I am trying to use the Conveyor Belt slideshow script, from Dynamic Drive. [URL]. I have two DIVS, one on top of the other, and I would like to use this script in both places, on the same page. For the life of me, and many, many, many hours later, I cannot get it to work.
View 2 RepliesI need to be able to fade in 3 divs but not all at the same time, I need one to fade when thats finished, fade in then the next, then the next. Can anyone help me with this? I assume its got something to do with queue's but im not 100%
View 1 Replies View RelatedI have a little issue with trying to hide / show multiple divs on my page. I am using a class name for the divs but the name is generated by a field have set in my database. So for example
<div class="General">Ttitle 1</div>
<div class="General">Ttitle 2</div>
<div class="General">Ttitle 3</div>
<!-- and my link is -->
<a href="#" class="toggle" title="General">Toggle 1</a>
And then say I have
<div class="Questions">Ttitle 1</div>
<div class="
Questions ">Ttitle 2</div>
<div class="
Questions ">Ttitle 3</div>
<!-- and my link is --><a href="#" class="toggle" title="
Questions ">Toggle 2</a>
What would be the easiest way or the best way to code out the jquery to hide / show all the divs with the same name as the links title i can do code jquery to toggle 1 div but not sure how to code it so that it will hide / show all the divs with the same class name.
Currently I'm using this code:
$(document).ready(function(){
//when a link inside our thumbba div is clicked
$('#thumbb a').click(function(event){
//prevent the default behavior(going to the page)
[Code]....
to swap out content from a hidden div (swap-b) into the visible div (swap-a) - this works great, however, I have 12 of these "hidden" divs on the page, and I want each one to behave independently. Currently, when I click the swap button for one div, it activates all the others. I get that this is because all the divs have the same IDs, and that the function is telling all the divs to behave the same, however, I don't see how I'm supposed to apply this function to each div independently. I've tried using a "this" function to make it work, however that just breaks the function.
I use this script to show/hide multple divs on a page. I am trying to adding cookies to this script.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "[URL]">
<html xmlns="[URL]"><head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Show Hide</title>
<script language=javascript type='text/javascript'>
function hideSpan(pass) {
var spans = document.getElementsByTagName('span');
for(i=0;i<spans.length;i++){
if(spans[i].id.match(pass)&&spans[i].style.visibility){
spans[i].style.visibility=spans[i].style.visibility=="hidden"?"visible":"hidden";
}}}
</script></head><body>
<span id="256a" style="visibility:hidden;" >
My content<br/>
</span><span id="256b" style="visibility:hidden;">
<br/></span>
<span id="512a" style="visibility:hidden;">
<br/></span>
<a href="javascript:hideSpan('256')">show/hide span 256</a>
<a href="javascript:hideSpan('512')">show/hide span 512</a>
</body></html>
I have been trying to do some tooltips for a website and desperately wanted to learn something new and do that with jQuery.However, every time a mouse hovers over a tooltip, all hidden divs are shown, not just the one that supposed to. Here's my html:
Code HTML4Strict:
<div class="tip">
<a href="#"></a>[code].....
This link below is of a slideshow [URL]Is it possible to have multiple instances of it in a page. I wish to have 4 of them, one below the other. I have no knowledge in javascript but tried making some changes.
View 2 Replies View RelatedIm a complete newbie to javascript and I've basically copied and pasted the javascript I found here to use on my site. Its an onMouseOver slideshow: [URL] to use on my site. Basically, my problem is how do I add a second, separate image in a different location on the web page, associated with this script? If I post <a href="javascript:warp()"><img src="myimage" name="targetimage" border=0></a> in two different locations, which is the script for the image, the script stops working, but having it once makes it work. So how do I add two different image locations? Can someone please help me here? I just want to add more images in a different location. ie have image location 1, and image location 2.
[Code]...
I have a form with 3 questions and 9 hidden option divs. Questions are answered in radio form and it will be mandatory to answer each question. Depending on which radio in each question is selected, several of the hidden divs will display, once the "Get options" button is selected. Now the code I have already works fine (only tested in IE8), however I'm almost 100% positive that the Options() function can be truncated considerably. In the final form, there will be 36 individual permutations of radios and as you can see with the little example below, the function will get quite large.
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
[code]....
I have a fixed size area.called a container tag.And based on selection of no of divs the area should divide into those many no of equal divs.And is there any other techinic to divide area by multiple divs or parts.
View 1 Replies View RelatedIn short, I have a lot of divs with the same id and would like to change the background color without having to name them all differently. Is there anyway to do it?
Using:
Code:
document.getElementById(timebox).style.backgroundColor = #E00;
But that only changes one div.
I was wondering how to show MULTIPLE divs.
Not one at a time, but all my divs with one link.
Is this possible?
On my site I have a news page, where users can read part of the news (trimmed with php) and then they click "Read more" to see the full news item. That item then comes up in a popup (using jQuery of course) and should be displayed. To get this to work I'm usingthisby including it like so:
<script type="text/javascript" src="includes/jquery.colorbox.js"></script>
The jQuery code looks like so:
$('.open').colorbox({width:"50%", inline:true, href:"#news"});
This all works great with that one div. The problem is, my news will be coming from a MySQL-query via PHP in a while-loop and I need this effect applied to every single news item. What I tried is to do this:
while($row = mysql_fetch_assoc($rs)) {
echo '<a class="open" href="#">Read more</a>';
echo '<div id="wrapper" style="display:none">';
[code]....
how do I make this work? How do I make jQuery open only the news item I'm clicking on? I know it could possibly be done with (this) and maybe children() or something like that? But I'm totaly lost at the momeny, I've tried loads of stuff with the pieces mentioned above but can't get it to work and most times I just "break" the jQuery and the popup won't even come up at all.
I have a div with a height of 100 pixels.If the content is too much to fit in div, I want to show a 'Read More' link at the bottom.If you then click 'Read More', the div expands to full height so all the content can be seen and the link text changes to 'Read Less'.If you then click 'Read Less', the div contracts back to 100 pixels.I've found solutions that can handle the above situation, but I want to have multiple divs with the same class that all work independantly of each other.So I'd have the following HTML
[code]
<div class="openclose">
...some content...
[code]....
I'm trying to piece together a little div which slides out and shows various links to sites like Digg, Reddit to share the story with. I've got it kind of working but when there are multiple divs on the page, named the same like in each article of a post on a Wordpress blog. Only the top ones work and the rest don't do anything...I'm trying to get it do something like the image => HereThis is an example I'm trying to get to work but the second "slickbox" div never shows
View 1 Replies View RelatedI'm trying to use nextUntil to select all the .cell divs between the .start-date and .end-date, the code works for the .cell's within it's .cal-container but if wont work over multiple .cal-containers.The code I have is$('.start-date').nextUntil('.end-date').addClass('fill-date');
<div class="cal-container">
<div class="cell" id="1" title="01-01-2011">1</div>
<div class="cell" id="2" title="02-01-2011">2</div>
[code]....
Want to swap multiple divs using onclick. Understanding of js is cursory. The way its set up now is when you click it hides a pre-specified div-this causes issues because you dont know which div the user is going to be on and if the user is on a different div then one specified it hides random divs. I want to hide the 'active' div. Heres the code. In head:
Code:
<script type="text/javascript" language="JavaScript"><!--
function HideDIV(d) { document.getElementById(d).style.display = "none"; }
function DisplayDIV(d) { document.getElementById(d).style.display = "block"; }
//--></script>
[Code]...
I am creating a form. The form uses variable to show different divs. Like for example .
If the user chooses state where tax will be implemented than it will update the div which contain total amount. Now the problem is I have 3 divs on a page and I want to update all of them accordingly. Like user select quantity as 500, state as florida. So I need to update 3 divs .. total cost, Shipping cost and quantity divs. Problem is they all r not inside a single div else I would have put tht whole div inside the response. So is there a way to update multiple divs?
Below id the ajax code I am using ..
Code:
function update_dockcontent() {
var quantityval = document.HVAC_Cards_Form.Quantity.value;
var BillingZip = document.HVAC_Cards_Form.BillingZip.value;
var url = '[URL]'+quantityval+'&BillingZip='+BillingZip;
if (window.XMLHttpRequest) {
req = new XMLHttpRequest();
if (req.overrideMimeType) {
req.overrideMimeType('text/xml');
} .....
Code for ajaxcall page is:
Code:
<?
header("Cache-Control: no-cache");
header("Pragma: no-cache");
$total=($_GET[qval]*0.50);
$shippingrate="50";
if($_GET[BillingZip]) {
$total=$total+$shippingrate;
}?>
<p>Total Quantity: <strong><?=$_GET[qval]?></strong></p>
<p>Shipping: <strong><?=$shippingrate?></strong></p>
<p>Total cost: <strong>$<?=number_format($total,2)?></strong></p>
I want to show all 3 of them in different divs.
I am trying when a user chooses an airline from dropdown seen here [URL].. that two additional drop downs appear for departing airport and arrival airport. I have coded it to work when one chooses American Airlines from drop down, but I need different departing and arrival airports to appear for the various a user may choose.
View 5 Replies View Relatedim not so good in javascript.I want to show multiple divs on select of a <option> box. So lets say there are 3 options.All works fine up to some point, when I choose lets say option 'b' first.. I get 2 divs. Thats good.. Then I choose option 'c' I get only one div. Thats good.But if I choose option 'b' again, I get 3 divs instead of 2 !! It shoudnt show the div from from option 'c'.
View 1 Replies View RelatedI will have a page with about a 100 or so different links and I would like each one to toggle the visibility of its corresponding hidden div.For instance, if I have a county 'Johnson' when it's clicked I would like the hidden div associated with that county to become visible. I would like to do this without having to write a different function for each one. Is there a way to do this easily?
Below is a solution I was given elsewhere but I couldn't get it to work.Most ideal of all I would like it to work with an image map, with each county having it's own set of stats to be toggled in.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>[code].....
I've created an ajax function which retrieves comments from a news article. But if I am logged in I will also have access to an input field for posting comments. The problem / question is that if I use Ajax I can only update one div with the responseText? How would I go about updating another one where I want to insert my form field. Can I make multiple requests in some certain manner or do I simply create another ajax function updating it separately?
http.onreadystatechange = function(){
if(http.readyState == 4){
document.getElementById(newsId).innerHTML = http.responseText;
}}
http.open("GET", "AjaxController.php?func=newsGetComments&showcomments="+newsId, true)
http.send();
I have multiple divs something like this
<div id="div1">
<div id="div2">
<div id="div3">
[code]...
I want JavaScript code to print div1 with all nested divs as well I tried using the following code but it only print div1 content
PHP Code:
var printContent = document.getElementById('div1');
var windowUrl = 'about:blank';
var uniqueName = new Date();
[code]...
What i would like to achieve is a single page with multiple fade in/fade out divs.
Like this section of the Apple site, click the navigation on the left, the different content sections fade in/out, the links are all hash links to id'd divs on the page. so the whole thing doesn't fall apart without the script.
I did a bit of a trawl and found this example that works on the mouseover, I had a look as the script and can't see how I would change it from 'hover' to 'click'.
The other I found was this one But the 'multiple' example on there seams to have some sort of 'flicker' and the examples all use script within the href which isn't great accessibility wise.
I also took a look at the Apple page, they are using 'scriptaculous' to do this, but they also do a bunch of other things on that page so finding the bit that just does the click fading, is a bit like a needle in a haystack.
I have a page with a number of divs on it. The number of actual divs is variable and is database dependent. Each div has a sequential id, e.g.:
<div id = "id0">
<div>
<div id = "id1">
[code]....
Initially the first div's visibility is set to "display: block" and all the rest to "display:none". What I would like to be able to do is present the user with a series of links which when clicked would result in just one of the divs being displayed and the rest all hidden.
I found code on this site for creating popup divs, and got one such popup working fine. Trouble is, I can't figure out how to create multiple popups. I've tried duplicating the CSS piece, calling it layer2, and referencing it from the link piece, but nothing happens. Do I need to create a new javascript file for each layer?
View 3 Replies View Related