!Mouseover Images And Call Form
May 14, 2001Does anyone have any sample scripts or even tips on how to get an image to mouseover and when clicked will submit a form. (as graphic buttons will not mousover)
View 1 RepliesDoes anyone have any sample scripts or even tips on how to get an image to mouseover and when clicked will submit a form. (as graphic buttons will not mousover)
View 1 RepliesI'm trying to get a function to call when a user has mouseover a div (or table or form)
Onfocus doesn't seem to work. How can I achieve this?
I need a script to:
1. Display a base image on a page, e.g. image0.jpg.
2. On mouseover that image, it begins cycling through other images while the mouse is over it - (image1.jpg, img2.jpg, img3.jpg, etc.) and continues to cycle through them over and over again while the mouse is over.
3. Onmouseout, it goes back to displaying the base image (image0.jpg).
4. Needs to support multiple instances on the same page.
This is for an index page for different galleries, so there will be like 20 images showing on the page, and when the visitor puts their mouse over any of the images, it will cycle through the preview images for that gallery.
I am probably use way too much code to have this done.. but this is what I came up with..
$(function() {
$("#mail")
.mouseover(function() {
var src = $(this).attr("src").match(/[^.]+/) + "_over.png";
[Code]....
Problem is it doesn't do anything. When I only have one image set to change on mouseover it works fine.. I put two or more in there it doesn't work on any of the images.
I tried to put borders around images on mouseover. I use this code:
PHP Code:
<a rel="#voverlay" href="engine/swf/player.swf?url=../../data/video/gabriel_-_web-lashoppe_-_copie.mov&volume=100" title="Gabriel - Web-LaShoppe - Copie" onmouseover="this.style.border='1px solid Darkorange '; this.style.padding='0px
[Code]....
It is working but is there a way that I would not have to always put the mouseover tags to each images?
I currently have an image and underneath it there are 6 thumbnails. When I run the cursor over them the big image changes. This works fine. However, I would like to have text beside the big picture that also changes depending on the thumbnail over which I am hovering.
I have tried to work it out myself but failed miserably. I have tried forums, but can't find what I need. My code as it stands at the moment is:
<script type="text/javascript">
if (document.images) {image0 = new Image;
image0.src = "i/p0.png";
image1 = new Image;
[Code]....
who I can fix the rollover buttons? Or suggest a different script. I'm kind of old school and self taught... so I want to keep it simple.
[URL]
I am developing a framed site. I'd like to utilize javascript "mousevoer" to change images that are used for navigating the site. Where to find something like that?
View 1 Replies View RelatedI have created a page using the code below and it works fine.
Is there any way that I can replicate the gallery further down the page using different images? When I try, the mouseover on the top gallery opens the images in the bottom gallery.
<script>
I have a problem when changing images and image maps with mouseover and click events in IE. Firefox, Chrome and Safari all work well but IE does not. It's hard to describe but when I mouse over a hot spot the image changes and then right away changes back. you can see it here (http:url....): here is the Javascript code:
var current_overID = "";
var last_overID = "";
function item (img_name,width,height)[code]....
The code below allows the user to hover over 1 object and it not only replaces the object but also shows an additional object between the buttons.It works great in Firefox, but does not in Internet Explorer.
standard mouseover commands are used in index.php
<CODE>
<a href="http://www.tiimes.ucar.edu/beachon/" onMouseOver="imgOn('img1')" onMouseOut="imgOff('img1')">
[code].....
After many trials and errors finding exactly what someone wanted I came up with the solution I wanted for an image rollover. The problem is I put all the code directly into the mouseover/mouseout function. I am not sure how to implement this into two separate Javascript functions to limit the amount of code I have to write. The reason I am not sure how to write the function is because the images are in classes and the results are going to be pulled from a sql query, so they can't have their own id. So, in a nutshell, I just would like some guidance on how to put the mouseover/mouseout code into a Javascript function. Here is my code markup.
<div id="content">
<div class="container">
<ul class="thumb">
<li><img src="images/car1.jpg" width="80px" height="60px" class="images" onmouseover="this.style.width='180px';this.style.height='180px';
[Code]....
i am trying to do a mouseover effect with some images inside an unordered list. i have a lot of divs in my html (some are generated) but its fairly straight forward. i have tried all sorts of variations on my jquery code below but cannot get it to alert me. i am not sure if the other div containers matter at all or not.
$(document).ready(function() {
$("#navigation li")
.hover(function(){
[code]....
The site in question: [url]
The problem: Popups work fine, as they open the mini thumbnails when you mouseover. However, as you scroll down the page, the images move with you. So, if you mouseover'd the top result (having not scrolled down) the graph would appear when it was supposed to. However, if you scrolled down 200px, and then mouseover'd the top result (or any result), the thumbnail would popup 200px lower than it should.
The guide site I used: [url]- it doesn't happen on their site.
I set up a dummy site of their site: [url]- I just copied the source code for everything and changed literally nothing. It still happens on my version of the site.
<script type="text/javascript" src="ddimgtooltip.js">
I am trying to put an image on the front page of my website that changes to one of two random images on mouseover. This part was easy, and has been done (I got the code from [URL] But what I am finding difficult is to make each image link to a different page. For example, if the user mouseovers the main image and sees the 'thumbs up' image, then clicks on it, they should be taken to the 'thumbs up' page. And if the user mouseovers the main image and sees the 'thumbs down' image, then clicks on it, they should be taken to the 'thumbs down' page. The site is here: [URL] I think using 2 arrays is the way to go, but am not sure.
View 3 Replies View RelatedI have been trying all sorts of things, but falling short... I'm trying to set up a way to detect a user's browser size and then call a specific background image accordingly...
say (for example) that BKGD1.jpg is for users who have browsers that are 1280x1024 and higher; BKGD2.jpg is for users who have browsers that are smaller than 1280x1024...
i'm even open to an option that only displays a background image if the browser is (as in the example above) 1280x1024, and just a background color if the browser is smaller than that.
I dont know much about javascript but I am trying to get a little mouseover for a submit button to work.
<input name="Submit" type="image" id="submit" src="images/button-send.gif" alt="Send Email" />
<a href="#" onMouseOver="document.Submit.src='images/button-send-over.gif'" onMouseOut="document.Submit.src='images/button-send.gif'"></a>
am I even close?
I'm in the middle of teaching myself PHP and SQL so I'm only at the paste-and-tweak level with Javascript. Bear with my newbie-ness.I've seen a few solutions for creating a form dropdown menu that changes a nearby image based on what is selected. I want exactly that, but is it possible to have the images also appear on mouseover? I found a menu solution using CSS, but when I applied it to a form, it didn't work. Can anyone put me in the right direction on how to do that? I've started with this code, but need to tweak it to do this if possible:
<html>
<body>
<table border="0" cellspacing="0" cellpadding="0">
[code].....
[Cod]...
What trying to achieve is to have a div which when you mouseover a div and h4 within will change properties.This is working but when you mouseover the div and pass over either the border of the containing div or the h4 text the animate/fadeTo repeat again. Is someone able to tell what Im doing wrong? Also you may notice the function is effecting more than one container div at a time which is not what Im going for.
Is there a way to seperate them like this or somehow?
[Code]...
What I want to do is change the border of several images on the page to show a 4px border. There are many images on the page so I just want to call the changeborder() function on the onClick event so as the image that has been clicked changes. However, I don't think using this.style.border to identify the element works when placed within the function. That is, how do I identify, from the function, which image has been clicked? My current code (which does not work) looks like this but I am sure its possible to gather what i'm trying to achieve:
<script type="text/javascript">
function changeborder()
{
this.style.border='4px solid red'
}
</script>
<img style="border: 1px solid #F4F4F4;" onclick="changeborder()" src="images/colours/010.jpg" border="0">
I've tested across IE7,Firefox, Chrome, Safari and the only browser I experience this issue in is Opera. I have 3 icons at the bottom of the page (facebook, rainbow, charity logo) and on mouseover the whole site expands downwards (it's not supposed to do that). I've googled for reasons why it would do this but have found none. [URL]...
View 1 Replies View Related1.The user presses 'Submit Answers' button,which ends the exam and his result is displayed.This one is working fine.
2.The other is the timer expires.the exam finishes and the user's result should be displayed.This one is giving me a problem.
When the timer expires I want to run the onsubmit() function to assign values to hidden form inputs ,but I am unable to do so.How do I do this.Everything else with the timer function is working fine. Only a snippet of the actual code is given here,because the rest of it is ,I believe,irrelevant to the discussion.
[Code]...
"<scr'+'ipt type="text/javascript" src="js/val_feedback_Email.js</scr'+'ipt>"
How should I call the js validation script for a feedback form that was document.written in a pop up?
I have a page which contains a button. Onclick it produces a pop up window that contains a small feedback form produced by document.write. This much works.
NOW I need to call the js validate script but nothing seems to work
I tried this is the head of the page
<script type="text/javascript" src="js/val_feedback_Email.js">
I tried this is the head of the doumnet.write part
"<scr'+'ipt type="text/javascript" src="js/val_feedback_Email.js</scr'+'ipt>"
How do I call the js script to validate the form in the pop up? Where if anywhere should it go?
THis is the start of my script
<script type="text/javascript">
var newWindow;
function subWrite() {
newWindow = window.open("","","status,height=500,width=700")
[Code]....
I am about to submit a form and I need to call two functions onsubmit. But I guess this cannot be achieve? Code:
View 2 Replies View RelatedOn my page, I'm uploading photos. The form looks like this:
HTML Code:
<form action="addPhotoHandler.php" name="form1" method="post" enctype="multipart/form-data" target="upload_target" onsubmit="return beginUpload()" >
<input multiple='true' onchange=' beginUpload();
[code]....
It's supposed to execute on every file upload. The problem is that it only shows the last call after every file is done uploading. "File 3 of 3" or "File 16 of 16" and never anything in between.
Scenario: I have a form with around 125 input fields. I want to use .ajax() to send these form data to the server.Is there a way to send the entire form to the server? Like, the form is passed when we click submit button and url changes. But I want to achieve this using AJAX.
View 2 Replies View Related