Hide Div So Content Won't Be Loaded Until He Is Visible?
Nov 29, 2010"How to hide div so his content won't be loaded until he is visible?"
And is it possible to add preloader for that div?
"How to hide div so his content won't be loaded until he is visible?"
And is it possible to add preloader for that div?
This is the Javascript function that I use to hide/show DIV content. I use it everywhere without problems:
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However, I get strange behavior when the above DIV is located within an AJAX response. My main page loads another HTML page into a div, and within THAT div is the "div6" above.
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which works once the page hasn't been loaded using.load $(".toggle_cat_container").hide(); How do I adapt it to work when the page is loaded with .load? I am familiar with needing to use .live on click functions.
i.e.
$("a[id^='mydiv']").click(function(e) {
needing to be changed to:
$("a[id^='mydiv]").live('click', function(e) {
My problem is that $(".toggle_cat_container").hide(); would trigger when the document was ready but when its loaded it won't trigger. What adaptation do I need? I suspect something similar to the below - just not getting it right $(".toggle_cat_container").live('onLoad', function(e) {
I have the following code that don't work like i want it.
Code:
function hideDisplaySingleSuite(textstring) {
var myclass1 = new RegExp('\b'+textstring+'\b');
//Populate the array with all the page tags[code]....
For example.It show objects if I remove the if statement that checks if the class is visible.for example this shows a class and works.
Code:
function hideDisplaySingleSuite(textstring) {
var myclass1 = new RegExp('\b'+textstring+'\b');
//Populate the array with all the page tags[code]....
So my question is why don't this work on a class, it works on an "id"?
Code:
if (allPageTags[i].style.display ==''){
allPageTags[i].style.display = 'none';
}[code]....
I want to show the class if its not visible or hide it if it is visible.How can this be done?
I have loaded DIVs that by default should be hidden as the page loads. The problem is that the content is visible while it is loading and after it has finished loading, the DIVs set themselves as hidden. Is there a way to set this script so that the content is not visible for those first few seconds?
View 4 Replies View RelatedHow can I generate a visible content from an invisible iframe?I'm working on a project which involves scanning of content posted through HTTP.For example, a file uploaded to some web-mail client (i.e. Hotmail) as an attachment. If the file is suspected to be a virus, the user should informed and asked whether he wishes to post the file anyway. This scan is made before the file is sent to the server.The message should come from the browser (like JS alert box) but should contain some arbitrary HTML code, not supported by alert box.
Normally, when a file is uploaded, it is done in some hidden iframe. When the upload finishes, the server replies with JavaScript code which when run, notifies the user the upload is done.To inform the user he is uploading a Virus, I'm altering the server's reply to the HTTP post. The altered reply is a JavaScript code which generates some custom dialog box.
The problem is, the page is returned to some invisible iframe, which means the generated dialog box is also invisible. Simple JavaScript alert box works fine as it comes from the browser, and not as part of a webpage. how I can generate a visible dialog boxes, from the hidden iframe?
I'm trying to debug a tabbed menu implementation, where I have a variety of pages that are made visible based on tab clicks. This works well, until I have a page that is laid out with nested divs. Any content beyond the child of the selected page (page_about shows 'Put an image here' but not 'This is where...') remains invisible. I've tried a number of options in the slideDown statement, but failed thus far.
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I have a div tag element and a hide/show button above it. I'm able to handle the hide show of the contents all right via the button, but I want the div to be hidden when someone clicks anywhere else in the document, save inside the div area itself.This functionality is similar to what you see on the sign on panel in twitter.com. Press the sign in, the div sign in panel displays. Press the sign in link OR anywhere else on the document outside the panel. The panel is hidden.What's the best way to script this functionality in jquery?
View 1 Replies View RelatedI am implementing some tabs using jquery and have run into a problem where a google map on one of the tabs is not displaying. I read that a solution is to "Use the off-left technique for hiding inactive tab panels"i.e
Code:
.ui-tabs .ui-tabs-hide {
position: absolute;
left: -10000px;
}
how the hide method is currently hiding the tab contents. i.e how does the hide() method hide the tabbed content?
I created a slideshow using the cycle-lite pluginLINK. LINK TO SLIDESHOW The slideshow is nearly great. The first time you load the images it is a bit bizarre. The images loads and fades at the same time.
Is there a way i can hide the images until all has loaded then trigger the slideshow.
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I am loading some content dynamically using the .load() function in jQuery.So once the content is loaded, div#slider moves to reveal the new content. The div will move once all the text is loaded but not the images, which is fine. The images will be loading when the viewer first clicks on a.load-button.What I'd like to do is to hide the image until it is fully loaded into the cache, have an animated 'loading' gif as a background image, then BOOM, the image appears in one go with .show();I'm a little unsure how to approach this, since I'm already using the .load() callback function. I've tried using $(window).load(function(show image)), but jQuery dosen't like that.
View 6 Replies View RelatedI am absolute javascipt newbie so please threat me like that I need the following functionality to my webpage: Let's say I have a div with some unique ID on my page. Now, what I need is to show this div on my page only the first time visitor opens a page, and then not show it every next time he/she opens it for next 24h.
So I need to set a cookie that hides div from page if it has already been shown to visitor, for next 24h,so that the content of this div will be shown to each unique visitor only once for a day.
I have a set of divs on my portfolio page that all share the common class 'module', with an additional class that determines the background image.I currently have this function that I thought would keep each instance of .module hidden until it had loaded:
$('.module').ready(function(){
$('.module').fadeIn('9000');
});
I'm not certain but I think the 'ready' only refers to the HTML content and ignores the fact that the background image (defined in css) isn't ready.Is there any simple way I can make each div stay hidden until the background is loaded, then perform show() or fadeIn()???
The page in question can be found at http:[url]....
I'm working on an embedded device and I want to display only part of the original configuration page by building a jQuery page on top of it. Unfortunately, the code that generated the pages was not ajax friendly in the sense that the only way I have to identify the parts I want to show or hide is the class attribute. Up to now, I've been able to load the page with the simple code:
<div class='contentcontainer'>
<hr> <div id="content">
</div>
</div> <script type='text/javascript'>
[Code].....
But it doesn't work. Then I read on the [URL] that I would need to wrap it:
Chris Moore
9 months ago
If you want to load some content into a div and then manipulate it afterwards ((ie: loading something your use a template for a message window and then want to change the message contents) you *must* do it by wrapping it in the completed function handler..
Don't just throw it a few lines down, you'll get random chances that the selector will
how I should do this? Do I need to replace the test() function by a function that will do the post treatment? How then?
I'm using a double background image for a site - basically two containers around everything, one with a gif with patches of different colour, and above it a semi-opaque png with a very faint texture. I'm doing it this way as it makes for much faster loading than one jpg with the image and texture combined.
The only problem is that you see the gif load first, then the texture goes over it. Is there any way, perhaps with JS, to hide these background images until they're both fully loaded, then display them together?
I'm creating a site that uses AJAX to create a "page flipping" type effect. So it works kind of like an FRAME, where when links, etc. are clicked just the main content area is reloaded using JQuery AJAX.
The problem is that that content seems not to pick up the CSS stylesheet rules. I have to press refresh before it loads the styles.
I have a script that takes longer to load than the page, so I would like to have it say "Loading - please wait!" until the script has loaded. I don't want it to hide the entire page - just this one script.Up until recently, I had no idea as to what ajax was, or what it did, so I surely am unable to do this.
View 3 Replies View RelatedI have a form with three fields. When the user changes the value of field1, the form displays either field2 or field3. This works fine for NEW records.However, I'm running into a problem when trying to EDIT an existing record. When the form is loaded, I need to test the value of field1 and display either field2 or field3. I've tried using the form onload event, but do not know how to access the value of field1.I'm using Javascript and div tags.This is what I have so far.
<script type="text/javascript">
function hide(obj)
obj1 = document.getElementById(obj);
[code]....
I have loaded a fragment into a div using the .load function. Is it possible to access the newly loaded content for editing?
$("#outfitTopDesc").load(""+itemTop+" #productTitle, #productDescription, #productPrice");
var linkDiv = document.getElementById("productArticles");
[Code]....
My alert dialog never apears.
I'm trying to bind an event handler to a button in a page loaded via Ajax. This procedure should apply to every page I have to load via Ajax. I have tried two things: first, I declared the 'click' event handler for the button like this, and just did my ajax request. Here's the code:
$("#close_button").click(function(){
alert("This should popup");
});
$.ajax({
url: 'js/ajax/text.html',
[Code]...
what i'm trying to do is to acces the content loaded via AJAX but in an other way than by a callback function.i have a div where the data will be loaded via ajax, the data is represented by a list of folders and when i click one of them i want to load then the subfolders and so on, but if i use the callback function this is not gonna be dynamic..cause i don;t know how deep is gonna be the tree.[code]but if i do in this way....first time it works....so id i click <ahref="folder_1">folder_1</a> it loads the subfolders...and if i click then on of the subfolders loaded with ajax it wont work anymore to see the subfolders in the respective folder.
View 5 Replies View RelatedFor starters i'm new to jquery and javascript, hence my post here. I've tried to do research but I'm not finding the answers. Here is the problem. the web page i'm working on has 2 area's or panes. one that changes dynamically via ajax and one that stays the same to control the dynamic area. The dynamic content is loaded with the following function to load a given page into the <div>.
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When the content is loaded into the div jquery does not work. More specifically i'm using the jquery ui datepicker. The page that is loaded via loadPage() work fine if its not called by the function. but once it is it seems all javascript does not function.
I've got the following code:
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I have question about JQUERY. Im using
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I load content from a separate php page into a div in my other page. This is done using .Get I believe.I've taken the plugin from net tuts +This is working, however, plugins that are supposed to work with the content that's just arrived aren't. Only when specifying that page and loading that as a whole. Long version:I'm doing a website that's pretty graphics intensive. It's more like an application really, only with very "scarse" interface. So I liked the idea of loading only the new content directly onto the already loaded page instead of reloading everything.
And so I found a plugin from net tuts that did the very same thing.Basically, this plugin lets you load content from a said div container directly as a feed onto the page that's already loaded. So all pages are the same, with the only change being in the same div container as all pages have.Now, several issues occurred. What I find strange(probably not for you) is the fact that plugins that I use somehow stop working when loading the content using the said plugin. Cufon stopped working on the newly arrived content. And the same thing happens with a slide menu plugin as well that also arrives with the new content. But if I completely load the page that contains the div with Cufon and the slide menu, everything works as normal. But as soon as I click a link and new content arrives, plugins in that content does not work.
What am I missing? The pages are completely identical, with only a few differences in the a div container that both pages have. Clicking links are supposed to only remove existing content, fetch new content and place it in exactly the same location. One would think that scripts that are already loading in <head> would work with the newly arrived content as well?
I have a page (index.php) with a pictures carousel that works with css and jquery. I want to loaded a new carousel into a <div> after the page is loaded using the $('#mydiv').load('myscript.php') function that calls a php script returning the html code for the carousel, containing a list of images.So I have a <ul> of pictures that doesn't work as a carousel without the CSS and jquery code that has been loaded on the page when my index.php loaded on the first place.So, since the page has already been loaded the carousel doesn't work properly.It seems like the jquery code for the carousel to work, should execute every time I load a new list of images with the load() function.
View 1 Replies View Related