I'm working on a simple Twitter app that checks whether a user is following another user, but I'm having trouble picking up on the inputted values in my form.
I've got this form on my page:
And using the form plugin, here's my JS:
The only thing that's being alerted is "username, username" and it's not registered text inputted into the fields at all.
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View Relatedhow to add forms in javascript, but it's limited to text input forms.
<script type="text/javascript"><!--
function updatesum() {
document.form.sum.value = (document.form.sum1.value -0) + (document.form.sum2.value -0);
}
//--></script>
Where the inputs sum1 and sum2 are text fields you put whatever numbers you want in. That works fine. Great. Now what I'm having trouble with is modifying the code so that it will add one form with an input number with a form that spits out a randomly generated number.
<input type="button" value="D20" onclick="this.form.display.value = Math.round (20 * Math.random())" class="buttonHi" /> <input name="display" type="text" size="6" value="" />
This is what I'm using for my random number generator. So basically I want to be able to put, say, 5, into the input text field above this. And then click on the d20 button to get a random number, say, 15, and then have the first code add the inputted 5 with the randomly generated 15.
I have a problem that I couldn't solve myself. I have 2 forms. name="form1" and name="form2" In each form, there's the same class names for rows. <tr class="draggable">
What I need to do, is to take the last draggable row in a certain form. $( tr_object + " tr.draggable:last" ) <- returns the last tr with class draggable in whole document. How do I limit It's view/search scope to one of the forms only?
BlockUI is not submitting forms! Did I do something wrong? Please help by pointing me to the right direction.[code]
View 1 Replies View RelatedWhen in IE7 or IE6, I can't get a input value with same id. My sample code looks like this:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js" type="text/javascript"></script>
[Code].....
I am in the progress of building a new website; the layout and stuff is already done for the most part, but I am having a problem with the two order forms on my website. Well not the forms themselves, more with how they appear (and disappear).Like stated I have 2 forms on my website. When coming to my website they should be hidden (standard). When someone wants to order they press the link for order form A or form B.
Is it possible to load a page within the DIV for example I want form B to include extra-info.php. Is this possible?If I understand correctly the above would be possible with jQuery with use of hidden DIV's. But I really don't know much about Javascript to pull this of myself.
I have a form with the same structure being loaded in 3 tabs. Now during validation, I will have issues with the IDs of the form fields. Now is it possible to disable the forms in tab 1 and tab 3 when tab 2 is clicked.
View 1 Replies View RelatedI am not new to jqueyr or to programming. I currently keep having problems when using ajax jquery for forms.
here is what I am doing. I have jquery fade in a div and in that div I use ajax to inject html code mainly a form inside this div. When I click the submit button. The form acts like it got processeed but dosen't So it like submits nothing that is only if I use jquery to submit the form. If I use the html old way it works fine but gives me a white blank page when it get processed and I would have to type in the page in the web browser url box to get back to the main page again where I was.
So my question is about ajax and jquery. How do you guys use ajax forms properly without getting errors? I like to make one php file and cram many stuff like the form code and also the processing of the form. I just make sure I got conditions so variables passed to the file will run the right code whennecessary.
So what I would like to know how do you guys setup your ajax forms so there is no errors or problems.
Mine dosen't spit out any errors. Yet I do know the data isn't being submitted yet it acts like it did.
I am rather new to JQuery and would like to use it with php. I ran into problems when my html is not static, I generate php forms on the fly using my php script and JQuery just doesn't seem to validate those forms. When put the same form in static html file JQuery works like a charm. What could be wrong? Does JQuery need a page to be static? Right after I load my php page firebug reports that $(document).ready(function() { is not a function and JQuery is not defined. I have loaded the necessary JQuery libraries.
View 3 Replies View RelatedI have the following code which just submits my login form via AJAX. It works fine. But I am wondering if I can adjust this to work for pretty much every form on my website, rather then copy paste this code over and over and only changing the values to match the form respectively.
[Code]...
I need to have two separate forms, each using a different PHP script that I cannot modify to process them. I need to have both of these forms share the same submit button. Here is a simplified version of the html. I will also need simple validation on these and know Ill have to do all this via jQuery's AJAX function.
View 7 Replies View RelatedI google'd myself silly, I can't find tutorials for this. I hope someone could lend me a hand.
I'll try to make this simple. I have a PHP & MySQL driven site. I have a form for adding new content.
The form has a set of check box options that are pulled from MySQL.
At the bottom of the check boxes there is an "Add New" input field which I want to be used to add new check box options right above it.
database
So as I understand how this should work, when I click in the 'add new' text field, type something in, then press enter - the value of the add new field should be sent to a php script, addnew_backend.php. The form itself should not submit it's data. The PHP script will add the new value to the mysql table of options, and if successful, returns the newley generated checkbox which should fade in right above the add new text field into div#newoptions.
addnew_backend.php
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
$(document).ready(function(){
$('#submit1').click(function(){
$('#form2').submit();
[code]....
I have a simple form for a basic expense tracking app I am trying out. The form has about 8 inputs, either select boxes or text inputs.
It works fine when used on an iPhone. On an android phone with the stock browser running Android 2.2, when I select a text field to type in, the keyboard pops up, but the page scrolls upwards so that the submit button is visible.
The text field is hidden. I have to bring down the text field in focus again and once I start typing, it scrolls again to render the submit button.
This is the form, using Rails helpers:
When I add a tab, whose content is a form. The form is loaded by ajax $.ajax('url'); On ajax complete, I add a custom method for validation, which is supposed to get called when the "Upload" button in the form is clicked, but it never get called. I have searched and tried multiple things for two days now, and nothing works.
[Code]...
I have several forms on the same page that need to use the datepicker plug-in. I have datepicker working PERFECTLY on one form. Now I need to add other forms on the page. I haven't been able to get two datepickers working on the same page nor can I find any documentation on whether it's possible. What do I have to do to get two datepickers working in two separate forms on the same page?
<form method="post" action="?" name="FORM1">
<input type="text" id="datepicker" size="8" name="InactiveLevel3Date">
<input type="submit" id="InactiveLevel3DateInactivate" value="inactivate" disabled="disabled">
</form>
[code]....
I am trying to figure out how to dynamically show/hide certain form elements based on the selection from the drop down list.My form is defined like so[code]...
View 6 Replies View RelatedI want to change the action attribute of certain forms. I am new to JQuery so I wrote this code but it doesn't work at all:
<script type="text/javascript">
$(document).ready(function(){
$("form").not("form[action*=/nxpages/index.xhtml]").each(function(){
alert("Cat1!");
});
$("form[action*=/nxpages/index.xhtml]").each(function(){
alert("Cat2!");
});
})
</script>
But it seems that JQuery doesnt work at all. How can I change the above code to modify the action value to something else?
I've a page that has 2 forms. If the user clicks the bottom form the validations appear and everything goes red but the Top form is a required field but it doesn't as it's a separate form. How can I validation form0 and form1 together to show to the user the required fields. When the user clicks form0 it goes over to a pagedLIst, the user returns and textfield gets populated with the product that as selected. So when they hit form1, that value gets passed through as a hiddenfield..
<form id="form0">
...text box input to search for your product, returns to this page populated the found product
<input class="button" id="FindProduct" type="submit" value="Find Product" name="action"/>
[Code].....
I have a file upload form (see end of email) that I am am processing with jQuery so that it can be submitted via AJAX. When I click the submit button, the form sends as it should (I can see the submit went properly in the server logs). However, the response doesn't get handled properly. In the response, I get a file download dialog (firefox), although the page itself isn't replaced: "You have chosen to download
[Code]...
I am using a variation of the multipage form in the demo and run into a small problem with the pageRquired function. Seems it does not validate correctly if you add any custom selectors after the pageRequired. I am trying to make one field required depending on whether another field is blank. E.g.:
class="{pageRequired: '#field1:blank'}"
In this case, the validation is completely ignored, even if I have {pageRequired:true}. It will only validate if I have class="pageRequired" without the curly brackets. However, if I set it up in rules, it will make the field2 required regardless of the value of field1, e.g.: $(document).ready(function(){
$("#myform").validate({
rules: {
field2: {
pageRequired: "#field1:blank"
}}, debug:true
});
On a whole the multipage validation works very well but not with any custom selectors such as :blank, :filled etc or by using curly brackets in the class. Is there a way around this? I would really prefer to use inline validation using class statements and still be able to use custom selectors. View this message in context: [URL].
I'm struggling with a script for an e-commerce site.When the user clicks the add to cart button they are currently taken to a PHP shopping cart page, but the client wants them to stay on the same page after they press the button and get notified that an item has been added to the cart.The add to cart button is a form submit button, because there is also a quantity field for each item. I would have cracked this by now but there are multiple add to cart buttons on each page and when I submit the form only the data from the first form in the page is sent to the cart page.Here's a dummy version the JavaScript:
Code:
$(document).ready(function(){
$('.subbtn').click(function(){
$('<p id="add">Added To Cart</p>').insertAfter(this).fadeOut(3000);[code].....
At the moment I've got it set so that AJAX returns information to the page (just so I know it works), but this won't happen on the actual page.So, as far as I can tell, I need a way of POSTING $(this).parent(); $('[name=quantity]').val(), but I can't seem to find the correct syntax.
I've been searching everywhere for an answer, tried everything I know and for the life of me I cannot seem to be able to submit a form inside a jQuery UI tab. I have a bunch of files that are loaded with AJAX inside the tabs and I would really need to pass form data in them ...
View 1 Replies View RelatedI'm trying to use a single submit button to submit 3 forms on a single page. 1 form I use and process, the other 2 are sent to other sites.
Everything works great except in Google Chrome (and Safari) due to some restriction/bug in WebKit.
Code:
This works perfectly fine in IE and FireFox, but in Chrome - as it sits, it will submit the first 2 forms only. Yes, I know the return false prevents anything else, I'm getting to that.
With the return false in, it will submit the 2 forms. Removing return false only processes the form named Test1 and not the other 2.
I've shown code for attaching to the click event hoping that I could sneak my submits in on that, then let Chrome carry through to the submit function, but that doesn't work either.
I m aware of various ways to validate forms using JQuery, but here I have a complex thing, and i need the most optimized code for it... Basically I have a form made up of rows each containing a number of input text fields which are repeated on a the following rows however of course with different IDs and names... There is no need to fill all the rows, but it is necessary to fill all the fields of a specific row. Now I was wondering, how can i make sure that each row is properly filled? knowing that some rows will be totally blank [which is okay]
View 4 Replies View Related
