I'm trying to selectively hide and show divs based on what a user specifies using three select boxes in a form. I'm probably missing something obvious, but here's what I've got and it doesn't, work, they divs just stay hidden.
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
[Code].....
how can I show / hide the content of sub divs based on whether the input is != or = and be able to repeat this.I tried to hide the sub divs using , onclick if bla bla = '' ;document.getElementById('hideme').innerHTML = ''; which works, but once I try to enter a new input, then nothing happens, even if the content of the sub divs is = input.
View 2 Replies View RelatedThe two page sections you see on the page "One Time Gift" or "Monthly Subscription" are normally hidden via a document.write via a body onload. Generally, all of this functions well. But, I want to expand the use a bit here so I want to pass a $_POST value to this page from another page which hides or shows these two sections based on this passed value. So, if the value in "once", I want the div with the id="onetime" to be visible and the other div to be hidden. If the value is "monthly", then the opposite would happen. Now this is supposed to all happen as the page loads because we are just arrivng here from the sending page.
View 9 Replies View RelatedI'm having some issues with showing / hiding divs in a form based on radio button input. I'm fairly new to JavaScript so I'm still not 100% on what I'm doing... I have a pretty extensive form with quite a few container divs that are set initially to "display: none" and I need them to be set to "display:block" dependent on radio button input.
For this piece, I need the div with id "SFSCPROJSPONCOMP" to be displayed when the user selects the Radio button with name "PROJSPON" and value "COMP".If someone could provide me with JS code for that example, I can get through the rest of this form with ease.
I am going to achieve something like this.
<div id="sidebar">
<div id="html1"><h2>Test 1</h2></div>
<div id="html2"><h2>a1 tes2</h2></div>
<div id="html3"><h2>a2 tes3</h2></div>
</div>
The thing is that first I need to detect if the div id is "sidebar" if its "sidebar" then it will pickup all the text inside h2 tag and will search for a1 or a2 in the text.If a1 is found then it will pickup the id html2 and make this div only visible.So in this case it will pickup id html2 and make it visible while other ids like html1 and html3 will be hidden.
Using jQuery, the hide show part is easy. I need to show or hide a single section of a form based on the value of a select box. More specifically, if the select box is one of 30 countries, then show, else hide.
What's the easiest way to handle this?
I'm doing a page w/lots of divs that I set to visibile or hidden dynamically using getElementById.. the divs are all forms... sometimes elements in a hidden form show thru on a visible form.. how can I fix this..
View 5 Replies View RelatedI am creating a form that you don't actually submit in order to allow people to download files. You select different options with radio buttons and drop-down menus and then use that information to "show/hide" divs with javascript. That part works, but if the user leaves the page and then comes back, the data can be somewhat misleading. One radio button may be checked, but the corresponding div that was showing before you left the page is not (it was set to "display:block;" in css with the "onclick" or "onchange" depending on which choice on the form caused it to appear). I know that I need to set a session cookie to save the values on the form, but it is a bit more complicated because I need to set divs to "display:block;" or "display:none;" depending on what the values of the form fields are. I'm a novice at javascript. Since I am not submitting the form, I can"t use PHP.
View 9 Replies View RelatedI'm trying to get my form to show and hide various divs with radio buttons. There are multiple options in the second box of my example. When a user selects the first option, more input boxes come up. Perfect, that's what I want. However, if they decide they didn't mean to click that option and instead wanted another option, the original part that popped up doesn't disappear. I cannot figure out how to make this happen.
View 6 Replies View RelatedI have a set of radio buttons on my pricing page:
And a corresponding text_field input element div I'd like to display based on which radio button the user selects:
When the page loads, I'd like to see:
When the user clicks on a (different) radio button, or clicks one for the first time, I'd like whichever div is currently showing to be hidden, and the newly selected one to be shown.
Right now I have jQuery code at the bottom of my page that looks like this:
For each of the four options.
When the page loads, the correct div is shown, and when I select a new button, the new div is shown, but the already showing one isn't hidden.
I've read some posts that suggest using change() instead of click(), but others indicate that's problematic in IE.
I am building a large registration form. In this form, a sponsor/educator must register himself or herself and then may add up to 6 more " delegates" in pairs. The first two pairs registration info on the form is shown by default. I need to hide the other two pairs until when/if the user clicks on a button to add two more delegates at a time. I used javascript to show or hide the parts of the form that I had put into two divs and adjusted the css display attribute. However, my problem was that, if the user filled out the sponsor/educator section and the first two delegates, and then decided to add two more, when the user clicked on the button to show the part of the form for delegates 3 and 4, it reset all the previous visible form fields to empty. Not good. So, I thought, maybe AJAX.
I created the request object (I am a relative novice at AJAX), had it grab a text file with the code to insert into my target div, in this case a div with id = "delegate3and4". Surprisingly however, it still reset the previous form fields to empty. Am I misunderstanding how AJAX is supposed to work? I figured that, because it does not refresh the page that this would not happen. In fact, to test this out, I created a simple page from scratch with just a single input field and then used AJAX to insert the file in a div after this field and it did not reset the previous input. So, I am totally confused about why this would be happening on my live page. The page is a php page as it submits the form to a php script for processing but I don't think this should make a difference.
I'm looking for some javascript to work with wordpress (jQuery preferrably) that will show/hide multiple divs on one click.
I had one working but it was kinda janky because it was causing me to have two divs with the same ID on one page. No good.
Since I updated to wp2.8.3 prior to launch, it's not working. So I've decided to just try and do it right.
Here's a page: [URL]
So, what I want to happen: On page load, the first tab: "general" and it's corresponding div beneath should be showing. And the first image should be showing. The other content divs and images should be hidden. I've given the text content divs a dashed border to show their borders. When a visitor clicks "dine at home" the general div and image hide, the second content div shows, as does the second image (it's currently the identical image, but the client may change later.) Etc.
I'll be using this function on a few other pages as well.
how to adjust this javascript to work on two different IDs at once?
current code:
Code:
<script type="text/javascript" charset="utf-8">
$(function () {
var tabContainers = $('div.imgswap > div');
[Code]....
I'm trying to get the two followup questions underneath the checkbox to show up only if someone places a check there, but for some reason the way I've got it set up now it's simply hiding the area I want to show up altogether, and the checkbox has no effect on it.
Rather than waste tons of space pasting it here, here's the pastebin: [url]
Alternatively here is the live version:[url]
I'd prefer to have the form collapse when the additional questions are hidden, though if i can get this working at all.
I am setting up a contact form, and want to have a drop down box with a handful of options. Clicking one option should display fields to input username & password, whereas all others will not. So far, I've tried and (replacing 'none with 'block' for the option that is supposed to show the input fields) but neither does what I need it to. I'm fairly new to javascript, just muddling my way through with the aid of tutorials.
View 2 Replies View RelatedI'm trying to show/hide a simple piece of text and a text field on a
form based on what choice is made from a drop down box.
<select name="dropdown" size="1">
<option selected value="">Please make a selection</option>
<option value="1">Choice 1</option>
<option value="2">Choice 2</option>
<option value="3">Choice 3</option>
<option value="4">Other</option>
</select>
i.e. if Choice 2 is selected I'd like to display a new <tr> with the
following:
<tr>
<td>New text field:</td>
<td><input name="newField" type="text size="20"></td>
</tr>
if any other choices are made, I don't want to display anything.
I've tried several onchange() functions but can't achieve what I'm
looking for.
Im using a jQuery script to show/hide a div based based on the selection made via a dropdown.
<script type="text/javascript" src="jquery-1.3.2.min.js"></script>
The problem im having is that the value used in the dropdown lists are price values eg 10.00
Consequently jQuery seems to interprit these as css notations, meaning the code doesnt work.
I have been using a jquery based plug-in, and what i would like to do is degrade it, so a non js enabled browser will hide the relevant div when js is not enabled, and show a different div with appropriate message content.i have followed a couple of tut's which do this on click, but i would like this to occur on page load.
View 2 Replies View RelatedCompletely new to jQuery but I am trying to implement a few pieces on my new website. At the moment I have three images in a row and I want to be able to click on any one of the images and use jQuery to populate a hidden div below the three images that contains more info and slide it out using the fold animation. I'd also like it if when a second image was clicked it closed the currently open div and opened the new one. I've seen tutorials that open the divs but can't find one that closes them again on opening a new one.
Can anyone point me to a tutorial that does this or suggest how it could be done?
I have a site with a lot of small div-boxes (with images and movieswithin them)they are positioned with CSS and float:left.i created buttons, which show and hide either all images or all moviesthis works well.but when i switch between these options, the float-position of thedivs goes crazy and every div-container is on one line for itself(instead of 5 on one line)
View 2 Replies View RelatedI have a table with 5 columns, I want to show column by column, first show the 1st column, after 5 seconds hide this column and show the 2nd column, and when I show the 5 column hide this and return to the 1st.All this automatically, without a button click If is more easy with divs I can change this columns for divs
[code]....
I have a jquery function that will show or hide a div id="hide1" based on the result of a select id="ticket1"
$(document).ready(function(){
$('#hide1').hide();
$('#ticket1').change(function(){
if(this.value == 'adult'){$('#hide1').hide();}
[Code]....
It works well! But my script actually clones elements of the form so a user could be selecting adult or child for a number of tickets - ticket1,ticket2,ticket3....
How can I adapt that script so that it will show/hide for each ticket
I'm currently programming a website and we wanted to have Jquery on it. This is my first real foray into Jquery (other than occasionally using a plugin here and there) so I'm a bit confused as to why what is happening is happening.
The idea is to have 3 different things going on: At the top of the website we want rotating ads. When one of them is clicked, it opens a video file in Lightbox style (darkens the BG) 3 rotating banners below that, when clicked they just go to a website 3 more buttons with play buttons in the corners. When the play button is clicked, a video player takes over the button and plays the video. So far I have the 2nd and 3rd one working. The video player works, the Jquery shows and hides the divs appropriately, and the rotating banners work great.
[Code]...
I have a little issue with trying to hide / show multiple divs on my page. I am using a class name for the divs but the name is generated by a field have set in my database. So for example
<div class="General">Ttitle 1</div>
<div class="General">Ttitle 2</div>
<div class="General">Ttitle 3</div>
<!-- and my link is -->
<a href="#" class="toggle" title="General">Toggle 1</a>
And then say I have
<div class="Questions">Ttitle 1</div>
<div class="
Questions ">Ttitle 2</div>
<div class="
Questions ">Ttitle 3</div>
<!-- and my link is --><a href="#" class="toggle" title="
Questions ">Toggle 2</a>
What would be the easiest way or the best way to code out the jquery to hide / show all the divs with the same name as the links title i can do code jquery to toggle 1 div but not sure how to code it so that it will hide / show all the divs with the same class name.
Is there a way I can simplify my code below? I want to be able to have just one iteration of the code and have it automatically switch out the IDs without have to add a new bit of JavaScript with each new div that is added. Here's my Javascript:
$(document).ready(function() {
// toggles the personnel window on clicking the image/header
$('div.title'+'#one').click(function() {
[code]....
I am new to jquery and need some help with this I have the following simplified html
[Code]...
I have 2 divs: <div id="box1></div> and <div id="box2></div> I also have one link to contoll them both. The effect I want to get is: when I click first time on my link box2 hides, when i click second time also box1 hides, when I click third time both divs should show. I manage to do that both divs hiding but later I can't get the show. Im trying sth like this:
$(document).ready(function() {
$('.slick-hide').click(function() {
$('#box2').hide('fast');
$('.slick-hide').click(function() {
$('#box1').hide('fast');
$(".slick-hide").removeClass("slick-hide").addClass("slick-show");
$('.slick-show').click(function() {
[Code]...