What im trying to do is for each item selected from the drop down, display its value in a text box (GAC). I have attached a picture of the image to clarify.
The drop down items are populated from a database, and each item has an associated GAC value. The remaining inputs are user supplied and all the inputs including the drop down item and its value are is stored in a different table in the database.
I've looked around and from what I can tell, the code seems right. Basically crating a JS array and passing PHP values to it to use in an onChange to fill a text field. The dropdown gets populated fine but the text field does not autopopulate onChange. I'm not too fluent with JS but have a good analytical mind and from what I can see, the logic seems right.
<?php
include('connectdb.php');
$CENTRE = $_SESSION['centreAFB'];
$qryFormList = mysql_query("SELECT * FROM tblLogin WHERE ACCT_TYPE = '2' AND loginCENTRE = '$CENTRE' ORDER BY loginNOM");
echo "<script type='text/javascript'> var formCourriel = new Array()";
while($resFormList = mysql_fetch_assoc($qryFormList))
[Code]....
I have a simple form - I want to disable the text field if Choice 2 from the dropdown menu is selected. I have this working with the code below, but for some reason if I go back and select choice 1 after selecting choice 2 the text field remains disabled. I only want it to be disabled if choice 2 is selected.
View 5 Replies View RelatedI have set up my website quite some time ago that has served its purpose very well, however I will now be adding an order form functionality. So far, by reading books and traversing forums, I have been able to develop a page where the user
1.Enters data into the required fields, that is then submitted to a MYSQL database via PHP,
2.Can retrieve orders that are stored in the database,
3.Delete orders that are stored in the database.
I have wamp installed on my computer as the webserver. I have also incorporated two drop down lists that both retrieve their values from tables within the database. The first drop down list retrieves the Australian States that I have stored in a table, and once the submit button is pressed, it stores the State that is selected to a separate table. This drop down list functions as it should. An extract from "From Place an order.php"
<?php
$dbcnx = @mysql_connect('localhost', 'root', 'tingling');
if (!$dbcnx) {
exit('<p>Unable to connect to the ' .
'database server at this time.</p>');
} .....
The second drop down list retrieves product names from a table that contains products and their prices. What I would like to happen, is that when the product is selected from this drop down list, a text box is automatically filled with its corresponding price. I had this drop down list working as per the "States" drop down list, but could not get it to auto populate the text field. I got some assistance from a friend and was able to get the text box to auto populate with its corresponding price, however when the page was submitted to the database, the "id" number of the product name from the drop down list was stored, and not the product name.
<select name="productSelection" onchange = "getProductDetails(this)">
<option selected value="1product">Select Product</option>
<?php
$products1 = @mysql_query('SELECT * FROM products');
if (!$products1) {
exit('<p>Unable to obtain author list from the database.</p>'); .....
Im using a jQuery script to show/hide a div based based on the selection made via a dropdown.
<script type="text/javascript" src="jquery-1.3.2.min.js"></script>
The problem im having is that the value used in the dropdown lists are price values eg 10.00
Consequently jQuery seems to interprit these as css notations, meaning the code doesnt work.
I have an HTC (Thanks to Beetle) that auto fills a field as a user key strokes letters into a text box. Except for one thing everything works great. The one thing is if a use types somethin in that is found, accepts it (tabs out of the field) the goes back to the first letter and trys to change the case (upper to lower or vise versa) it gets an error "invalid argument". I cannot seem to figure out why it would error. Below I have all of the code HTML and HTC should be easy Code:
View 2 Replies View RelatedI have a text field, call it income, that when the input is > 0 I need to dynamically show the next text box, and if it is blank hide the next text box. I would like to use onBlur but can't seem to get it to work.
View 5 Replies View RelatedI'm developing a web page. It includes 2 text boxes. One text box for city and another text box for std code. I wrote the code for auto suggestion to city. Now i want to pre populate the STD code when ever a known city is selected (when city is selected from the recommendations displayed for city field).
View 8 Replies View RelatedI have a page on which I have 2 dropdowns. Both are similar. I have a piece of code that whill make a textbox appear if we select "list Box" as the option in the drop down. But for some reason, the first dropdown works fine, but for the second dropdown, the textbox is always there on page load. The code that I am presenting can be copied as a HTML page and you will know what I am referring to.
<html>
<script type="text/javascript">
function showfield(name){
if(name=='lstbox')document.getElementById('div1').style.display="block";
else document.getElementById('div1').style.display="none";
}
function hidefield() {
[Code]...
I have a Javascript function that allows the display of a textbox upon selecting an option from a dropdown menu. In my case when a user selects listbox as the option, the text box appears. I want the same thing to happen when another option (checkbox) is selected. when I repeat the JAVAscript code, the first textbox(listbox's textbox) appears irrespective of which option(listbox, checkbox) I select. I want to be able to appear/disappear only the respective textbox. Here is my code.
<html>
<script type="text/javascript" >
function showfield(name){
if(name=='lstbox')document.getElementById('div1').style.display="block";
else document.getElementById('div1').style.display="none";
}
function hidefield() {
[Code]....
I am needing the coding to do the follow:When a user makes a selection from a dropdown, the value is placed in a text input.SELECT >>> INPUT
View 5 Replies View RelatedI have a form that has a pretty complicated combo box - a user starts typing text, it queries a database for matches, and displays the results to the user. The user can then select the match they desire and it has a value id, which I am currently sending to a hidden field in the form. So, for example: user starts typing in a movie name, Seven - it returns Seven and user selects it. The form submits the id of the movie seven (say 12) to a hidden field.
Where I am stumped: Once a user selects a movie title, I have another drop down select box that is to display the available formats of the movie by querying my database based on the product id (12) and returning the available formats in the list:
DVD
BLUERAY
VHS
I am pretty good at programming, but I cannot figure this out - how to make the select box fire and return results once the value for the textbox has been captured.
The specific piece I'm stuck on at the moment is this:I have a form with a lot of fields, two of which are subnet (a drop box populated from a database, via PHP) and IP address (a text input box). When the user selects a subnet, the value is sent to a PHP script that queries the DB and returns the next unused IP address. If all I wanted was to display that in a div next to the IP input box, I'd be set -- that works fine.Unfortunately, I can't for the life of me figure out how to get the returned data into a text input box, which is what I actually want.I know that ocument.getElementById("div_id").innerHTML=request.responseText; will display the text in a div in my sample code. I found a post somewhere that implied that frm.getElementById("input_id").value = request.responseText; would do the job for a text input, but it doesn't, at least in any of the browsers I've tested.
View 1 Replies View Relatedi'm quite new to javascript and have an issue with an image swap script. I have three images that should change based on the value of a text field (total), however, there is only one image that is swapping. Please see the code below:
Code:
<html>
<head>
<script type="text/javascript">
//This is where we decare our function to validate the HTML form
function validateform()
[Code]...
Not exactly sure this is the right forum to post this but just to give it a shot.I am relatively new to programmming...I am currently working on a web appliation using MySQL DB and use PHP/SQL.I have a web form i have created. What i want to achieve is that when a user fills in one of the fields...a text field, i want 8 other fields to be AUTO filled with different values related to the one the user filled in
View 2 Replies View RelatedI have a mysql database (name) which helds 3 fields, id, naam, email. In php I've made the connection and create a selection menu and with javascript I was able to display, (when I selected for example "Bas" in the selection menu), bas his name into a first input text field. Now a couple of things I still want but can't seem to get it right.
First: I also want to display "bas" his email address in a second input text field. (the database contains more names, but this an example).
Second: The selection menu starts with the first name in the database, but can I make it for example "Select name" as beginning.
[Code]...
I'm trying to show/hide a simple piece of text and a text field on a
form based on what choice is made from a drop down box.
<select name="dropdown" size="1">
<option selected value="">Please make a selection</option>
<option value="1">Choice 1</option>
<option value="2">Choice 2</option>
<option value="3">Choice 3</option>
<option value="4">Other</option>
</select>
i.e. if Choice 2 is selected I'd like to display a new <tr> with the
following:
<tr>
<td>New text field:</td>
<td><input name="newField" type="text size="20"></td>
</tr>
if any other choices are made, I don't want to display anything.
I've tried several onchange() functions but can't achieve what I'm
looking for.
I'm trying to do something that is slightly complex and I can't find any relevant examples in the usual places,I'm pulling a list of projects (and their IDs) into a select:
Code:
<select name="proj_id" id="proj_id" onchange='setValuz()'>
<option value="1" >1st Project</option>
<option value="2" >2nd Project</option>
</select>
Each project has two associated values, in addition to the unique ID:
[Code]...
Can anyone shed some light on how I could do this? Maybe a link to a "how-to" (if there is one out there)?
I have 2 dropdown lists which are connected to a mysql database. When I select an item from the first dropdown list the second dropdown list should show item which are linked to the item from the first list. But the thing is I can select an item from the first one, but the second isn't showing anything.
In the mysql database I have 2 tables: hesk_programma and hesk_projecten. In table hesk_programma there are a ProgrammaID and Programma column. In table hesk_projecten there are a ProgrammaID, a ProjectNumber and a Project column.
ProgrammaID from the two tables are connected to each other, so when I select an item from the first dropdown list with the ProgrammaID AK, the second dropdownlist should only display the items with the ProgammaID AK from the hesk_projecten.
Here is the code I use:
PHP Code:
<?php
mysql_connect("localhost", "root", "");
mysql_select_db("bestellingen");
$query = "SELECT * FROM hesk_programma ";
[Code]....
By the way, one more thing. The ProjectNumber from the hesk_projecten table should be displayed (when selecting an item in the second dropdownlist) in a input text field.
I have a PHP form which has an select field (i.e. drop-options) where the different options are populated from a MySQL database as follows:
<select size="1" id="category" name="category">
<option value="">Select from drop-list:</option>
<?php
$sql = "SELECT * FROM `DB1`
[code]....
Now, the issue I have is that I also have another input field (possibly hidden) in this form which is called 'category_id', and what I want it to do is to automatically populate when the user selects the relevant 'category' from the select field above.
I am looking for a way to use minimal javascript to open a popup window when the user clicks on an input field and allow them to choose one string inside the pop up window (like click on a radio button) and get the input box in the parent window filled with the value of the string. I know it's kinda standard, but I don't know much about using javascript ... so I dont know exactly what to search for ... I've seen hotmail allows you to populate your recipient input box using a popup ... I am looking to do something similar ...
View 3 Replies View RelatedI have a form which has a checkbox option.Only - if the checkbox is checked, then the email field must also be filled in.Otherwise the form is handled as normal (this includes filling in the email even if the checkbox is not checked).(hope this makes sense)
Code:
<input type="text" name="email" value="">
<input type="checkbox" name="Inform" value="Tell me stuff">
[code]....
I'm have a Joomla component who use Jquery for several thing in his template. This component have a form where some field are displayed and I would like conditionnaly restrict the use of 2 fields. I have in fact a field "City" and a field "Zip code" and my goal is to disable one field if the other is filled. In practice that mean if a user start to type the name of a city, the zip field must be disabled for avoid to fill also this field. Same thing if the user start to type in the zip field...the field City must be disabled too..
I need to setup this because the search engine of my component can not retreive correctly data if both field are filled. This happen tipically if the the zip code don't match with the name of the city... I that case the component will display "no result found" and this is annoying. Any example of working code making possible to get this function? Unfortunately I'm not a coder and except html and a bit of css, I do not have enough knowledge..
I am developing a site with Dreamweaver CS3 and have a little knowledge of HTML.
I need a solution for the following:
Visitors can come to my site through a referrer for ex: [url]
The referrers information (cesar017) should be prefilled automatically in a form field on another page than the index page. This means the visitor first can look around on the other pages of the site and then go to the page with the form.
I dont use a database at this moment, I only want a certain field automatically prefilled with the referrers info from the URL for ex : <input type= hidden -or text- name= partner id= partner value= ""/> In this case the field should have the value=cesar017
I understood this can be solved with Javascript or PHP and cookies, but I nearly dont know anything about this and Dreamweaver has not automated this function.
how can i grab a value off of a URL and fill in a input field on the page with that value? Say I have this url: [URL] how can i grab the value of var_email and pulse_daily and place it in a input field ?
View 3 Replies View RelatedI'm starting with javascript and I have a doubt. I already have a grid with data and a form with 5 fields. One of these fields of the form I want to fill with data of the grid. This is what I have:
[Code]...