JQuery :: Populate Textbox Based On Dropdown Selection Index Change
Jun 26, 2011based on dropdown selection i need to fill two text box in sharepoint 2007 using jquery.
View 1 Repliesbased on dropdown selection i need to fill two text box in sharepoint 2007 using jquery.
View 1 Repliespopulate textbox based on dropdown selection index change. populate two text box on the dropdown box value selected index change dynamically.
View 2 Replies View Relatedhow to populate checkboxes based on the dropdown menu selection
View 2 Replies View RelatedI have set up my website quite some time ago that has served its purpose very well, however I will now be adding an order form functionality. So far, by reading books and traversing forums, I have been able to develop a page where the user
1.Enters data into the required fields, that is then submitted to a MYSQL database via PHP,
2.Can retrieve orders that are stored in the database,
3.Delete orders that are stored in the database.
I have wamp installed on my computer as the webserver. I have also incorporated two drop down lists that both retrieve their values from tables within the database. The first drop down list retrieves the Australian States that I have stored in a table, and once the submit button is pressed, it stores the State that is selected to a separate table. This drop down list functions as it should. An extract from "From Place an order.php"
<?php
$dbcnx = @mysql_connect('localhost', 'root', 'tingling');
if (!$dbcnx) {
exit('<p>Unable to connect to the ' .
'database server at this time.</p>');
} .....
The second drop down list retrieves product names from a table that contains products and their prices. What I would like to happen, is that when the product is selected from this drop down list, a text box is automatically filled with its corresponding price. I had this drop down list working as per the "States" drop down list, but could not get it to auto populate the text field. I got some assistance from a friend and was able to get the text box to auto populate with its corresponding price, however when the page was submitted to the database, the "id" number of the product name from the drop down list was stored, and not the product name.
<select name="productSelection" onchange = "getProductDetails(this)">
<option selected value="1product">Select Product</option>
<?php
$products1 = @mysql_query('SELECT * FROM products');
if (!$products1) {
exit('<p>Unable to obtain author list from the database.</p>'); .....
how to populate a dropdown based on Another dropdown selection. This all should be a dynamic. Eg: I have two text boxes one is TechID and other is JOB ID. When I start typing Tech ID it suggests me the list of IDs which start with the input string i have put in Tech textbox. When i select the Tech ID the jobs associated to that Tech ID should be displayed in JOB ID text box as a dropdown list.
I have a dropdown box with 2 selections(True/False default False) .If false I want to show under it a form like so.
input text
input check
input text
Im using a jQuery script to show/hide a div based based on the selection made via a dropdown.
<script type="text/javascript" src="jquery-1.3.2.min.js"></script>
The problem im having is that the value used in the dropdown lists are price values eg 10.00
Consequently jQuery seems to interprit these as css notations, meaning the code doesnt work.
I want to populate the right text box with the result of the drop down multiplied by the left text box. I'm able to do this already but with only one set. I want to be able to have multiple rows.
Here is the code I currently am using for the single.
Code:
$(function() {
$('#DropDownList1').click(function() {
$("input#TextBox1").val(
(
[Code]....
how to get contents into a textarea based on a radio button selection.
Code:
<script>
text = new Array()
text[0] = Array('Saab','Volvo','BMW');
text[1] = 'second list';
[Code]....
I have a page which has a dropdown box.On selection a value is sent to a php script (Ajax), based on the value a html table is created and sent back to the responseText.The table is outputted to the html page, I want the table to have sortable columns, so I have used jquery datatables for this, but it is not working.I have cut and pasted the exact table into the html and ran the page, and then sorting works.
View 1 Replies View RelatedI've looked around and from what I can tell, the code seems right. Basically crating a JS array and passing PHP values to it to use in an onChange to fill a text field. The dropdown gets populated fine but the text field does not autopopulate onChange. I'm not too fluent with JS but have a good analytical mind and from what I can see, the logic seems right.
<?php
include('connectdb.php');
$CENTRE = $_SESSION['centreAFB'];
$qryFormList = mysql_query("SELECT * FROM tblLogin WHERE ACCT_TYPE = '2' AND loginCENTRE = '$CENTRE' ORDER BY loginNOM");
echo "<script type='text/javascript'> var formCourriel = new Array()";
while($resFormList = mysql_fetch_assoc($qryFormList))
[Code]....
How can i make a text box appear/dissapear on selection of a specific value from a dropdonw list?
Take a look at this page...
[URL]
If you look at the department dropdown, there is an "other" option which once selected i want a text box to appear..
Code:
<div id="1">
<asp:DropDownList ID="DD1" runat="server">
<asp:ListItem>option1</asp:ListItem>
<asp:ListItem>option2</asp:ListItem>
[Code]....
I want the div with the id of "option2show" to be hidden unless the user has selected option 2 in the dropdown box.
If the user has selected option 1 then nothing will happen, however iff option 2 has been selected then the option2 div will appeaar. I would like this to happen before any submit buttons are press, so i guess onblur of the dropdown box.
I have a long list consisting of a name and associated number, like this:
SITE01 2111
SITE02 4567
SITE03 5555
and so on.
I would like to put two dropdown boxes where the user can select either the name or the number. Then based upon the users selection have both the name and number appear. I'm thinking of putting all the data in an array and using the dropdowns to query the array.
I'm trying to populate a triple dropdown menu based on Roshans code The first dropdown populates the second one fine but when I clidk on the second it populates itself instead of the one below! I thought at first it was a simple problem with the element ID its not and I can't figure it out.
View 9 Replies View RelatedI'm trying to populate a form with information from a database based on a textbox entry. However, when I begin to key in the textbox I receive "undefined" in each textbox throughout the form.
Take a look at my code for any errors? It also appears that my $_GET['jobid'] is not working properly.
And here is my php:
I am working in ASP.NET 4.0 anduse IE8, Firefoxand Chrome for testing. Inside the web page I have a textbox and a drop down with 5 items. If the 4th item is chosen I want the textbox to become a datepicker.
Here is my best attempt thus far.
$(document).ready(
function () {
$(
"#txtSearch").focus(function () {
if ($("#ddlSearch").attr("selectedindex") == 4) {
$("#txtSearch").datepick("enable");
} else {
$("#txtSearch").datepick("disable") .....
i am building a website form which I would like the user to select a product of interest. Some products are three tiered and some are two tiered.
1. Example of three tier (3 dropdowns required only):Scooters (dropdown 1)Three Wheel Scooters (dropdown 2)
Delux 503S Bird Scooter (dropdown 3)
2. Example of two tier (2 dropdowns required only):Standing Bikes (dropdown 1)Children 300 Series (dropdown 2)
If the user wants to submit their interest for one of the products, I need to have at most 3 dropdown menus. So in Example 1, I would have 3 dropdowns in my form. Dropdown 1: Scooters Dropdown 2: Three Wheel Scooters Dropdown 3: Delux 503S Bird Scooter.In Example 2, I would only need to use the first 2 dropdown menus. (Obviously the first dropdown would contain 'Scooters' and 'Standing Bikes' in the menu list)I would like to alter the code so that the second and third dropdowns are hidden until a selection from the first drop down is made. Once for example, 'Standing Bikes' is selected from the first dropdown menu, the second dropdown menu appears and the third remains hidden due to the fact that it is not required. If I selected Scooters from the first dropdown menu, the second dropdown would appear listing all items associated with this and at this point the third dropdown menu is hidden. If i select 'Three Wheel Scooter' from the second dropdown the third dropdown menu now appears listing all Three wheel Scooters such as 'Delux 503S Bird Scooter'.
I have a page on which I have 2 dropdowns. Both are similar. I have a piece of code that whill make a textbox appear if we select "list Box" as the option in the drop down. But for some reason, the first dropdown works fine, but for the second dropdown, the textbox is always there on page load. The code that I am presenting can be copied as a HTML page and you will know what I am referring to.
<html>
<script type="text/javascript">
function showfield(name){
if(name=='lstbox')document.getElementById('div1').style.display="block";
else document.getElementById('div1').style.display="none";
}
function hidefield() {
[Code]...
I have a form which has a dropdown menu on it. The last option on the menu "other". When "other is clicked, I would like a textarea to become visible, so that the user can enter the new information. Does anyone know how I might do this?
Here is the html for the form:
HTML Code:
Union: <select name="union" id="union">
<option value="choose">Choose One</option>
<option value="ibew">International Brotherhood of Electrical Workers</option>
<option value="ibt">International Brotherhood of Teamsters</option>
[Code]....
On a registration form I have 4 fields that are all dropdown select fields. NAME, CLASS-1, CLASS-2, CODE
1) I would like to activate the CLASS-1, CLASS-2, CODE fields only if the NAME IS Selected from the dropdown.
2) Also would like to make the CLASS-1, CLASS-2 as required fields if the NAME is selected from the dropdown.
How can I achieve this? Can I use some kind of a server event to activate / deactivate the fields on the form?
I have a Javascript function that allows the display of a textbox upon selecting an option from a dropdown menu. In my case when a user selects listbox as the option, the text box appears. I want the same thing to happen when another option (checkbox) is selected. when I repeat the JAVAscript code, the first textbox(listbox's textbox) appears irrespective of which option(listbox, checkbox) I select. I want to be able to appear/disappear only the respective textbox. Here is my code.
<html>
<script type="text/javascript" >
function showfield(name){
if(name=='lstbox')document.getElementById('div1').style.display="block";
else document.getElementById('div1').style.display="none";
}
function hidefield() {
[Code]....
I have searched and found lots on enabling/disabling form inputs, but nothing that matches my needs.
I have a form with a dropdown with values 0-4. If value 0 is selected I want the checkboxes to be disabled. If value 1-4 is selected I want the checkboxes to be enabled.
Code:
<html>
<head><title>Disable with Dropdown Test</title>
<script>
function num_check(sel,cb) {
[Code]....
I have a simple form - I want to disable the text field if Choice 2 from the dropdown menu is selected. I have this working with the code below, but for some reason if I go back and select choice 1 after selecting choice 2 the text field remains disabled. I only want it to be disabled if choice 2 is selected.
View 5 Replies View RelatedI have been searching for hours and have not found what I am looking for. BUT, I have seen it before when I was NOT looking for it. haha!
Anyway, I am creating a form. And the form has an element that asks for "How Many Children?" followed by a dropdown from 1 to 6.
Well I would like to display another set of elements from 1 time to 6 times, based on their selection.
Name: ___ Age: ____ Sex:____
That will be displayed as many times as the user selects.
How can I hide/disable the submit button if the name Todd is selected?
View 7 Replies View Related