I'm loading a (HTML) list from mySql via PHP into a main page using load. The main page is linked to a css file and a js file (jquery). The loaded data assigns the css file BUT does not seem to be able to find the js file as the click handlers in that file do not work. I'm new at this and this is probably a BASIC issue.
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I am attempting to do two things and I'm missing a vital element: ajax call to an XML file to be inserted onto a page, FOLLOWED by selecting these newly created elements to apply event handlers on them. I am near certain that the problem is that the selectors are not 'seeing' these elments and it's an issue of running the event handler only AFTER these elements have been loaded.
How do you do this? I already have a $(document).ready(function() { in order which I naively thought would take care of this exact issue...
I have searhed all the web about this Question I hope I can find the answer here.
I have loaded external file js into html page :
<table><tr><td id=x>
<script language=JavaScript src = first.js></script>
</table></tr></td>
NOW :
I need to click on a button or a link to load the external second.js instead of the old one first.js
I don't want to use any iframes...
Any idea how to load external js files in <td> tags or any other place in html page.?:rolleyes:
I'm trying to load an xml file with jQuery but it doesn't seem to work. This is my code, I made it very simple for testing, but it doesn't work.
var test = "./test.xml";
$.get(
test,
function(data) {
$('#textarea').text(data);
});
I just don't know how to get the data of an xml file, does the $.get method not work with xml? When I try it with an .html file it works.
I'm trying to access data from a .txt file, and parse that data with jQuery. My .txt file is written like this:
&month=November&day=Tuesday&hour=15
If I use jQuery.get() I do see the data but I want to parse through that data so I can get name and value pairs. This is what I used:
<script type="text/javascript">
jQuery.get('http://www.example.com/test.txt', function(data) {
alert(data);
});
I have a question about load(). I created a php script that simply returns <img src="something.jpg" class="myimage">
To test I created this code, the image loads fine and the mouseover works fine showing the alert dialog :
However, my trouble seems to be that if I bind mouseover to the class "myimage" nothing happens, like so :
Seems that the document would load the html first then the mouseover bound to the class (myimage) would fire off.
My client will upload some pdf files in my php page.
I want to find a pdf file is normal file or shared review file. If it is shared review file then only i can allow to upload that file.
How can i find a pdf file is normal file or shared review file?
Dynamically, I create a container DIV with an iFrame inside.
When the iFrame content page is loaded, I would like to determine the ID,
name DIV object reference of the "container" DIV with an onload javascript
function.
Is it possible? ...and if so, how would I do this.
If I load all the external page, the javascript works... But if I only load a fragment (using .load("page2.html #only_load_this")), the javascript is not executed.
Here is my code:
This is index.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
[Code]....
The code is supposed to generate this: PS: This is generated by a PHP Function that the Ajax Load Method Calls.
[Code]...
I've been noticing a lot of problems when loading these stuff, Sometimes I have to remake the HTML Tags because its not showing anything. Is there any option? I want it to load EXACTLY how it is, I don't know if this is some kind of protection for bad code, but if it is I would like to disable. But also, this code is really clean. no problem, I don't know.
I have loaded the form in div tag using load() like below.$("#empdiv").load("http://empdata.employee.net/empinfo.html"); Now, I want to access the input fields in the empinfo.html.
View 1 Replies View Related I'm working on an embedded device and I want to display only part of the original configuration page by building a jQuery page on top of it. Unfortunately, the code that generated the pages was not ajax friendly in the sense that the only way I have to identify the parts I want to show or hide is the class attribute. Up to now, I've been able to load the page with the simple code:
<div class='contentcontainer'>
<hr> <div id="content">
</div>
</div> <script type='text/javascript'>
[Code].....
But it doesn't work. Then I read on the [URL] that I would need to wrap it:
Chris Moore
9 months ago
If you want to load some content into a div and then manipulate it afterwards ((ie: loading something your use a template for a message window and then want to change the message contents) you *must* do it by wrapping it in the completed function handler..
Don't just throw it a few lines down, you'll get random chances that the selector will
how I should do this? Do I need to replace the test() function by a function that will do the post treatment? How then?
I have a page (index.php) with a pictures carousel that works with css and jquery. I want to loaded a new carousel into a <div> after the page is loaded using the $('#mydiv').load('myscript.php') function that calls a php script returning the html code for the carousel, containing a list of images.So I have a <ul> of pictures that doesn't work as a carousel without the CSS and jquery code that has been loaded on the page when my index.php loaded on the first place.So, since the page has already been loaded the carousel doesn't work properly.It seems like the jquery code for the carousel to work, should execute every time I load a new list of images with the load() function.
View 1 Replies View Related$('#food_rate').load('/ajax.php?x=get_food');
$('#tax_rate').load('/ajax.php?x=get_tax');
$('#mood').html(function(){
return ($('#food_rate').html()-$('#tax_rate').html())*10;
});
$('#mood').html always contains the value of the values food_rate and tax_rate had before I loaded the new values in. (Before Line 1 and 2 happen)I already red, about event bubbling and event delegation, but the html-elements fax_rate and food_rate exist from the beginning, and only their innerHTML does change.
Here is what I'm trying to do but the problem is "source.html" is not on a server somewhere. I am running everything locally. $('#container').load(source.html #sourceContent) Is there a way to do this exact thing but with a local file?
View 3 Replies View RelatedI am making an project what's require load scripts after the page it's fully loaded, so i use an append and thats work ok, when you make clicks, selects, or other events but when i try to execute some script in the load event theres comes an error.theres my code of the page if anybody needs.
window.onload = function(){
var fncName = 'general';
chargeFnc('index', 'srcfnd', fncName);
[code]....
I have code that lets the user click on a link. When he does that, it calls the .Load function. This loads some HTML (a div and some contents) into a tag. Then it tries to color the left border of the DIV that it loaded. Now the interesting thing is that it does succeed to color that border very briefly - but immediately the color is covered up with black, which is the original color.
[Code]...
I am pretty new to jQuery and my programming skills are almost non-existent.
But I was wondering; is it possible to create something which will load a page (or php include) when the website has been fully loaded with a loading bar?
The reason why I want this, is cause I am building a website and it will have a ping (to severs) script, but it takes a "long" time to load (depending on the servers that are being pinged). So it can take anywhere from 2 or 3 seconds to 10 seconds (or even more). So it would be nice that first the website would be loaded completely and when that's done, it should load the ping script and show that it's loading with a loading bar.
Is this possible and easy to do?
I'm using .load to load a snippet of code into a div on a page. This works fine, but IE won't show the div if there is any JQuery, or indeed and sign of <script></script> tags. The snippet I'm loading contains a form with a from/to date and needs some form validation, all of which I wish to use JQuery for, for instance:
[Code]...
Putting this script anywhere in the main body of my html page means that JQuery can't see the fields which eventually get loaded into the waiting div on the same page (even when using $(document).ready ). The field seems to be too deep in the DOM and loading too late for JQuery to see it. Anyway, this is why I want to include it at the top of the loaded html snippet. Is IE known to have a problem with scripts in .load-ed snippets? p.s.The reaction of IE is just to show a blank div.
I have a nproblem with running commands from a loaded page;[code]Now i want to execute the alert() on page BB.html when doing the load on page AA.html.
View 2 Replies View RelatedI am wondering how to select a div on a page that is loaded using the .load() function.I have tried using a function in the callback of the page to select elements but this didn't work.It appears the pages are called after a the document has loaded (which makes sense) thus anything I place on the page that is loading the various data into the the content div can't selected the newly loaded content.I could include the new script on the pages I am loading but this would result in the undesirable editing every page I have made.
View 6 Replies View RelatedI have successfully loaded an element of content from another section of our website on a page, but for some reason it is firing .load() twice and displaying the section of content twice, stacked on top of each other.
<script type="text/javascript" src="/js/jquery.162.min.js"></script>
<script type="text/javascript">
$(function() {
$('#site_navigation').load('/store/ .menu_div', function() {
[Code]....
I have a php script which contains various links which get handled by a jQuery function which in turn passes parameters to and loads another php script. The php script that gets loaded queries a large MySQL database and returns a set of results in an HTML table. Where there is more than 1 page of results the php script provides page numbers which can be clicked on to bring up further pages of results. Where there are more than 20 pages a small algorithm displays an abbreviated set of page numbers,This obviously worked fine when the script was running on its own but now it's being loaded using jQuery it's preumably of no use. Can anyone suggest a way of tackling the problem, I did take a look at various pagination plugins but they didn't seem to be what I was looking for based on what I've said above.
View 4 Replies View RelatedI am developing a web application in which user can change the theme of the page.
So for this i am changing href attribute of the link tag on selection of the perticular theme.
Problem is that when i change the theme whole page gets messed up till the new css fileis fully loaded.
So how can I check if the CSS file is completely loaded or not?
I have my site all set up with a horizontal accordion menu and a content area into which I load a DIV via jQuery from an external php-file.
Let's say I have the content of one category loaded and I offer two links to switch between subcategories. Now of course I could simply have the content in different DIVs - both loaded and only one at a time visible and toggle. But the markup is always the same, only the text in different. So I would prefer not to repeat the markup and instead define the text through a php-variable and an if-else-construction. To achieve a result, I would need to reload (or rather reparse) the already loaded php-file with the new condition when clicking on the subcategory.
Is there a way to "unload" the ajax-loaded file or reload it? I tried simply loading it again and also removing the DIV before that. But it didn't work. Also now not solely the DIV is loaded but the whole page reloaded. Neither
Code JavaScript:
Nor
Code JavaScript:
would do it.
I have been mostly working with php and prefer it in these cases also in terms of progressive enhancement.
Code JavaScript:
PHP Code:
I've googled the heck out of this, and although I'm finding plenty of solutions, I'm having trouble understanding them. I'm very new to jquery, and brand new to ajax. My problem is, I have a php application using several jquery effects. I've just started learning ajax and it is going really well, this stuff is incredible! But all the ajax loaded data loses the jquery effects. I get that it is a DOM issue, and I've seen that others have used "live" (i think?) to fix this, but I honestly just have no understanding of how toimplementanything that I'm seeing.
This is part of my ajax...
And this is the main effect I need to get working.
