Array Length Not Working In Safari?

Jun 8, 2009

The problem is that it keeps returning a value of 0 every loop. When tested in Internet Explorer, FireFox and Google Chrome, it works just fine, returning values as it should (in this case the values of 32, 36, 35, 36). However, like i said, Safri returns 0, 0, 0, 0.

Crazy thing is, before it calls the checkArray() function, i check to make sure its sending the correct number and it does, so its something to do with the .length part since i did a check on that and that's where its coming up with the 0's.

var aryItems = new Array();
function add2Array(theName){aryItems[aryItems.length] = theName;}
function checkArray(theName){
for ( var z=0, len = aryItems.length; z < len; ++z ){

[Code].....

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Multidimensional Array Length?

Jul 8, 2010

Is there any function or property for finding out the size of the first (or for that matter any) dimension of a multidimensional array?EDIT:There seems to be no such functionality, I found a solution that does not require it. If anyone is reading this for the same reason; it needs to be scripted.

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Feb 16, 2009

Ok the setup is basically this. The user selects a option in a drop down field, whatever they select through javscript additional records are populated in a second select field. This second select field allows for multiple selections, however I am submitting the form to a php script and I want to capture the multiple selections in the second select field. To do that for php I need to turn the field into an array so I have to add the brackets, [], to the name of the select field.

In php you can name the field like so:

Code:
<select name="fld[]" size="1">

The problem is in the js function when I give it a field name with [] the script doesnt work. Here is the js function:

Code:
function channelform(select_value) {
IntPath = document.channel_form.cid[]
TheOptions = IntPath.options.length

[Code]..

You can see the [] for the cid field name. Whenever I add that to the field name the js script is broken. How do I get it to work so that I can pass an array to php when the form submits?

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Mar 6, 2006

I'm wondering if anyone would be most kind as to give me a few pointers on the subject of arrays! I'm trying to create an array of an unspecified length, the length is based on the result of another task that is performed in my code:

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RegExp Match Returns An Array Of Length 2?

Jan 11, 2010

why I get an array containing [xml, xml]

Code:
str = 'index.xml'
re = RegExp( /([^s./]+)$/ ) ;
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I only need xml, not an array, and especially not [xml, xml]

Update: thnx mrhoo, thats clear now!

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Aug 3, 2009

I'm a JS beginner and I find looping through arrays with for/in is very easy. Yet I find lots of code examples where array length is used instead of for/in and I'm thinking to myself, why do it this (somewhat) hard(er) way?

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Nov 10, 2010

I have a function that requires the ability to count the number of entries in an array.

I'm using the following to call my function inside an input tag:

Here is the javascript:

And when errors.length is alerted, it outputs 0. I can only figure that there is an issue when using custom named keys in an array, since this works when I use only integers, however, I have the need to use a custom key index as shown.

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Mar 22, 2010

why I get this error when i have one radio button in the array with a length size of one and i = 0?

]document.radioForm.Radio[i] is undefined
Line 25

Here's the code

ln = document.radioForm.Radio.length
if(isNaN(ln)){
ln = 1[code].....

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Aug 16, 2010

i used the String.length(string) function in javascript to get the length of string but nothing happened. It doesn't give me a value when i tried to view the result using an alert function. Actually, this kind of problem does not only exist with the length function, it's also the same with the trim(). I have not tried using other functions but perhaps it won't also work. What could be the possible reason for this?

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Jul 12, 2011

validate: function () {
contact.message = '';
if (!$('#contact-container #contact-name').val()) {

[code]....

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May 27, 2010

xmlDoc.getElementsByTagName('TagName').length is not working in FireFox xmlDoc.getElementsByTagName('TagName').length is returning 0 in FireFox. its worth mentioning taht xmlDoc.load(XmlFile) is working fine in Firefox while its ok in IE.

following is my code:

if (mozilla) {
xmlDoc = document.implementation.createDocument("", "", null);
xmlDoc.async=false;
xmlDoc.load(XmlFil);

[Code].....

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Dec 3, 2009

The following script is scrolling my page smoothly, as it is supposed to, in IE and FF however it is not working at all in Safari, any version. The page is:

[URL]

When working correctly, you click the nav buttons in the left sidebar, the page scrolls to the appropriate section.

The script:

$(function(){
$('a[href*=#]').click(function() {
if (location.pathname.replace(/^//,'') == this.pathname.replace(/^//,'')
&& location.hostname == this.hostname) {

[Code]....

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Aug 15, 2007

Im using Javascript to expand a unordered list menu and it works on my pc in the latest versions of Opera, Safari, Firefox and IE. But i have been told that the buttons do not work in Safari on a MAC. It does however work in IE on a MAC.

Is there a difference between the way Safari on a MAC would read the code? Code:

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Dec 8, 2010

I am also in onclick problem, my code works fine in FF,OPERA,Chrome but not in Safari.My problem is this onclick.

Code:

1. <?php if(has_access($userarray,'view_serverdet','server')){
2. if (('Y' == $webpanel_ajax) && ('N' == $server_details || $usergroupid == "1")) { ?>
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[code]...

In other Browsers these values alert, but in Safari not.I use Safari 5.0.3 in Fedora 13 using Wine.

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Mar 30, 2006

I am using Regular Expressions and Javascript to validate a form,
specifically I want to make sure that if they try to upload a file that
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works on IE and Mozilla but fails on Safari on the MacOSX. Here is my
code..

// ok files with proper extension
var reOKFiles = /^([a-zA-Z].*|[1-9].*).(doc|DOC|pdf|PDF|rtf|RTF)$/;

//where i check for the file...
if(window.document.myForm.myDocument.value != ""){
var fileStr = window.document.myForm.myDocument.value;
if(!reOKFiles.test(fileStr)){
alert("Please try again, you tried to upload an invalid file type
for CRITERIA 1");
window.document.myForm.myDocument.focus();
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I'm using Fancy Form Slider and love it. In firefox, it's working great. In Safari, its not so hot. Check it out:[URL].. It renders fine in both, but the animation is acting REALLY weird in safari.

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[Code]...

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Nov 10, 2010

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Sep 15, 2009

I have written a PHP script for a secure client login system and it is working on Firefox and Chrome. But it doesn't work on Safari and IE. I have noticed that some of the javascript functions do not work at all while a few of them work.I am pasting the part of my code that does't work up here:

<script type="text/javascript">
function newdir(i)
{

[code]....

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Feb 11, 2010

Ok I have tried and tried and cannot get this code to work in safari or google chrome.

Basically I am working on a shopping cart. The user will click the paypal pay now button. The form is submitted to paypal via a new window target="_blank"

I also need to refresh the current page. This will write shopping cart data to DB via php upon page refresh.

Safari and google Chrome will open the paypal window, but seems to ignore the javascript to refresh the browser.

FF and IE both work fine.

<script LANGUAGE="JavaScript">
function newPage() {
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[URL]

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index.php
<?php
include "dbconnect.php";

[code]...

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Jun 25, 2010

I'm opening a new window with window.open in javascript and i'm keeping his reference to make focus on it or detect if the window is closed or not.My code is working well in Firefox and Chrome (execpt the window.focus, but there's already an issue in chromium: [URL]

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here is a sample of my code (I use jQuery 1.4.2):

Code:

MyBrowser = $.klass({
window_ref: null,
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[code]....

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Feb 15, 2009

I am integrating PHP with javascript and css to create an image gallery for an art site. When a user clicks a thumbnail, the painting shows above the thumbnails, and data about the painting, along with an artist statement (in the form of an image) shows up on the right side. Everything works as it should with firefox and safari, but the statement image is not showing up in explorer. I right click the broken image and it shows the correct url, but the image is not/won't be displayed. What am I missing?

[Code]...

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Why is jQuery only working in Safari (mac) and not for Firefox or Chrome?

[URL]

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