I am using Soundmanager 2 to currently execute audio clips when vistors click on images. I want to have to cycle through 3 mp3s each image, with each click, "click" play 1, "click" play 2, etc etc? Seem doable, but I am not sure how - Hence I am here Here is the code I am using on the images. FYI there is also a rollover on the images too.
[Code]...
Should I disable the right click option or not? I have a gallery site, I don't want people to be able to copy the images with the default right click over an image. From a professional looking site point of view I suppose I would be messing with the functionality a bit too much, OR is it OK in this instance to disable the click. I know how to write the code to disable the click, but what I was thinking was maybe it would be better to leave the right click but change the menu options? I'm not sure how to change the menu options ere is a link to the site. [URL]
View 12 Replies View RelatedI cant really figure this out, the only thing i could see messing it up is the javascript:void(0) inside the anchor link but since there is a double click function and a click, it should only be one click.I put autoOpen which i think is also causing it, but i did that so theuser can open it, close it, and open it again so the delay "double click" is saying for the first time initialize and then the second click is opening?? if so how do i get around this?
HERE IS MY JQUERY
$(document).ready(function(){
$("#pro_edit_profile").hide();[code]....
HERE IS MY HTML FOR THE LINK
<a href="javascript:void(0);" id="pro_edit_pic_link" name="Change
Profile Picture">Change Profile Picture</a>
There is a checkbox on a form page, when you check it, a div will become visible with some extra inputs needed for that situation. To simulate this click on the checkbox external, I use click(). With jquery files 1.4 and lower this works properly and like expected. When using jquery library 1.4.1 or higher, something does not seem to work properly. Sooooo, the code:
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.min.js"></script>
<!--<script type="text/javascript" src="http://code.jquery.com/jquery-1.6.1.min.js"></script>-->
<script type="text/javascript">[code]....
Somehow I managed to get this thing 'sort of' working with 1.4.1 or higher. But the code to accomplish this is absurd. See functioncheckTheBox4Plus() on line 8. It works :) but shouldn't.. Or is it the other way around?
Can't figure this out.HTML code for the element in question:
<a href="#" id="nRight">RECENT NEWS</a>
jquery mouseover statement:
$('#nRight').mouseover(function() {
nextRight = '#newsRight';
});
[code]....
This is just a page swapping images on the mouseover event, but i want to remove the mouseover events from all links when the the on click function is triggered,
This is the html code:
Code:
This the javescript code, the swapping image is working fine, but not the removeMouseover function,
Code:
I would like to write a jquery function that will work like this:
$(document).ready(function(){ifclick is made then do:
$("#wheel1").click(function(){ $(".wheels").show(500);});
leave the function
else:$("#wheel1").mouseover(function(){ $(".wheels").show(500);});
$("#wheel1").mouseout(function(){ $(".wheels").hide(500);});
This is what I'm trying to do: I want a simple image container to swap the image inside it by clicking the nav buttons on the right like 1, 2, 3.Here's my code:
HTML
Code HTML4Strict:
<div id="item1">
<div class="img-container shadow" style="background-image:url(images/gallery/tcg1.jpg)">[code].....
My jQuery code is not right. I want it to turn off the "hover" class and the "show" class of the others when you click one. I think I need some kind of if..else? how to write it? I have a bg image set on the container div so there's an initial image to view.I also need multiple of these on the same page!
Im trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear).
However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that thisblank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably.
I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
I found this---but havent figured out how to implement it in my scenario:
I found this---but havent figured out how to implement it in my scenario:
Code:
Source: [url]
I've been trying to have an image be placed during a mouse over or mouse click event. The closest to accomplishing this is having the image be replaced by the image I want to overlay.
View 2 Replies View RelatedI need a script to zoom a image.when i click on the image it should maximize in new customized window and the main window should be disabled.
View 2 Replies View RelatedUsing a UI dialog I'd like to load in 10 or so images. Each would be unique and after you click on one the following needs to happen:
1. Image appears on the parent page in a specified ID.
2. A "hidden" field is updated so that when the user submits the db is updated with their selection.
3. Dialog closes automatically.
That's it. Basically it would work similar to "datepicker".I'm using the latest 1.4 and ui and been making great progress as learning basics. I need to do the above and it seems like such a no brainier and or it should already exist but after 2 days of searching and trial and error...
What I've doing wrong, on first click it detects that the div is hidden and makes it visible, button on second click it does nothing:
View 1 Replies View RelatedOnce you in, click on the button with the sign 'Click To Start Shopping' The problem is, the Flash doesn't load I bought this flash template and i was supposed to edit the FLA file for the serverpath. I guess i didn't put the server path correctly. Below is the code in the .FLS file
[Code]...
Below is the instruction from the documentation: 3. Once you have everything correctly running on local, then OPEN THE FLA, go to first frame, layer codes, open “action” panel and set there the final pàth on your server where all the files will be located (create a folder especifically for this): [URL]
I have a basic dropdown css menu system. When a menu item is selected (ex: foo.html), the cluetip link opens a 450px wide window as expectedThen,I selectanother menu item (ex: bar.html). But when I return to link foo.html: and click the same clueTip link the clueTip link now opens in it's own window instead of the 450px clueTip window as beore would expect the small clueTip window to open and show the clueTip on each successive click as it does the first time. If I do a browser reload, the first menu selection works as it should, but only on the first click.If the menu is not used, the single file opens the clueTip correctly. Does clueTip get confused in a menu program?
// the cluetip code:
$(document).ready(function() {
$('#clickme').cluetip({
[code]....
Im trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear).
However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that this blank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably.
I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
-I found this---but havent figured out how to implement it in my scenario:
Source: [url]
-I found this---but havent figured out how to implement it in my scenario:
Code:
Source: [url]
I am still designing the website and want some flexibility. I am capturing the mouse clicks fine on top of an image, but the coordinates are absolute and not relative to the image. How can I capture mouse clicks relative to the image so that I can move the image anywhere in my website?
View 3 Replies View RelatedWant to click an image to open another image in a Wordpress Post
View 1 Replies View RelatedI have four links that use graphics to create an unvisited and visited state (using CSS). The link actually changes a section of text elsewhere on that page, so the user doesn't leave the page. The clicked, visited graphic reflects what text you are reading. You can then select a different link, and new text reflects the link you clicked on. What goes wrong is that if you click all four links, you eventually get all four visited graphics showing.
What I want is this. You click on the graphic and the graphic changes to visited. You then select a different link and that state goes to visited but the previous link that is visited too, changes back to unvisited. Therefore when you click on any link, that visited state is shown, and all others always reset to unvisited. The results is that the visited graphic reflects the current text on that page.
I've a function for my search form. Basically when you click on the form box where it says "Enter your search here" this value disapears when you click in the box. When you click out the box it re adds the value. It works if you click return on the keyboard and performs the search no problem. However if you click the search button with the mouse it removes the search term and replaces it back with "Enter your search here". This obviously will not return the search.
Anyone know how I can fix this so this does not happen on the mouse click?
I've used jsfiddle to add the html and javascript but it is not working in there, but works if you add it to dreamweaver and look at it within a browser. [URL]
This is the code:
<script type="text/javascript">
function make_blank()
{
[Code]....
I have this code:
$
(
'#region_dc').
click
[code]....
The click works fine. Check the checkbox, the hidden div displays. But when I uncheck the checkbox, I want it to go away.
I want to call the click event of the link (anchor tag) on the click of the button. I used this code below in the click event of button to call links click event and it works fine in IE.
document.getElementById('linktag').click();
But, this doesn't work in Firefox. I googled a bit and found that in firefox, you have to do something more to achieve this behaviour. So, I ended up doing this on button click to work in firefox:
var link=document.getElementById('linktag');
var e = document.createEvent('MouseEvents');
e.initEvent(
[code]....
The above code does the click on link when I click on the button. But my problem now is that I have defined a link as
<a href="mailto:abc@xyz.com?subject=abc&body=email body">email </a>
and when click is called and mailto links opens my email client, it somehow ignores the subject and body parameters of the link. It works properly when i actually click a link element. but it doesn't work when i simulate the click event by code written above. above dispatching event code somehow ignores the link parameters?
This is just a page swapping images on the mouseover event, but i want to remove the mouseover events from all links when the the on click function is triggered, this is the html code,
View 3 Replies View RelatedHow can I give a click on a link when it is just created and added to DOM?
None of this works:
function openProfilePage(profile){
$('#profile-link').remove();
var link = $('<a/>').attr({'href':'profile.php?user='+profile, 'target':'_blank', 'id':'profile-link'}).css({'top':'-200px','left':'-300px', 'position':'absolute'}).html(profile);
[Code]...
<html><head><meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"><title>emailsig.html</title><meta name="viewport" content="width = 400, minimum-scale = 0.25, maximum-scale = 1.60"><meta name="title" content="html email signature"><style type="text/css"> <!-- body { margin:0px; background-color:#fff; height:100% } html { height:100% } img { margin:0px; border-style:none } button { margin:0px; border-
[Code]...
I've a strange problem [for me]I want to make that:1 - click on the red, it goes up2 - second click on the red, it comes backbut it doesn't work if I used 4 times #red, but If I change it it's perfect.Where I made a mistake?
View 4 Replies View Related