$
"a.mSelect"
.hover
function
{
var month = $
[Code]...
I have multiple div's acting as buttons, when you over over them it will show the respected div, but I would like this respected div to stay visible until the user hovers over another div button In the
How can we show or hide a div on mouse over and mouseout. For the example below When we mouse over to the div1, div2 should be shown and div1 should be hide and vice versa.
E.g.:
<html>
<body>
<div id="div1">
div 1 content goes here....
</div>
<div id="2">
div2 content goes here.........
</div>
</body>
</html>.
i would like to show a div on mouseover via toggle and change it back on mouseout. right now my code looks like this:
$(".#image").mouseover(function(){
$(this).next("#posts").fadeToggle(200)
return false;
});
it works on mouseover but i have no about the mouseout part.
I have this piece of HTML code:
Code:
<ul>
<li>Cat 1
<div class="actions">Edit | Delete</div>
<ul>
<li>SubCat 1
[Code]...
This is what my code is supposed to do:
1. create a select list that changes the photo showing, (which I have)
2. create script so that when the user hovers over the image it shows a div
3. when the users mouse is off the image/div shows the coordinates where it last left
4. on mouseout hides the div again (this is the part I'm stuck on)
This is my html:
<style>
#selectdiv
{
position:absolute;
left:10px;
top:10px;
[Code]...
I am a newbie on jQuery. I work on a project which will allow to find a room in a building. On the left of the page there is a plan of the floor, and on the right, a list of the rooms coming from a database. Every room is a link and when the mouse rolls over the link, the room is highlighted on the plan.
I use this function :
$('#link_1').mouseover(function(e) {
$('#sal_1').mouseover();}).mouseout(function(e) {
$('#sal_1').mouseout();}).click(function(e) { e.preventDefault(); });
$('#link_2').mouseover(function(e) {
$('#sal_2').mouseover();}).mouseout(function(e) {
$('#sal_2').mouseout();}).click(function(e) { e.preventDefault(); });
$('#link_3').mouseover(function(e) {
$('#sal_3').mouseover();}).mouseout(function(e) {
$('#sal_3').mouseout();}).click(function(e) { e.preventDefault(); });
But as far as I don't know how many rooms I have, I would like to use it in a loop, something like that :
var indTab = 1;
$('#link_'+indTab).mouseover(function(e) {
$('#sal_'+indTab).mouseover();}).mouseout(function(e) {
$('#sal_'+indTab).mouseout();}).click(function(e) { e.preventDefault(); });
indTab++;
It doesn't work like that. A second idea is to use .each()
$("[id^=link_]").each( function() { // all the id's starting with link_
$('#link_'+indTab).mouseover(function(e) {
$('#sal_'+indTab).mouseover();}).mouseout(function(e) {
$('#sal_'+indTab).mouseout();}).click(function(e) { e.preventDefault(); });
});
No success.
This code is working perfect to mouseover:
$(document).ready(function() {
$("#main ul li").hover(function(){
var fade = $('img.g-img', this);
fade.fadeTo('slow', 0.5);
$("#main ul li").removeClass("active");
$(this).toggleClass("active");
});
});
But what about mouseout? I want to remove effect like "removeEventListener" in as 3.0, How can I do this?
i have a problem in mouseover and mouseout events.when the mouse is on the image a div will show,but when mouse is on that shown div something loops happened.Here is the working example:Jsfiddle
View 2 Replies View RelatedIt appears I can not put a mouseover and mouseout even on the same element. Which I find very strange because css can do it. why cant jquery ? What I am doing is enabling and disabling a textfield based on whether the mouse is over or off the textfield. if its over, its disabled, if its out then its enabled. Is this possible ?
[Code]...
I have a series of slideshows on a single page. They activate (independently) on mouseover.
At present, the slideshows pause on mouseout.I would like for each of them to return (paused) to the first slide instead. Ideally this return to the first slide would also be a fade transition.
The code in place at the moment is as follows:
<script src="/scripts/js/jquery.cycle.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('div.gallery').cycle({
[Code].....
What is the proper technique to hide a flyout menu on mouseout? Note that it should not disappear if the user continues to hover over it's corresponding menu tab.
Some ideas:
1. I remember seeing a post about this fromkboudloche, but can't find it for the life of me. He selected the whole document, and then filtered out the menus, and hid the flyout on a mousein event. Something like that.
2. I have a parent div that contains both the menu tab and its flyout. I tried hiding the flyout on a mouseout of that div, but to no avail.
3. Some sort of nested check; e.g.:
If mouseout of flyout area...
If mouseout of menu tab...
Hide flyout
4. Selecting the document body, and then using not() or filter() to remove the flyout and tab, and binding a mouseover -> hide flyoutevent to this selection.
How can ignore queuing in mouseover/mouseout in such codes like this:
I dont want cubes blink N times when the user does mouseover/out N times.
I want to animate the menu 'height' on mouseout (it works fine on mouseover) - basically a slide up/slide-down effect.
View 5 Replies View RelatedIs it possible to animate the Superfish menu on mouseout (like a slidedown/slideup animation)? I only manage to get the animation on hover/mouseover to run (using 'height').
View 1 Replies View RelatedThis should be the easiest thing in the world - set a background image for a div on mouseover. I'm working on a color picker for a clothing store. The customer can choose any of 20 colors. The colors are represented on screen by 20 tiny divs, each with a background color. When the customer wants to see a particular color variation, for the clothing, they mouse over the div with that color. A background image is then set that highlights that div, showing it is choosen. This background image should remain till another color div is mouseover-ed. The image appears on hover, then disappears on mouseout. I can not figure out why it disappears on mouseout. I've tried several variations of the following jQuery code, but the back ground image still disappears on mouseout. I also removed the background image from the hover rule in the style sheet - it made no difference.
// 04-24-09 - the little color divs have this styling:
//
// div.color-row div:hover{
// background: url(../img/bg-color.gif) no-repeat;
[Code].....
I have a mouseover part, but it (when it complete the mouseover action) also execute the mouseout actions, which is not supposed to happen.
My code:
$('#navigation li').live({
mouseover: function()
{
$(this).animate(
[Code]....
since it is not supposed to execute the mouseout actions when going mouseover.
I'm having issues with the animate procedure in jQuery. I should start by saying that while I am not new to web developement and scripting, I am fairly new to jQuery so this may be fairly elementry to some of you pros out there.
Basically what I am doing is I have an image map with hot spots, when you mouse over a hot spot, another image (an enlarged version of the hot spot) appears (fading in and growing) and then disappearing on mouse out (fading out and shrinking). My problem is odd because it does not happen every time, but "sometimes" when you mouse over the first animation (grown and fade in) will run then second will run (shrink and fade out) and then repeat until you click outside of the hot spot and the popped-up image. I've noticed the problem mainly occurrs in Firefox (3.5) and rarely or never in IE (8) and Chrome (2).
[Code]...
I am using the fade in and fade out and mouse over and mouse out. What I am doing is creating a menu that fades in when the mouse if over the users image. The problem I run into is that when the background of the menu fades in with the buttons which are links. I notice that if you move the mouse over the buttons/links the menu and buttons fade out.I have 2 elements one is the menus background and the other element is the buttons/links on top of the background.
I have a fade out command when the mouse it off the menu background. So I am guessing when the mouse goes over the links/buttons it acts as if the mouse isn't no longer over the menu background element causing a fade out effect. What can I do to prevent the menu fading out when the mouse is over the buttons that are links. I want the users to be able to put their mouses on the buttons and be able to click on the buttons without the menu fading out but only fade out if the mouse is not longer on the background of the menu and is not over any of the buttons on the menus background.
I was woundering if I should do a if statement to check the conditions which would be where the mouse is over. If the mouse is over either the menu background meaning the menu or is over the buttons on the menu background meaning the opitions in the menu. Then don't do a fade out only do a fade out if the mouse is not over either the buttons or the menu itself.
I have some simple code to add and remove a class when an li element is hovered.
$("#nav li").hover(
function(event) {
$(this).addClass("hovered");
[Code]....
The hovered class just adds a background image. When I quickly hover over the list, sometimes the background image gets stuck so it seems like the "hovered" class never gets removed.
I have the simple script below, mouseover works, but mouseout dosen't. Have tried with mouseenter/mouseleave also, mouseleave dosen't work either.
$(document).ready(function () {
$('.nav').mouseover(function () {
$(this).removeClass('nav');
$(this).addClass('navactive');
})
$('.navactive').mouseout(function () {
$(this).removeClass('navactive');
$(this).addClass('nav');
})});
I would like to write a jquery function that will work like this:
$(document).ready(function(){ifclick is made then do:
$("#wheel1").click(function(){ $(".wheels").show(500);});
leave the function
else:$("#wheel1").mouseover(function(){ $(".wheels").show(500);});
$("#wheel1").mouseout(function(){ $(".wheels").hide(500);});
I am trying to build this page where there are 3 levels of icons/contents. When user hovers on 1st level, they see the 2nd level. They now hovers on the second level and suppossed to get the 3rd levels of contents.My 1st/2nd levels worked fine.But when I added the 3rd level, could not make them to work.Problems: 1. the 2nd levels show up with multiple 3rd level items - suppossed to be all hidden.2. When I hover over the 2nd level - they are like frozen if the 3rd level is displayed. After hiding all the 3rd levels by doing mouseout - when I hover over a 2nd level, 3rd level shows up but when I move over to the next (2nd level), the corresponding 3rd level shows up without hiding the previous one. So again - displays multiple 3rd level items
var cr_event = $('#imgCE');
var info_center = $('#imgIC');
var tab_events = $('#tabCreateEvent');
[code]....
I am building some video player controls and when I mouse over/out the volume icon, I want the volume slider to appear and disappear. On the mouseout, I want it delayed so what I did was this:
$("#mutebtn").mouseover(
function() {
$("#slider").fadeTo("fast",1);
});
$("#mutebtn").mouseout(
function(){
$("#slider").fadeTo("fast",0).delay(2000);
});
It delays but it puts the delay on the mouseover. So naturally I put the delay on the mouseover and then the delay was on the mouseout which is the correct behavior.
I added mouse in and mouse out affect like this in $
(document).ready function
$(document).ready(function(){
....
$(".StripMe tr").mouseover(function(){
[Code].....
My question is if i used jquery post method to change some div content, than this new div won't have mouseover and mouseout affect anymore, is there anyway to achieve it. Is that needed to trigger ready function again? Another question is can anyone teach me how to add click and dblclick event to the same div, because if i add both of them then it won't trigger dblckick event.
How do you hide a div on mouse out. I have a flash button that unhides the div and I want to hide it when the user's mouse is out of the boundaries of the div.
[URL]
here's the java to unhide it
Code Java:
<script type="text/javascript">
function unhide(divID) {
var item = document.getElementById(divID);
[Code]....
I have a function that is activated by a mouseover. The function
triggers an image rotation. I need to stop the rotation on the
mouseout but I don't know how to do this. the mouseover triggers the
rotate() function below. currently the mouseout produces the default
image but then it keeps cycling the other images.
<script language="javascript" type="text/javascript">
if(document.images) {
bubbles = new Image
off = new Image
bubbles.src = "images/bubbles.jpg"
off.src = "default.jpg"
}
else {
bubbles = ""
off = ""
}
adImages = new Array("images/whitemarble.jpg", "images/bubbles.jpg",
"images/oak.jpg")
thisAd = 0
imgCt = adImages.length
function rotate() {
if (document.images) {
thisAd++
if(thisAd == imgCt) {
thisAd = 0
}
document.ImgField.src=adImages[thisAd]
setTimeout("rotate()", 3 * 1000)
}
}
</script>
