I've managed to open the login form in fancybox. When visitors login, the page opens in the i-frame itself. When they hit the close button of the fancy box, the parent page refreshes.Almost there but I would like to close the popup and refresh the parent page at one go with a proper function when a visitor hits the submit button
View 1 RepliesYou can see that when selecting 'Contact' from the top navigation a light-box (fancybox) with a contact form opens, this form can be filled and when the submit button is pressed the content of the form is emailed to myself. However.... The 'Thank you message' is not appearing in the light-box as I would like it to and I cannot work out how to do this.
View 2 Replies View RelatedI've been working on a freelance design site, and I have been using jshowoff and fancybox on my portfolio page. The portfolio has multiple sections that are set to be scrolled through using jshowoff by using the slide links. This use of jshowoff is working perfectly fine, but fancybox isn't. fancybox is supposed to be set to launch a modal when any of the portfolio thumbnail images are clicked. As it is right now, fancybox links will not work within the jshowoff slide div, but they do work outside of the jshowoff slide div.
I have done about 5 hours of searching online for possible fixed to my issue, and I haven't found anything. I am attempting to fix the conflict the between jshowoff and fancybox. I am very new to using jQuery plugins, so hopefully, you can all bear with me.If anyone may know how I can fix my fancybox links, so that fancybox will work within my jshowoff slide, I'd greatly appreciate it. I have provided the html below:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
[code]....
I have a form which open in a jQuery Fancybox Window. The fancybox window opens automatically when the page loads. When it loads, I would like it to set focus on the username field in the form in the Fancybox window. I have found that this must be done when fancybox is envoked, thus I have tried the below code which does not work :
<script type="text/javascript">
jQuery(document).ready(function() {
$("#hidden_link").trigger('click');
document.getElementById('login_form.username').focus();
});
</script>
The form name is "login_form" and the field name is "username".
When a user in somewhere of a site, he/she may want to login to access some user restrict pages. He/she clicks a login link on the menu and sign in on the login page. How to use JQuery to let the user back to the page where he/she clicks the login link?
View 3 Replies View RelatedI'd like to have one form that has username and password at the top and if that is all the user supplies, then try to log him in. Otherwise, validate all fields for registration.
The problem then lies in the remainder of the form which has email, name and password confirmation. I still want to run validate on those fields but ONLY if the user has typed at least one character in any one of them.
Is there a way to do this? Or an example somewhere? Can validate for certain fields only be turned on IF a certain other condition is met?
I have this ajax login plugin. If login ok, reload the document, else diaplay an error message above the login form. It works fine, execpt if hit keyboard enter button instead of click the submit button, it has no response. How to make the default keyboard enter button work?
[Code]...
I have a intern page with a form. User should enter their data and send the form. Some data from the user is stored in a database (name,phone). I want to make the form easier and complete the form with data from the database. The user should only enter his personal-number. How can i solve this with jquery? Is there any plugin?
View 2 Replies View RelatedIn Chrome, the login page on my schools educational online platform doesn't remember the login info. So i made a bookmark with this javascript injection, that fills in the info, and focusses on the 'aanmelden' button (='login' in dutch), so that i only have to press enter to continue. Here's the javascript injection:javascript: ocument.getElementById('username').value='23889493984';document.getElementById('password').value='4 42384985';return false;document.getElementById('login').focus();This works fine but i'd like to make it happen faster. I wish i could let the script be activated instantly when the page loads, so i only have to press enter, or if possible, let the script click the login button itself.
View 19 Replies View RelatedI want two buttons: one for login and another for logout. Initially login button is enabled and logout button is disabled. When I click on login button, the logout button should get enabled and the login button should get disabled. And after that, when i click on logout, the login button should get enabled and the logout button should get disable.
Here's how far I could go with it,but it doesn't work.
I have a a html page that is used as a login page.I know it is not secure but this is just for learning purposes, I'm not using it for anything important.My problem is that when I put in the correct login all that happens is the page just clears the text boxes as if you were starting over.I am trying to get it to go to register.html which is located in the same directory as the login page.
View 3 Replies View RelatedI am able to run perfectly the following
<li><a href="javascript:ajaxpage('login.php', 'ajax');">Login</a></li>
But not the following
echo "Welcome Guest!<br><a href=javascript:ajaxpage('login.php', 'ajax');>"
I removed the " around the javascript:ajaxpage('login.php'); as it was giving me syntax error. But I am unable to cal login .php upon clicking Login. I tried various combination of single quote and double quote but I think I am missing some fundamental rules of single and double quote combination....or may be something else.
I found his basic code online for a popup login but I don't know how to get the information from it either into php variables or whatever i need to do code...
I put the css on a separate page and just copied the login link and the javascripts. I don't know how to get the information into php variables so i can check it with the database.
I know I'm just asking for the answer but I don't know javascript and i don't want to spend a month learning it just for a login form. If your going to just say go learn javascript then don't post .
i have a login page and it is separately in my index.phpnow i need my login page become a pop up form when I open my index.phphere is my login.php
<?php
include 'config.php';
session_start();
[code]....
I am trying to automate a login to a website and am learning jscript on the fly
java script:
var webstart ={
var email = prompt('Enter your Email Address:', 'Email...');
var pwd = prompt('Enter your Password:', 'Password...');
login: function() {
[Code]...
I am just trying to have a login form on a page using div tags. After successful login without refreshing the page, the textboxes on the form should be replaced by Welcome message or displaying username and Logout button.
View 1 Replies View RelatedI am trying to fix error- object does not exist- I want it possible to
allow object not to exist.
I am writing a script on a page that may or may not include a login
form. For example-after a visitor logs in, the login form is no longer
on the page, but other content is still there.
I want to bring focus to the login form using the onLoad in the body
tag.....but if the login form does not exist, I do not want to perform
this function.
The following code works fine for focusing the cursor on to the login
form.
(code)
<html>
<head>
<title>
Testing Javascript
</title>
<script type="text/javascript">
<!--
function addcursor ()
{
if (document.login) {
document.login.username.focus();
}
}
//-->
</script>
</head>
<body OnLoad ="addcursor()">
<form name="login" id="login" action="" method="post">
<input type = "text" name="username" id="username" />
<input type="password" name="password" />
</form>
</body>
</html>
(end code)
But if you remove the form in the body section from the code, an error "object does not exist or is null" results.
I am having a particular problem with my Javascript page, which should change the form that the user is at. Need to proofread my code to check for errors? The code does not change the form (Also it does not run the PHP page, or at least does not display its output in the loginStatus div):
<html>
<head>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
<title>
PHP Hardcoded Login Script!
</title>
<script>
function processLogin(form) {
var user = form.user.value;
var pass = form.pass.value;
var url = "processLogin.php?user=" + user + "&pass=" + pass;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
} .....
Why this is not working? The page running this code can be found at: [URL]
Another page without the signup form (that works) is at:
[URL]
The login for the pages is:
user: john_doe
pass:password
I have a gallery on my site here:
[URL]
add a caption to the bottom of the images when they are clicked on and perhaps even a link?
My website [URL] works well in Firefox and Safari. But some of the JQuery function doesn't work in IE, e.g., Fancybox.
View 1 Replies View RelatedI use the fancybox plugin. I need the plugin with two setups (CSS and plugin itself changed a little) so I duplicated the script and made my changes to it. Now I want to use both script in the same page. Of course there is a conflict with function name, which is why I want to rename the function name of the one script to .fancybox2. But I can't seem to get it to work. I don't know which parts of the fancybox.js file I have to change. There are so many fn.fancybox's. I tried to change them all but it's not working. Any advise how this has to be done?
View 1 Replies View RelatedSo I have a script that retrieves images from Flickr and displays them on my site. I have Fancybox so that when a user clicks on the image, the picture will come up in a... "fancy box"... everything seems correct, but when I click on the image, it sends the user to the location of the picture on Flickr servers instead of opening it using Fancybox.
Here is the code for the Flickr retrieving...
<script type="text/javascript">
var FLICKR_ID = '41313008@N08';
var THUMBNAIL_HTML = '<a id="single" href="%IMAGE_URL%" title="%IMAGE_TITLE%"><img alt="%IMAGE_TITLE%" src="%THUMBNAIL_URL%" /></a>';
function displayImages(data){
var htmlString = "";
$.each(data.items, function(i,item){
var thumbnail = (item.media.m).replace("_m.jpg", "_s.jpg");
var large = (item.media.m).replace("_m.jpg", ".jpg");
htmlString += THUMBNAIL_HTML;
htmlString = htmlString.replace(/%IMAGE_TITLE%/g, item.title);
htmlString = htmlString.replace(/%IMAGE_URL%/g, large);
htmlString = htmlString.replace(/%THUMBNAIL_URL%/g, thumbnail);
});
$('#gallery').html(htmlString);
}
$.getJSON("[URL]", displayImages);
</script>
<a id="single" is the id that goes to open the image in Fancybox. When I disable this Flickr script, and input an image manually, it works 100%.
I'm using the most basic functionality of the Fancybox plugin. All renders fine in FF 3.5.9 & Chrome 4. Wouldn't you know it, IE 7 has a problem, it does not display the close box and doesn't honor the location of the title. You can see the problem here: [URL]
Click the Players tab and then click any thumbnail.
I have this simple gallery that loads images from an xml file and usesFancyboxto display the images. Demo Everything is working but the last image is not working with fancybox. The last image just displays in it's own window.
[Code]...
Somehow I can't get this to work on that page: [URL]...
View 2 Replies View RelatedI have the following problem: In wordpress I wanted to popup the login-page (wp-login.php) and i used the fancybox to generate an iframe. after clicking the "login" button i want that the fancybox is closing (thats not the problem) and i want to reload the whole page so that it recognizes that i'm logged in.
Now that is the problem .. I cant reload the index page when clicking the login button, because (i think so) the login document is in a iframe and is not able to reload the whole screen). I don't know the "reload" command, too, maybe load("index.php"); ? :D