JQuery :: Get The Position Of An Element Relative To The Document (accounting For Margins As Well)?
May 26, 2010
What is the best way to get the position of an element relative to the document (accounting for margins as well)?I would like to position another element over it. I'm using the offset() function but i am running into issues 1. The values for top & left returned in IE 8 (perhaps other versions) are incorrect.2. Offset() doesn't take into account margins of the element. And when margins are set to auto i cannot seem to get the correct margin values to use
how can I get the absolute position of a relative element?
We dynamically create a page with multiple segments which are relatively ordered among each other. In these segments we have input fields. When such an input field is focused I need it's absolute position. Is there a way to do so with IE > 6?
I'm busy trying to build an interface where users can create a sort of collage with images that they upload. I know it is possible to get the position of a DHTML element relative to the screen, the problem is I need the coordinates relative to a main div tag so that I can "compile" the collage and then when it gets served it will look the same regardless of screen size.
I need to find the position of an element on the page relative to the browser window. Its part of a popup calendar script (and no, they don't want to change it so please don't suggest jQuery date-picker etc) The script uses these functions [url]... to find the position of the anchor to pop up the calendar next to it.
Now the client wants to make the calendar fixed when the user scrolls so that it always stays on screen. The most graceful solution is using css position:fixed (I'm aware it doesn't work in IE6 - that's not a problem)
I've been using the getAnchorWindowPosition function to get the coordinates but the numbers its giving are wrong (to different degrees depending on the browser) It was only 200px out in the Y axis in Firefox but in IE7&8 its off the screen.
Have a web app which consists of a form and have it set up to launch a dialog box containing information next to the subject label text field.Everytime, someone fills out the form and clicks on submit, the form's message body (from the text area of the form) is displayed on top and theform is displayed underneath it. Before, I had it set up as fixed (x,y) for the dialog box to appear next to the subject label. But, now, whenthe page becomes longer, the dialog box doesn't appear next to my subject label text field. It is displayed a lot lower.
Here's the code to find the position:
// Finds the position and adds 40px to the left axis. function findPosition(obj) { var curleft = curtop = 0; if (obj.offsetParent) {
[Code]....
How can I set it so my findPosition() calculation doesn't miscalculate when the page is too long (when scroll bars are needed)?
Is there a way to set the relative positioning to always have the dialog appear 40px right of the subject label?
I had askedthis question on another forum but unfortunately I was unable to find a fix. I have a select and drag code that works well until in selection is added a position relative div. Here is the code and you can see a working demo at [URL] To see the problem just mouse select span 1, span 2 and the nested span 4 You can see the code and demo at http://jsbin.com/azeli/2
I display tooltips on my page that appear to the right of form elements. But if the element is too far to the right, the tooltip gets cut off. in that case i would like it to appear to the left.
I made this quick 12sec/600KB screencast to help illustrate what's happening:[URL]...There is a hidden div that contains the fieldset. The slide is applied to the div. In Firefox, the element that has the slideDown/SlideUp effect applied works fine. In IE7, the element just appears, then the elements around it slide (which appears broken)
The fieldset element has a position:relative property (which is needed for fixing CSS bugs on the legend tag)
If I remove the position:relative property, slideUp/slideDown works fine in IE7 (but breaks the legend tag)
Is there a way around this without having to remove the position:relative property?
I'm having a problem with css positions !! i want the position of an image to be fixed when the user scrolls till some point and the position should be set to relative after that
I have an iframe with some javascipt that gets the mouse x and y position like this:
//inside the iframe's onmousemove call back funciton xMousePos = window.event.clientX + document.body.scrollLeft; yMousePos = window.event.clientY + document.body.scrollTop;
This gets the x and y position inside the iframe. But what I want is the x and y position of the parent window, not the screen like screenX. Is there any easy way to get parentX and parentY or to get the offset x and y of the iframe relitive to the parent from inside the iframe?
I wonder if you can help? I've implemented a ready made JavaScript vertical toolbar into my Web site but have problems with positioning. It only has by default absolute positioning parameters and I need to change them to relative as whenever the browser is resized the menu stays at the same place on the screen. I was told that using <DIV> tags can help, but I have no idea how to do it.
Can anyone please submit a working example code of asigning relative parameters to the menu?
I want my divs (position: absolute) to be positioned relatively to window size My page is a main table with one cell containing all the rest This cell (anf thus my page) is centered (top and left) Each menu link has onMouseOver which shows (visibility) the corresponding layer (div)
Each visible/invisible layer is positioned on the same spot I use absolute positioning for the divs because some browsers don't support positioning relative to tables My question: is the following code the only solution or am I making my life (slightly) complicated over nothing?
This thing works on NN4, 6 7, IE 4, 5, PC and Mac -- that I know of; repositions divs onResize, with reLoad fix for !#+x°! NN4 I get the window size: Code:
I am trying to make a layer that mimics a particular cell in a table (please dont ask me why, its complicated). I have created the layer so that its dimensions exactly match the table cell in question. Now I want to create a function that sets the top and left position of the layer to exactly match the top and left position of the cell in question. I have already had a try myself, but for the life of me can't quite figure it out.
I tried giving the cell in question and 'id' tag (id="centerCol") and then referencing the left and top values of the object. See the following code:
I managed to get my hover over text pop up to work but now I would like the text box to pop up in the same location relative to the text As you can see here, when you hover over any text not within the first row, it is a bit all over the place. Is there any way making the text pop up the same way it does for the first row for the other rows?
I have a div called pageWrap to wrap my page with the css as margin-top:-46px;
I would like to use Javascript onClick on another div. This Div is called loginButton, the onclick should change the the css of pageWrap to 0px and onclick again should change it back.
I have a 'window' that is moveable on this test page:[URL]... I'm trying to use cookies to store the window positions in the mouseup function. That part is working fine. The problem is that I can't figure out how to locate the window to the x,y variables after returning from checkCookie(). I've tried a few things and they are commented out if you look at the javascript. I thought that this would work, but it doesn't:
I'm really sorry to post this as I know it must have been asked countless times before, but I can't find an answer anywhere.
Does anyone have a snippet of JavaScript code I could borrow which calculated the difference in years and days between two dates, and takes leap years into account?
I'm calculating the difference in the usual way, i.e....
var difference = dateTo.getTime() - dateFrom.getTime();
....and converting this millisecond value into days by using...
var daysDifference = (difference/1000/60/60/24);
But how do I then display the difference in days AND years? I've tried the following:
var yearsDifference = Math.floor(daysDifference/365.25); var daysLeft = Math.floor(daysDifference-(yearsDifference*365.25));
....but it gives me inaccuracies. For example, if I use my code to calculate the difference between 05/01/1998 and 05/01/2000 it returns 1 year and 364 days!
It's possible to style document.body not to start at 0,0 for example: body {width: 1000px; margin-left: auto; margin-right: auto;} This means that X/Y of the body is not 0,0 but how can I find out what the position is using javascript? document.body.offsetLeft; is 0 and offsetParent is null yet if I position something absolutely at 0,0 it goes to 0,0 of the window, not the body!
Now if someone clicks on the row with content "help" (2nd), I want to catch the click with jquery .click() and know within the jquery code that the user clicked on the 2nd <tr> element within table#tbl.
If someone clicks on the <tr> with content "this", my jquery code has to return 5, because its the 5th row.
function executeUntil(end) { var i=0 ; while(i< 100) { if(i==end) break ; document.write("Javascript is fun"); i++; } return(i); }; (executeUntil(01));
@ runtime, the output is Javascript is fun (obviously).
My question is, how can I apply a CSS style to the document.write output, and how can I make a layer (well I know how to do that, lol), but say that I want the output to appear in that layer to control the appearance of the content? If I can do the latter with the layer, then applying a CSS style is simple.
i would like to know the absolute position of an element (e.g. <LI>) in the browser. i nned to know it in order to place juste beside another element (e.g. submenu).
for example: i have a <li> tag which is at 400px from my browser left border (because it is inside a div which is screen centered). this <li> has a width of 180 px so if i want to know the most left position for my submenu, i should get 400 + 180 = 580 px (from the browser left border).
i tried offset but without success. in fact it returns me 0.
