New to jQuery and Validation so please go easy :) The issue: If I validate more than one field with 'phoneUS: true' it breaks jQ Validation and no longer validates anything at all.
[Code]...
New to javascript and I have the following code in onSubmit() validation:
else if (cofaCOURRIEL == null || cofaCOURRIEL == "") {
alert('Le champ COURRIEL doit être rempli.');
document.forms["COFA_AIG"] ["COURRIEL"].focus();
return false;
}
else if (cofaCOURRIEL) {
if ( (atPOS < 1) || (dotPOS < atPOS + 2) || ((dotpos + 2) >= cofaCOURRIEL.length) ) {
alert('Adresse de courriel invalide.');
document.forms["COFA_AIG"] ["COURRIEL"].focus();
return false;
}}
else if (cofaDATE == null || cofaDATE == "") {
alert('Le champ DATE doit être rempli.');
document.forms["COFA_AIG"] ["DATE"].focus();
return false;
}
I understand it is not the best way to validate client side, but I will be doing php server side validation as well. My problem is that once the variable "cofaCOURRIEL" is valid, the script stops and returns true....not sure why...I'm guessing I'm missing an "else" statement after the embedded "if" statement, but I'm only guessing and if I'm correct, I wouldn't know what to put in the else statement to let it not break out of the validation. Any input?
I'm using the Form Plugin to allow a user to upload a photo.The user clicks on a link in the page and I display a dialog collecting the file and description.It works great the first time, but when they do it again the description and a hidden field is not passed n the form.How can I get the form to work more than once without reloading the page?I call this on the click of the link on the page.
var options = {target: '#divToUpdate', success: PhotoUploaded};
$('#photoForm').ajaxForm(options);
I have a form with a jquery listener that runs when you click the submit button. If there are errors an alert box will pop up telling you what they are. sometimes this box will pop up multiple times because the form is being re-submitted without clicking the submit button.
live demo: [url]
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I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedWe have a webpage setup to alpha page individual people with pagers at work. It is a simple form that submits to a php file on the pager server. I am working on creating a script that submits a alpha-page to everyone at once. There are about 120 different ppl in the company, I want the script to submit the form once for each persons pager. I'm new to javascript but have alittle programming understanding.
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I need to validate two forms containing multiple input fields but want just one error message if any of the fields are left blank, the page is required to submit the users details (registration form). Also if any of these fields are left blank i don't want to be able to go to the next page on clicking the submit button
View 1 Replies View RelatedI have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have a large form. One part of it is a column with selects. All drop-downs initially set to "No". The only other option is "yes". I need to make sure that at least one select is set to "yes". Any number, even all of them can be changed to "yes", but only one is required. I can easily add a rule that requires all the fields of the certain class to have certain type of value, but can't think of a way in js to only have one required. I can easily count number of "yes" values with PHP and prevent submitting on the back end, but would really like to have jquery do it first.
View 1 Replies View RelatedI am working on single form divided into multiple pages using <div id="">. I am using next and previous buttons <input type="button"> to navigate between these pages but I am unable to validate each page before moving to next page using next button.
I am displaying next page form by using "element.style.display = 'none' & element.style.display = 'block' " method.
How to with validation on the current page before moving to next page.
I am adding my code below:
I've many dynamic form on my current project. One if them have a two radio button, acting a little bit like tabs. If you select the first radio, the end of the form change to display the "branche #1", and if you select the second radio button, the end of the form change to display the "branche #2".
Let recap with dummy code:
And now I will have to make 3 validations:
1) The first one for the common field.
2) The second one, if buyer is selected.
3) The third one, if seller is selected.
So the code should look like:
But is seem that only my common fields get validated. How should I handle that situation ?
Run the following on a select field but only works when I remove the multiple="multiple"
View 3 Replies View RelatedI have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
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I'm building a web app the processes information into a DB. I'm attempting to write a JS validation page. On this page I'm also trying to make the button perform a submit only if the validation returns as true.
Somehow I would like to say if all fields are true then submit to submission.php.
I've setup a form on my website and added a simple validation script to check a few of the fields. After all the validations are done I want the submit button to process two other functions that will handle the submission of the form.
The problem is that if the validation returns true the script just stops and doesn't run the other two functions.
Here is my validation script:
Then on my submit button I have:
I am stuck here with a problem. I want to check if someone enters a negative score on a multiple form page. I want that the edit field is red color if the score is negative.I call htis function with the onblur event input name="pickscorehome" type="text" class="pickedits" id="pickscorehome" onblur="checknumberhome(this.form);" onchange="Setradio(this.form);"The problem is that there are an undefined number of forms on the page that are generated out of a database. How can i do that for each form ? Seems works only on
function checknumbervisitor(f)
{
if(parseFloat(f.pickscorevisitor.value)<0)
[code]....
This is my first post to this forum. When a button in parent window is clicked multiple times, more than one popup window is opened. This problem is occurring in linux firefox and mozilla browsers. In windows the code is working fine. Is there any option in window.open() method to open a popup window once. s there any known issue regarding this case?. Need a workaround to fix this issue.
View 1 Replies View Relatedhen a button in parent window is clicked multiple times, more than one child window is opened. This problem is occurring in linux. In windows the code is working fine. Is there any option in window.open() method to open a child window once.
View 8 Replies View RelatedI'm validating a form that has two buttons ("Next" and "Back"). The call
to the script is currently in the form's onSubmit() handler. Upon
pressing either button, the script runs. This is understandable, since
either button press is considered a submit. Is there a way to test which
button was pressed to determine whether or not to run the script?
I don't know why it's not running the validation js first upon "submit", it goes straight to the "thankyou" page specified by the php (let me know if php needs to be posted). I've check my syntax over and over, I can't see anything.
I'm trying to have a "tell-a-friend" form where one requires to enter his/her first name, surname, email and a friend's email � with option of forward to to other 4 friends (total 5).
Here are the fields I need to validate:
My js (validationB.js) file:
It is all working fine now. However I need to validate form input fields and I'd like to have the javascript in seperate files.
Here's the javascript I've developed so far:
Code:
function removeChar(sourceText){
var charToRemove = / /gi;//Any character between "/" and "/" is removed from the user's input (By default a space is removed)
[Code].....
Basically, I want to have the takePostcode and fidelityCard functions in seperate files, but I want the removeChar function to work for both of them.
The code works perfectly fine when it's place within the webpage itself, but I'd like to include them in the head as external files.
I have been using this simple js function to validate a field in a form is filled in.
<script language="JavaScript">
<!--
function SubmitForm()
{
var form = document.formname
if (form.client_id.value.length == 0)
{
alert('Please make a selection from the list');
form.client_id.focus();
}
else
{
form.submit();
}
}
//-->
</script>
Now I have a page with multiple forms and I would like to use the same script to validate depending on which form is submitted. I thought I should be able to do something like this.... but know very little javascript...any suggestions? Code:
I know it involved naming the html form inputs as col001row001, though. Doing that dynamically in asp is no problem, but how do I get the row number to be recognized inside javascript's "document.form.column###.value" while going through a for loop?
View 4 Replies View Related<script type="text/javascript">
function changeinput(){
if(document.getElementById(�MERGE2�).value=checked){
document.getElementById("newsletteru").value = "sadfjflaskfj";
document.getElementById("newsletterid").value = "345345";
}
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This is a form to subscribe people to a newsletter on Mailchimp. There are two lists: community, student. I am trying to separate people into one or the other based on the checkbox input, "Check if you are a student." To do this, on submit, I need the two hidden inputs, "u" and "id," to be set differently depending on whether the checkbox is checked. The error right now I'm getting is that it's not being linked to a mailing list. Most likely "u" and "id" are not being set properly. The javascript is fairly short, and I'm wondering if its setting the values correctly.
I'm only validating one (Consent) radio button with this code but I need to validate multiple different questions/buttons.
<script>
function getRBtnName(GrpName) {
var sel = document.getElementsByName(GrpName);
var fnd = -1;
var str = '';
for (var i=0; i<sel.length; i++) {
if (sel[i].checked == true) { str = sel[i].value; fnd = i; }
} return fnd;
}
function checkForm() {
var chosen = getRBtnName('Consent');
if (chosen < 0) {
alert( "Please choose one answer when you are asked to select a number." );
return false;
} else { return true; }
}
</script>
<form action="congratulations_aff.php" method="post" name="congratulations_aff" onSubmit="return checkForm()">
<table border="0" cellspacing="1" cellpadding="0">
<tr>
<td colspan="3">I consent to providing my electronic signature.</p></td>
</tr>
<tr>
<td colspan="3" valign="top">
<input type="radio" name="Consent" value="Y" />
Yes
<input type="radio" name="Consent" value="N" />
No
<table border="0" cellspacing="1" cellpadding="0">
<tr>
<td>I consent to electronic receipt of my information reporting documentation.</td>
</tr> <tr>
<td valign="top">
<input type="radio" name="Consent1099YesNo" value="Y" />
Yes
<input type="radio" name="Consent1099YesNo" value="N" />
No</td>
</tr>
<tr>
<td valign="top">
For tax purposes are you a U.S. citizen, U.S. resident, U.S. partnership, or U.S. corporation?
<input type="radio" name="USPersonYesNo" value="Y" /> Yes
<input type="radio" name="USPersonYesNo" value="N" /> No
</tr> </table>
<input type="submit" value="submit" value="Submit" />
</form>
I have a problem when I use the .live() function that I can't figure out. It's something I've run across several times and it keeps confusing me.
My jQuery:
jQuery('#content div.portfolio').live({
mouseover: function(){
jQuery(this).find('img').fadeOut();
[code]....
My problem is: when the mouse enters and leaves the image the image fades in and out for up to four times. The first mouseenter is just fadeout, fadein, fadeout. why is the event being triggered multiple times and more importantly what can I do to prevent this behavior?