JQuery :: How To Send Simply Variable Outside Function

Oct 4, 2011

As it is shown in line 2 does everything perfectly, but I must declare the variable outside the function, as it implies the following code (line 1).
marcel
var
wert = "text";
$('#bChange'
).click(function() {
$.ajax({
url:"content/nextpage.php",
type:"POST",
timeout: 5000,
dataType:'html',
cache:false,
data: { rNeuRecht: wert },
success:function
(msg){
$("#leer").html(msg);
}});});
$('#bChange'
).click(function () {
$.ajax({
url:"content/nextpage.php",
type:"POST",
timeout: 5000,
dataType:'html',
cache:false,
data: { rNeuRecht: "text" },
success:function
(msg){
$("#leer"
).html(msg);
}});});

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