I'm validating a form that has two buttons ("Next" and "Back"). The call
to the script is currently in the form's onSubmit() handler. Upon
pressing either button, the script runs. This is understandable, since
either button press is considered a submit. Is there a way to test which
button was pressed to determine whether or not to run the script?
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI have a form with several fields.
Each field can be modified:
- individually (one submit button next to the field)
- globally (a submit button at the end of the form).
Before submitting the form, a validation needs to be performed.... so I added: onSubmit="return isValid()".
If the validation does not pass, the form needs to be shown with the data previously entered by the user.
Now, I haven't even come to the previous problem I have mentioned..... my problem is that if a field is empty, the function isValid() recognize it (message sent) .... but the reDirect function is performed!
I need to validate two forms containing multiple input fields but want just one error message if any of the fields are left blank, the page is required to submit the users details (registration form). Also if any of these fields are left blank i don't want to be able to go to the next page on clicking the submit button
View 1 Replies View RelatedWhat I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I have a general form validation question. I know very little about
javascript, a little more about PHP. Using yav (http://yav.sourceforge.net):
<form method="POST" name=edit onsubmit="return performCheck('edit', rules,
'classic');" action="pages_edit_submit.php">
<input type="text" name="title">
<input type="submit" name="Save">
<input type="submit" name="Cancel">
</form>
.... PerformCheck fires when any submit button is click, which is logical but
I'd like to prevent this if it was the cancel button that was clicked (and
preserve form submission on pressing Enter whilst in the 'title' box.
So i have a form that has 3 radio buttons and i want to validate so that you must select at least 2 Yes's. I am new to javascript so excuse my poorly written statement. It is non-functional, how to change this in order to make it functional.
Code:
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
How do i begin a validation script for a form with radio buttons & check box & text area.
View 2 Replies View RelatedI have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
View 4 Replies View RelatedI am stuck here with a problem. I want to check if someone enters a negative score on a multiple form page. I want that the edit field is red color if the score is negative.I call htis function with the onblur event input name="pickscorehome" type="text" class="pickedits" id="pickscorehome" onblur="checknumberhome(this.form);" onchange="Setradio(this.form);"The problem is that there are an undefined number of forms on the page that are generated out of a database. How can i do that for each form ? Seems works only on
function checknumbervisitor(f)
{
if(parseFloat(f.pickscorevisitor.value)<0)
[code]....
I don't know why it's not running the validation js first upon "submit", it goes straight to the "thankyou" page specified by the php (let me know if php needs to be posted). I've check my syntax over and over, I can't see anything.
I'm trying to have a "tell-a-friend" form where one requires to enter his/her first name, surname, email and a friend's email � with option of forward to to other 4 friends (total 5).
Here are the fields I need to validate:
My js (validationB.js) file:
It is all working fine now. However I need to validate form input fields and I'd like to have the javascript in seperate files.
Here's the javascript I've developed so far:
Code:
function removeChar(sourceText){
var charToRemove = / /gi;//Any character between "/" and "/" is removed from the user's input (By default a space is removed)
[Code].....
Basically, I want to have the takePostcode and fidelityCard functions in seperate files, but I want the removeChar function to work for both of them.
The code works perfectly fine when it's place within the webpage itself, but I'd like to include them in the head as external files.
I have been using this simple js function to validate a field in a form is filled in.
<script language="JavaScript">
<!--
function SubmitForm()
{
var form = document.formname
if (form.client_id.value.length == 0)
{
alert('Please make a selection from the list');
form.client_id.focus();
}
else
{
form.submit();
}
}
//-->
</script>
Now I have a page with multiple forms and I would like to use the same script to validate depending on which form is submitted. I thought I should be able to do something like this.... but know very little javascript...any suggestions? Code:
I know it involved naming the html form inputs as col001row001, though. Doing that dynamically in asp is no problem, but how do I get the row number to be recognized inside javascript's "document.form.column###.value" while going through a for loop?
View 4 Replies View RelatedI have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have a large form. One part of it is a column with selects. All drop-downs initially set to "No". The only other option is "yes". I need to make sure that at least one select is set to "yes". Any number, even all of them can be changed to "yes", but only one is required. I can easily add a rule that requires all the fields of the certain class to have certain type of value, but can't think of a way in js to only have one required. I can easily count number of "yes" values with PHP and prevent submitting on the back end, but would really like to have jquery do it first.
View 1 Replies View RelatedI am working on single form divided into multiple pages using <div id="">. I am using next and previous buttons <input type="button"> to navigate between these pages but I am unable to validate each page before moving to next page using next button.
I am displaying next page form by using "element.style.display = 'none' & element.style.display = 'block' " method.
How to with validation on the current page before moving to next page.
I am adding my code below:
I've many dynamic form on my current project. One if them have a two radio button, acting a little bit like tabs. If you select the first radio, the end of the form change to display the "branche #1", and if you select the second radio button, the end of the form change to display the "branche #2".
Let recap with dummy code:
And now I will have to make 3 validations:
1) The first one for the common field.
2) The second one, if buyer is selected.
3) The third one, if seller is selected.
So the code should look like:
But is seem that only my common fields get validated. How should I handle that situation ?
<script type="text/javascript">
function changeinput(){
if(document.getElementById(�MERGE2�).value=checked){
document.getElementById("newsletteru").value = "sadfjflaskfj";
document.getElementById("newsletterid").value = "345345";
}
[Code]...
This is a form to subscribe people to a newsletter on Mailchimp. There are two lists: community, student. I am trying to separate people into one or the other based on the checkbox input, "Check if you are a student." To do this, on submit, I need the two hidden inputs, "u" and "id," to be set differently depending on whether the checkbox is checked. The error right now I'm getting is that it's not being linked to a mailing list. Most likely "u" and "id" are not being set properly. The javascript is fairly short, and I'm wondering if its setting the values correctly.
I'm only validating one (Consent) radio button with this code but I need to validate multiple different questions/buttons.
<script>
function getRBtnName(GrpName) {
var sel = document.getElementsByName(GrpName);
var fnd = -1;
var str = '';
for (var i=0; i<sel.length; i++) {
if (sel[i].checked == true) { str = sel[i].value; fnd = i; }
} return fnd;
}
function checkForm() {
var chosen = getRBtnName('Consent');
if (chosen < 0) {
alert( "Please choose one answer when you are asked to select a number." );
return false;
} else { return true; }
}
</script>
<form action="congratulations_aff.php" method="post" name="congratulations_aff" onSubmit="return checkForm()">
<table border="0" cellspacing="1" cellpadding="0">
<tr>
<td colspan="3">I consent to providing my electronic signature.</p></td>
</tr>
<tr>
<td colspan="3" valign="top">
<input type="radio" name="Consent" value="Y" />
Yes
<input type="radio" name="Consent" value="N" />
No
<table border="0" cellspacing="1" cellpadding="0">
<tr>
<td>I consent to electronic receipt of my information reporting documentation.</td>
</tr> <tr>
<td valign="top">
<input type="radio" name="Consent1099YesNo" value="Y" />
Yes
<input type="radio" name="Consent1099YesNo" value="N" />
No</td>
</tr>
<tr>
<td valign="top">
For tax purposes are you a U.S. citizen, U.S. resident, U.S. partnership, or U.S. corporation?
<input type="radio" name="USPersonYesNo" value="Y" /> Yes
<input type="radio" name="USPersonYesNo" value="N" /> No
</tr> </table>
<input type="submit" value="submit" value="Submit" />
</form>
New to jQuery and Validation so please go easy :) The issue: If I validate more than one field with 'phoneUS: true' it breaks jQ Validation and no longer validates anything at all.
[Code]...
I have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
[Code]...
I'm trying to get a radio button validation for different sets of radio buttons that simply contains Yes & No buttons.
Here's what I'm trying to do:
Question 1: if Yes, then (Alert 1) if No, then (Alert 2) (if Yes, then Question 2 appears) *Up to here I'm happy- can't figure out the rest*
Question 2: if Yes, then (Alert 1) if No, then (Alert 2) (if Yes, then Question 3 appears)
I need the Alerts to be swapped from this point*
Question 3: if Yes, then (Alert 2) if No, then (Alert 1) (if NO, then Question 4 appears)
Identical for Question 5, and for Last Question 6 Alerts swapped back again.)
Here's the script that I managed to piece together:
I am using jquery with the cookie plugin and I have multiple image buttons that can hide/show multiple elements. My question is how can I add a cookie to this code to remember whether each separate element is opened or closed?
The code,
$(document).ready(function() {
// choose text for the show/hide link - can contain HTML (e.g. an image)
var showText='<div class="expanddown"></div>';
var hideText='<div class="expandup"></div>';
// initialise the visibility check
var is_visible = false;
// append show/hide links to the element directly preceding the element with a class of "toggle"
$('.toggle').prev().append('<a href="#" class="togglelink">'+hideText+'</a>');
// capture clicks on the toggle links
$('a.togglelink').click(function() {
// switch visibility
is_visible = !is_visible;
// change the link depending on whether the element is shown or hidden
$(this).html( (!is_visible) ? hideText : showText);
// toggle the display - uncomment the next line for a basic "accordion" style
//$('.toggle').hide();$('a.toggleLink').html(showText);
$(this).parent().next('.toggle').slideToggle('fast');
// return false so any link destination is not followed
return false;
});
});
HTML,
<a class="togglelink" href="#"></a>
<div class="toggle">
Content
</div>