I've got a demo out on URL...As shown I want to show a .div while hovering over another .div.Everything seems to work except for the fact that it doesn't work properly.The .div that's getting shown on hover keeps getting reset when moving the mouse over the hover .div.Try the example for yourself and you'll instantly see what's wrong. I want that fixed but how.
View 1 RepliesI want to create a webpage that has a grid of 8 images displayed on the left side of the page. All the images are "dimmed" by default and when the user moves their mouse over an image, it lightens to its normal state. What I want to do is when they hover the mouse over an image, display a chunk of text in thearea to theright of the image grid. Essentially, the images act as a kind of menu and when the mouse hovers I want some details to be displayed. Ideally, I want to format the text to make it look good - so am not sure if it would be better to create an image containing my text and display this image when the mouse hovers.
View 4 Replies View RelatedI'm trying to make script that displays a tooltip when you hover over something, like a link. But it doesn't work and I have no idea why.
This is my script:
set the function that will draw the tooltip
function tooltip(header, content, w, h) {
get the tooltip element
var tooltip = document.getElementById('tooltip');
set the browser variable
var browser;
check what browser the use is using
if (document.all) browser = 'ie'; Internet Explorer
else if(document.layers) browser = 'ns4'; Netscape 4+
else if(window.navigator.userAgent.toLowerCase().match('gecko')) browser = 'gecko'; Mozilla
set the mouse coordinates
var x = event.clientX;
var y = event.clientY;
change the tooltip's width
tooltip.style.width = w;
change the tooltip's height
tooltip.style.height = h;
check if the header is empty
if (header.length = 0) header = 'Help';
change the content in the tooltip
tooltip.innerHTML = header + '<br>' + content;
change the visibility
tooltip.style.visibility = 'visible';
set where to draw the tooltip
tooltip.style.position = 'absolute';
tooltip.style.top = y;
tooltip.style.left = x;
tooltip.style.zIndex = 9999999;
} set the function that hides the tooltip
function hide_tooltip() {
get the element
var tooltip = document.getElementById('tooltip');
hide the tooltip
tooltip.style.visibility = 'hidden';
}
This how I'm using it on link:
<a href='java script: void(0)' onmouseover='tooltip("","This is a tooltip",100,50)' onmouseout='hide_tooltip()'>?</a>
Umm, this is a tricky one to add a descriptive title for!
Basically I have two links on the page that go to the same page when clicked. What I want to do is when I hover over one of those links for the hover to work for both of them and visa versa.
So I have this links
<a class="connected" href="">Connected</a>
<a class="remove" href="">Remove</a>
a.connected { background: url(../images/connected.png) no-repeat 0 top; }
a.connected:hover { background: url(../images/connected.png) no-repeat 0 bottom; }
[Code]....
I am doing:
And i see the datepicker in chrome's inspect element, but it is not showing on the screen
How to take the numerical output from a function, and display it in an id—as in:
function Ran() {
var r = Math.random();
if (r < 0.5) return 0; else return 1;
// export 'return' to <span id="#myid">
[Code]....
i am pretty new to jquery and hope this is the right place to ask. my problem is the following. when i mouseover a certain element on a page, i want that a certain image is displayed in the top right corner of the page, no matter where the it is currently scrolled. how can i achieve that?
View 1 Replies View RelatedI am using the Superfish Module and have been able to successfully install and use it. The problem I am having is that the sub menus are being drawn behind the banner / header area and therefore you are not able to see them or click on them.
Please let me know whether to change the index.php or .css file to see
the drop down menus properly. Following are details you might need [code]...
I'm fairly new to JQuery and am trying to get my menus to load all the images before it tries to fade in. I am passing categoryid to an external php page which gets the relevant data from the database, and then displays it in the right div element.
[Code]...
var array = result.sCitizenship.split(','); //array[0] = 1, array[1] = 2
$("#citizenship").val(array);
multiple select is not displaying .....
echo '<tr><td>'.lit($inv['id'],1,0).'</td><td><select id="target'.$inv['id'].'"><option>Choose An Action</option>';
echo '<option value=enhance>Enhance</option><option value=slot>Slot</option><option
[code].....
(I have tightened up my original example) I'm trying to invoke modal dialogs from within a tabbed UI, and I'm confused about the behavior I'm seeing. The first time I display the UI, my dialog behaves as expected, I can pull the data out of the fields, everything's wonderful.
[Code]....
I have been googling around about this for quite awhile without any definite answer. Here is the code I am having a problem with:
var $m = {'id1':'page1.html','id2':'page2.html'};
/* load modules */
$j.each($m, function($key, $value){
$j('#'+$key).html($loading);
$j.ajax({
url:'proxy.php',
type:'post',
data:'module='+$value,
context:$j('#'+$key),
dataType:'html',
success: function($response){
$j('#'+$key).html($response);
}});});
The problem is that the second XMLHttpRequest response does not get displayed. If using firebug for debugging you can see that two separate responses are returned from the server both with the correct HTML data. The first item gets displayed on the page however the second item never gets displayed. Some of the things I have read when searching for similar problems indicate a problem with the div id changing prior to the success callback.
I am totalynew to jQuery, and i want to do the following on a website: Load the full page - wait a few seconds -fadein a DIV with a slideshow. I tried the following code, but somewhere there must be a big, big bug in my code. Idid not tryto build in the fadein of the DIV.
[Code]...
I have a form that has parts seperated with the use of the jquery tabs. One thing i have noticed is that if i use <cfinput> to create the inputs that they do not get displayed, the only way i can get them to display is to use regular <input> tags; does anyone know why this is?
View 1 Replies View RelatedWhen you click the text "info" in the column "comments", a row should be displayed below with text information that is related to the "comments". Need also to click the text "Info" again to hide the text information of comments. Problem: I don't know how to display the row when you click one of the comments with the text "info". When clicking one of the link the remaining rows with the text "info" should not be affected. In order words, the part should be independent Need also some help hiding the text information of comments.
There are some things that you also need to take account to: - The amount of data that will be displayed in the table will be changed from day to day. The data is taken from a xml file.- Would like the sourcode to be written in jQuery.- Only html, css and javascript is allowed in this context.- html code in tr and td will be generated by javscript code.The class "firstDataRow" is the added in the tr row that has the text information of commentsPlease remember that the text hide and show is only for temporary.
// Fullmetalboy
<table border="1" SUMMARY="aaa" id="tblProject">
<thead>
[code]....
I'm a complete newbie to JSON and I'm trying to make some sense out of itI think that what I want to achieve is fairly basic, but I have no clue where to begin. Here's my problem:I want to get the information from this JSON-string, fetch the value for realm_rank and display it within a header-tag in my html-code.
View 9 Replies View RelatedGetting myself back into jQuery and have an issue which I didn't previously fix, and was wondering if anyone would be able to assist me. I have multiple DIVs (up to 50 on one page) that I wish to individually be able to hide and close an extra DIV once pressing the 'Details' to show, and 'Hide' to hide the extra hidden DIV.
[Code]...
I made a quote slider on a website im helping build, it works in Firefox, but not Chrome or IE,below is a link to the site, and also my code.
<script language="javascript" type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"</script>
<script language="javascript">
[code]....
I am loading the array data into jqgrid ,but it is giving some errors . point out the mistake in the code.
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>jqGrid Demos</title>
<script src="js/jquery.jqGrid.js" type="text/javascript"></script>
[Code].....
drop shadow not displaying right in certain browsers?
View 2 Replies View Related1) I have a series of divs embedded into a page, sort of like an FAQ setup. Each has a unique id like id="service1" etc.
2) i'm using an unordered list with each li being a hyperlink to the div id's
3) the div's are set up as name anchors ( <a name="service1">Service One</a. ) so I can hyperlink to them via the <a href="#service1">Service One</a> method
4) There's 22 divs and they need to be hidden until summoned. Therefore, I set $('.service').hide(); to make them all disappear.
Now, where i'm stuck is in how to summon them individually and have them appear when the appropriate list hyperlink is clicked. I'm using:
$('.servicelist a').click(function() {
var toLoad = $(this).attr('href');
}
So it's telling it to load the info found at the appropriate link. This is where i'm stuck. I need help on
1) how to 'unhide' the proper div id containing the related data
2) how to point it to the right location in the page (target div)
I want to do is let the user input a file,then read the contents send it to the server, loop over the inputs to query MySQL, return the results and display it in a user friendly,scrollable table?
View 1 Replies View RelatedI have enabled a hover() event on a DIV that includes an H2 element that is always displayed and a child DIV that needs to be shown/hidden. This code works wonderfully on Firefox and IE. However, it's not working in Safari (I have not tested Opera or Chrome yet)Here's my (very simple) code:
jQuery("div.category-text").css("display","none");
jQuery("div.category-item").hover(
function() {
[code].....
I really like the following code example from Scott Robbin, allowing me to slide pages in and out of the screen, however I wanted to slide in some DHTML from here:[URl].. ...but, at best, only the images show. Well they don't, I've even tried hard linking to them. I know the links are valid because opening the page on its own they all show up, so there's an incompatibility somewhere.
[Code]..
I have a form that asynchronously submits to a PHP file. The PHP file returns the following:
PHP Code:
echo�json_encode($array);
In my Console, I see the following:
Response:
{"groupname":"XYZ Group","id":4}
How do I display that JSON code through jQuery code?
Here's the jQuery code I have so far:
Code:
$.post("addgroup.php", { groupname:f.groupname },
function(data){
$("#groups tr:last")
.clone(true)
.insertAfter("#groups tr:last")
.html("<td class='tbldata'>"+ /* Returned JSON data (groupname) */ +"</td><td class='tbldata'> /* Returned JSON data (id) */ </td>");