I am quite happy to stay put using v 1.2.6 but with new bits requiring v 1.3.2 etc I would quite like to know why this isn't working when I use jQuery above 1.2.6. There are a few different things going on.
Code JavaScript:
<script type="text/javascript">
$(document).ready(function() {[code].....
I need a script that will redirect to a specific page is the browser is safari version 4. if the browser is NOT safari 4 I want the browser to stay on the current page.
View 3 Replies View RelatedI was using JQuery 1.2.6 but after I downloaded the version 1.4.2 I get the following error on FireFox: uncaught exception: Syntax error, unrecognized expression: .
View 1 Replies View RelatedI am using Jquery 1.2.6 version with existing website. I want to animate something on mouse over and for it I used animate function for it but I not able to get expected result.
$(document).ready(function() {
$(".small-packagebuilder").css({"background-position": "5px 0"});
$(".builder_top_magenta span a").hover(function() {
[Code].....
I have used your great plugin for a menu in Wordpress 2.8.4 and I wanted to use the default Wordpress jQuery library jquery.js?ver=1.3.2 but your plugin Superfish wouldn't work. I added the jquery-1.2.6.min.js file and it did work OK. Since there is no reason to have calls to two jQuery libraries which are doing the same thing I wanted to only use the default Wordpress jQuery version. After some searching I found an answer at this site:[url]..
I changed this to: jQuery(document).ready(function($){ Notice the $ function being moved. This now works OK using the default Wordpress jQuery version 1.3.2. and I imagine with the latest version of jQuery.
I'm trying to use the cascade function from the below link. If I try it as it is there, it works, but if I change the jquery reference to the one I'm using (1.7.1) it stops working... is there a diferent way to use that ajax call or am I missing anything?
View 3 Replies View RelatedI'm developing a relatively simple html based site for a gallery. Small images of paintings link to a popup window with a larger image of the painting. The problem is that the javascript code doesn't seem to work in Chrome or the new version of Firefox (where it only opens a new blank tab), though it works perfectly in Safari. This is my code (for vertical images):
var viewerWin=0;
function windowPopVer(URLStr)
{
if(viewerWin)
{
What am I doing wrong? We've changed the settings in Chrome and Firefox so that it enables javascript and all that. Why won't this work?
The CMS I use for my site currently runs/supports jQuery 1.7. The developers have chosen to leave the minified v1.2.6, v1.3.2, v1.4.2 files in the system too. I was wondering if any functionality was deleted over time from the lib. Does v1.7 contain all functionality from all older versions? Can I safely delete these older libs?
View 1 Replies View RelatedWhy this script no longer works in firefox? It works in the older version but since it got updated to version 3.5.3 it doesnt work anymore. It works fine in IE.
<script type="text/javascript">
function show_popup(s_file, msg, msg2, msg3, w, h) {
var p=window.createPopup()
var pbody=p.document.body
pbody.style.backgroundColor="white"
pbody.style.border="solid white 6px"
pbody.innerHTML="<table cellpadding=0 bgcolor=white style='border:0px solid #777777'><tr><td colspan='3'><img src='images/"+s_file+"'></td></tr><tr><td align=left><font face='times' color='black' size='1'><i>"+msg+"</i></font></td><td align=left><font face='times' color='black' size='1'><i>"+msg2+"</i></font></td><td align=left><font face='times' size='1' color='black'><i>"+msg3+"</i></font></td></tr></table>"
p.show(15,15,w,h+40,document.body)
}
</script>
This is then what I add for each of the images ->>
<a href="javascript:show_popup(image.jpg','Image Example ','acrylic on masonite','62 X 48 inches',430,564)"><img src="images/thumbs/image_thumb.jpg" alt="Images" width="100" height="128" border="0" align="center" valign="TOP" /></a>
I have problems updating from version 1.7.2. to version 1.8. I'm using a custom theme - can anybody give me a step-by-step guide how to update without destroying the whole site ? :) I would like to have the button featueres in the new version
View 1 Replies View RelatedOn my homepage (only my homepage) in newer browsers (anything but internet explorer), my table (I don't use css) color is not the right color, It's the same as my background color for some reason.Second, my slideshow messes up in newer browsers, and will overlap text that it shouldn't. What I need is either a way to fix the slideshow, or a new one that will work in newer browsers.
View 1 Replies View RelatedI have a web app that needs the follwing settings
Tools/internet options/settings/
Check for newer versions of stored pages.
I can not rely on the users to do this.
Is there any way to did this programatically?
I am trying to get started using JQuery, but I find I can't even get to lesson #1. When I go to jquery.com and click to download the latest version (or any version) it doesn't "download" anything. It opens the file as a webpage in my browser and I see all the JQuery in one big string. Why won't the file just download? Is it the browser I am using? Is it my Mac?
View 2 Replies View RelatedThis code works in all browsers, Safari, Chrome, Firefox, but not IE 8 in which I'm testing right now for version.The code is below:
<script type="text/javascript">
$(document).ready(function() {
$('#form_{picture_id}').ajaxForm(function() {
[code]....
I am trying to create 3 boxes with 2nd select box content to be uploaded on the basis of value selected in first box and third box list should be uploaded on the basis of value selected in 2nd box.i have written coding for that as below but it is not working .
<html>
<head>
<title>Search Website</title>[code].....
i have a select dropdown list working fine in firefox...but in IE it is not dynamically changing.i am using Jquery 1.32here is my code
$(function() {
$(document).ready(function() {
$('#provider').load("ajax/order.php?atask=getallproviders", {
[code]....
every other browser fails. there's got to be a simple explanation for this. code:
$(document).ready(function() {
$('.next').click(function() { nextSlide(); return false });
$('.back').click(function() { prevSlide(); return false });
[code]....
This code has been working in jQuery 1.2.3:
var country = jQuery("select[@name='country']").get(0).value;
now in jQuery 1.3.2, I got this error:
[Exception... "'Syntax error, unrecognized expression:
[@name='country']' when calling method:
[nsIDOMEventListener::handleEvent]" nsresult: "0x8057001e
(NS_ERROR_XPC_JS_THREW_STRING)" location: "<unknown>" data: no]
Line 0
The fadeOut is not working...
What is wrong in my code?
I am working on my site and I am finding trouble getting my thumbnails to open the larger images when clicked. It only seems to work with the first thumbnail, but I can't figure out why.Here is the code I am working with:
<link rel="stylesheet" type="text/css" media="screen" href="css/colorbox.css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript" src="javascript/jquery.cycle.all.min.js"></script>
<script type="text/javascript" src="javascript/jquery.colorbox-min.js"></script>
[code]...
This code is supposed to find all table rows with a class of "selected", remove that class, then find all checked inputs that are descendants of a tr and give its tr a class of selected. The problem is, that even radio boxes that are not checked are being returned by $(' tr input:checked', '#deviceSelection') and everything is getting a class of selected. Anyone know whats wrong? I'm using jQuery 1.4.1
[Code]..
Below code is in html
<div id="firstdiv">
<input type="text" class="cal"/>
</div><input type="button"/>
Below is in head tag
$(function() {
$('.cal').datetimepicker();
});
Following in .js file
$(document).ready(
function(){ /* here goes the code for div clone*/
$addTripBtn.click(
function(){ var $firstCal = $copydiv.find(':text');
$($firstCal).bind('click', function() {
$('.cal').datetimepicker();//$('$firstCal').datetimepicker();
});
I have textboxes in div wherein onclick I get a calender popup. Now I have to repeat this div on button click for which I used clone() method. Repeating div content is working fine but when I click cloned textbox for calender it is not working.
I have very common Problem with myJavaScriptThat I have create on page that have one div that is when page load it is display none when i click on link then its html is showing in modal Dialog that i have made my own but on that modal i am not able to fire any event but when execute any without the modal dialog then its working
View 2 Replies View RelatedI was under the impression that jquery is cross browser. For some reason in chrome when I click my button, nothing happens. this works in FF and IE though[yes, this code is extremely ugly and not proficient, but it works in IE/FF. I just started learning jquery,
$(document).ready(function() {
$('.extra_btn').click(function() {
$('.extra_btn').fadeOut('fast');
[code]....
When i use $.get without alert() my code not working into asp.net ( updatePanel and ScriptManager for asp.net ). if i use this code in firefox dont work:
[Code]...
Why does my below code not work in Safari and firefox? The below code does not call my page method.but it works on IE. Is there any thing need to enable Ajax mehod call.
[Code]...