entry_name;
form_element.elements['entry_addr1'].value = data.entry_addr1;
form_element.elements['entry_addr2'].value = data.entry_addr2;
form_element.elements['entry_addr3'].value = data.entry_addr3;
form_element.elements['entry_addr4'].value = data.entry_addr4;
form_element.elements['entry_postcode'].value = data.entry_postcode;
form_element.elements['entry_state_name'].value = data.entry_state_name;
}, "json"); }
I tried putting alert inside my function, and it also doesn't show. I'm thinking it doesn't go inside the function at all.