I need to be able to fade in 3 divs but not all at the same time, I need one to fade when thats finished, fade in then the next, then the next. Can anyone help me with this? I assume its got something to do with queue's but im not 100%
View 1 RepliesI have a little issue with trying to hide / show multiple divs on my page. I am using a class name for the divs but the name is generated by a field have set in my database. So for example
<div class="General">Ttitle 1</div>
<div class="General">Ttitle 2</div>
<div class="General">Ttitle 3</div>
<!-- and my link is -->
<a href="#" class="toggle" title="General">Toggle 1</a>
And then say I have
<div class="Questions">Ttitle 1</div>
<div class="
Questions ">Ttitle 2</div>
<div class="
Questions ">Ttitle 3</div>
<!-- and my link is --><a href="#" class="toggle" title="
Questions ">Toggle 2</a>
What would be the easiest way or the best way to code out the jquery to hide / show all the divs with the same name as the links title i can do code jquery to toggle 1 div but not sure how to code it so that it will hide / show all the divs with the same class name.
Currently I'm using this code:
$(document).ready(function(){
//when a link inside our thumbba div is clicked
$('#thumbb a').click(function(event){
//prevent the default behavior(going to the page)
[Code]....
to swap out content from a hidden div (swap-b) into the visible div (swap-a) - this works great, however, I have 12 of these "hidden" divs on the page, and I want each one to behave independently. Currently, when I click the swap button for one div, it activates all the others. I get that this is because all the divs have the same IDs, and that the function is telling all the divs to behave the same, however, I don't see how I'm supposed to apply this function to each div independently. I've tried using a "this" function to make it work, however that just breaks the function.
I have been trying to do some tooltips for a website and desperately wanted to learn something new and do that with jQuery.However, every time a mouse hovers over a tooltip, all hidden divs are shown, not just the one that supposed to. Here's my html:
Code HTML4Strict:
<div class="tip">
<a href="#"></a>[code].....
I am trying to use the Conveyor Belt slideshow script, from Dynamic Drive. [URL]. I have two DIVS, one on top of the other, and I would like to use this script in both places, on the same page. For the life of me, and many, many, many hours later, I cannot get it to work.
View 2 Replies View Relatedhave this Multiple Image Viewer very similar, -in fact almost identical- to the one in the main page of economist.com It uses the following code and its woriking nice,
Code:
function switch_product_img(divname, divnumber, divtotal) {for (var i=1; i<=divtotal; i++) {
var showDivName = divname + '_' + i;
[code]....
I use this script to show/hide multple divs on a page. I am trying to adding cookies to this script.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "[URL]">
<html xmlns="[URL]"><head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Show Hide</title>
<script language=javascript type='text/javascript'>
function hideSpan(pass) {
var spans = document.getElementsByTagName('span');
for(i=0;i<spans.length;i++){
if(spans[i].id.match(pass)&&spans[i].style.visibility){
spans[i].style.visibility=spans[i].style.visibility=="hidden"?"visible":"hidden";
}}}
</script></head><body>
<span id="256a" style="visibility:hidden;" >
My content<br/>
</span><span id="256b" style="visibility:hidden;">
<br/></span>
<span id="512a" style="visibility:hidden;">
<br/></span>
<a href="javascript:hideSpan('256')">show/hide span 256</a>
<a href="javascript:hideSpan('512')">show/hide span 512</a>
</body></html>
I'm trying to create a fade in out effect of three divs in the same place, but for some reason the effect is duplicating itself for two of the divs.
<div id="click1">click1</div>
<div id="click2">click2</div>
<div id="click3">click3</div>
<div id="content1" class="vis">This is the content initially</div>
[Code]....
I'm learning javascript, and was wondering if it was Possible to have buttons/links that you click, the whole page fades out, and then fade's in, with different stuff. here are my ideas for just changing the stuff
Text: 1. having a javascript src file to start, and then when the button is clicked, that is formatted to white, the text layer is moved down, and a new javascript file is loaded?
I have a concept I want to develop but haven't been able to find a jQuery plugin that will do what i need. I am hoping if someone knows of a script or even to share if this is possible.
What I want is to have about 10 small images to be displayed horizontally and have each of these images fade in and out at random times and being replaced by other images.
I have a flash example that i would like to replicate that would give you an example of what i want to achieve. If you look at the bottom of the page where the platinum sponsors are this is what i want to replicate.
[URL]
I need some help achieving an effect.
<span>SOME TEXT</span>
First part, move "SOME TEXT" left 20px and fade to 0 at the same time. Easy enough.Second part, repeat the same effect half way through the first part is done and the starting point is left 20px.So I would need to create the first effect. Half way through the first effect the second effect starts but it has a different starting point.
On my site I have a news page, where users can read part of the news (trimmed with php) and then they click "Read more" to see the full news item. That item then comes up in a popup (using jQuery of course) and should be displayed. To get this to work I'm usingthisby including it like so:
<script type="text/javascript" src="includes/jquery.colorbox.js"></script>
The jQuery code looks like so:
$('.open').colorbox({width:"50%", inline:true, href:"#news"});
This all works great with that one div. The problem is, my news will be coming from a MySQL-query via PHP in a while-loop and I need this effect applied to every single news item. What I tried is to do this:
while($row = mysql_fetch_assoc($rs)) {
echo '<a class="open" href="#">Read more</a>';
echo '<div id="wrapper" style="display:none">';
[code]....
how do I make this work? How do I make jQuery open only the news item I'm clicking on? I know it could possibly be done with (this) and maybe children() or something like that? But I'm totaly lost at the momeny, I've tried loads of stuff with the pieces mentioned above but can't get it to work and most times I just "break" the jQuery and the popup won't even come up at all.
I have a div with a height of 100 pixels.If the content is too much to fit in div, I want to show a 'Read More' link at the bottom.If you then click 'Read More', the div expands to full height so all the content can be seen and the link text changes to 'Read Less'.If you then click 'Read Less', the div contracts back to 100 pixels.I've found solutions that can handle the above situation, but I want to have multiple divs with the same class that all work independantly of each other.So I'd have the following HTML
[code]
<div class="openclose">
...some content...
[code]....
I'm trying to piece together a little div which slides out and shows various links to sites like Digg, Reddit to share the story with. I've got it kind of working but when there are multiple divs on the page, named the same like in each article of a post on a Wordpress blog. Only the top ones work and the rest don't do anything...I'm trying to get it do something like the image => HereThis is an example I'm trying to get to work but the second "slickbox" div never shows
View 1 Replies View RelatedI'm trying to use nextUntil to select all the .cell divs between the .start-date and .end-date, the code works for the .cell's within it's .cal-container but if wont work over multiple .cal-containers.The code I have is$('.start-date').nextUntil('.end-date').addClass('fill-date');
<div class="cal-container">
<div class="cell" id="1" title="01-01-2011">1</div>
<div class="cell" id="2" title="02-01-2011">2</div>
[code]....
I want to animate divs on click . But the problem is there are multiple divs and I unable to get the height of each div
my code isfunction show (div) {
var hei = $('.a').height();
$('.show').click(function(){
$('.text').animate({'height' : hei + 'px'})
[Code]...
Getting myself back into jQuery and have an issue which I didn't previously fix, and was wondering if anyone would be able to assist me. I have multiple DIVs (up to 50 on one page) that I wish to individually be able to hide and close an extra DIV once pressing the 'Details' to show, and 'Hide' to hide the extra hidden DIV.
[Code]...
I am trying to get the height of a div that is inside 7 other divs. I noticed the height() method works with the first and second div, but it does not work after that.
Example :
<div id="first">
<--------------------------- $("first").height(); works ![code]....
how to get the height of a div that is inside multiple other divs ?
I'm new to jQuery, and I'm having issues with showing my DIVs correctly. The problem with the script at the moment, is that it currently opens up every single .display div, whereas I only want it to open up the one which corresponds to the.input a.edit which I've clicked.
The script hides them individually, displays the hide button and makes the show button display correctly like I wish, but it's displaying all the the .display div's at the same time which isn't what I want. For reference here is my jQuery script:
[Code]...
How can I display a bunch of DIVs in multiple columns? Like Flex's TileList component.
A
B
C
C
[code]....
$("#addURLSArea").hide();
$('.jqTransformCheckbox').click(function(){
if ($('#multCheck:checked').val() == 'on') {
$("#addURLSArea").slideDown();
} else {
$("#addURLSArea").slideUp();
}});
I want to use this 4 times on a form. How do I change this so I can have it target 4 different divs?
I have a group of 4 divs and I'm looking to use jQuery to animate them once, then have a delay using delay(), and then run another set of animations on them, putting the divs back to their original configuration. Here's the code that I have:
//only selectors called 'option1' are affected by delay, and not 'option1 img' or 'option2'
$("#option1").showOption1().delay(3000).hideOption1();
//if i don't attach to #option1, delay doesn't work, but the animations that need to happen simultaneously work
[Code]....
will work from hideOption1() after the delay. The rest of hideOption1() is fired immediately after showOption1() finishes, ignoring the delay.
On the other hand, if I run line 5, all the code in hideOption1() runs simultaneously as desired, but ignores the delay entirely, running immediately after showOption1() finishes. How can I have all the code in hideOption1() run simultaneously after the delay?
I am trying to toggle multiple divs toggle open/closed show/hide with a slide left effect It works but is buggy if you click too fast [URL] I want to create this but control to content in the sliding divs [URL]
View 1 Replies View RelatedI have five divs that I want to work kind of like an accordion, but you can open multiple sections. Right now, when user clicks any link, it opens all five sections. And when you click to close, it closes all five. I want to be able to open one section, then go to the next and so on.
Here's what I have now:
Html looks like this:
I am trying to arrange 15 divs into a 5x3 grid.The divs have an id of piece1, piece2, piece3 etcI figured I could run a loop wherein each div is positioned to the right of the last.For each div, I'm trying to store the current position and width into variables then move it to the right by the number of pixels the div measures widthwise.This would position 5 divs horizontally and I am still unsure of how to get the next row of 5 divs positioned under the first and so on.This is what I have so far:
JQuery
for (var i=0; i<x; i++) {
var pos = $("#piece" + i).offset();
[code]....
I'm trying to use the function once which is .load() and fetch my content from there,then after that I'd like to seperate the class's or div's I'll be using such as <div d="test1">This content will show in the external website</div>But I'm having trouble doing that, I've used multiple lines just to load the same page and take small bits of content out and it doesn't work well together as some load's results will be different compared to the others.Heres my code:
$('#". $Server['ServiceName'] ."').fadeOut('slow', function(){ $('#". $Server['ServiceName'] ."').load('./includes/serversinfo.php #servers #". $Server['ServiceName'] ."', function(){ $('#". $Server['ServiceName'] ."').fadeIn('slow'); }); });
[code]....