JQuery :: Linkselect - Positioning Menus Off Bottom Of Window
Aug 3, 2009
I'm working on a website where we're using the jquery.linkselect plugin, and we're running into a situation where we have one of the dropdown linkselect menus happening near the very bottom of the users' window.
Imagine that we have a list of articles with abstracts, authors, etc. running down the left hand side in a div which is set to show a scrollbar if the results list gets long, and each article has a linkselect dropdown menu.
Unexpectedly, if you've scrolled to the bottom of the scrolling div and you're on the last item in the list, linkselect is allowing the menu to drop down extending past the bottom of the scrolling div and outside the boundary of the browser window. This is problematic, as it makes the menu items inaccessible.
We're looking for a way to have it automatically detect the bottom of the screen and reposition the menu accordingly (similarly to the way it does it to make sure it doesn't get positioned off the right hand side of the screen). I might be able to hack it, but was hoping maybe the linkselect team might be able to put something in more quickly and efficiently than I can. :)
Alternately, a way to specify that a menu drops up rather than drops down would also be a great solution to our situation (I didn't see that in the options.
Is it possible to create popup menus without using absolute positioning that take up no space in the flow of the document and appear with an onMouseOver()?
We noticed an issue with the jquery.linkselect plugin (version 1.2.08) today. When the container width would cause it to be positioned off the the screen it is repositioned incorrectly if there is no title element. I fixed this in anchorTo function by instead adding the width of the anchor if there is no title:
I am hoping that this is a proper forum to post to. I got an Ajax script from Dynamic Drive called "Dynamic Ajax Content" that loads external pages into a DIV in the Parent page. The effect is much like that of an iFrame. I am loading videos into the target DIV. All of that works fine, but visibility on the parent page seems to be a problem. By necessity, I must(?) place the div close to the bottom of the page. However, when I click on a link that loads the video, I would like to have the parent page "jump" to the DIV with the video.
It is probably easier to visualize this than for me to try to explain it: [URL] For instance, if you click on "The Natural", the video indeed loads, but it is not 100% viewable since it is at the bottom of the page. I tried to emulate an <a name=#jump"> <a href="#jump"> scenario, but since javascript is controlling the generation of the Ajax window, it was to no avail (I am embarrassed to say my javascript skills have eroded a bit!).
I place items at absolute locations on my LONG window. When I scroll the window My Absolute is only relative to the Viewing Area and tends to move up as i scroll my window.
Is this the normal behaviour ?
I need to have my item fixed to the bottom right hand corner no matter what is happening to the window, including scrolling.
Does anyone know how it would be possible to create bar at the bottom of the browser window that doesn't reload when you navigate thru the site. A good example is the chatbox that Facebook has. When you click links throughout the site the chat box is constant and doesn't reload.
The issue seems to be that when the buffer becomes extremely large instead of scrolling to the bottom of the window, there is a gap at the bottom instead.
Here is the test code I've been using, and it allows me to get to around 18000 pixels before the gap begins...
window.scrollTo(0, Math.max(document.documentElement.offsetHeight, document.body.scrollHeight ) + (window.innerHeight || document.body.clientHeight ) + 100); window.scrollBy(0, Math.max(document.documentElement.offsetHeight, document.body.scrollHeight ) + (window.innerHeight || document.body.clientHeight ) + 100); The issue is really driving me crazy, hopefully someone will be able to help me out.
Please do not suggest putting a link at the bottom of the content (IE: <a name="bottom">asdf</a>, url#name) for this is not an option.
I am opening a site soon that will have a preliminary, invite-only beta system to work out bugs, etc. I need to make a feedback system and I already have most of it figured out, but I need to know how to make a button or image stay at the bottom of the screen.
For example, take a look at klout.com. They have a feedback button on the right side that stays in the same position as you scroll down the page. How can I do this, but keep the button at the bottom of the page?
I don't want to have to add any extra containers, etc. I have my layout entirely designed and I want the button to be easy to add/remove. I'm thinking I would just need to run a script that creates maybe a div that holds the button, and position the div at the height of the window minus the height of the div. But how can I make it stay there as the user scrolls?
I have seen in some forums when members respond to the questions posted, a small window popup automatically and closes after few seconds. Can it be done using Javascript?
I'm having an extremely hard time finding out how to do this. I'm looking to attach the footer of my site to the bottom of the browser window. The site uses an accordian/slider as it's UI, so the footer needs to "float" above all the content and attach to the bottom of the BROWSER window (not the end of the content), so that when the slider comes down and some of the content is below the bottom of the browser window, the footer remains at the bottom of the browser window, even when the page is scrolled. I'm tearing my hair out trying to find a solution to this issue. Here's the page with the footer as a simple div (it's not even fixed to the bottom with CSS right now because that does no good when the page is scrolled):[URL]
I am trying to make a form where the user is only able to select an option from one of the drop down menus and if they click both then submit an error should pop up telling them to select just one. Now I have found this code:
<SCRIPT LANGUAGE="JavaScript"'> <!-- function validateForm(){[code]....
the first problem is that my menu must be named "id[2]2" which causes a problem due to the bracketed 2 and the 2 after. Is there any way around that?the second problem I forsee is that this will only work with 1 drop down box being unselected. I need a code that will give the warning if nothing is selected OR if something is selected in both drop downs.
I hired a programmer to develop a drag and drop system for my blog. The user should be able to browse one of my blog entries and click, drag and drop an image from my entry to a fixed bottom bar on that page.The problem we are facing is that when dragging an image, it wont place it on the bottom bar until the whole page is scrolled down to the bottom of the page. This is a problem because some of the pages can be very lengthy
I create an img, map, and area element dynamically. If I set the img to absolute position and set its top and left properties, they are removed as soon as I call $('map').hilight();. I can actually see the absolute position for one second, then the img element fly's over to the left side of the screen.
The menu bar works OK. But the themeswitcher resolutely locates in a screen-wide "overflow" of the menubar div, and doesn't have the correct nifty dropdown (it is squashed up to the height of a single line).
I expect the root of my problem is a misunderstanding on my part of the CSS.
I am trying to modify a jquery plugin (Infinite Carousel) to present some boxes instead of a plain image content. Here is theDemo I m not sure if this is more styling or scripting issue but I am encountering with tow problems as:1 - Contents of The Second round (First Click to Right) Doesn't fit inside the wrapper2 - There are some unknown dots ... after the Twelve and before the first item(in First click to left or Second Click to Right).
I am creating a single column fluid layout and have run into an issue when positioning the images I display via Mike Alsup's cycle plugin. I dynamically load a "content" DIV with three other DIVs, one of which is controlled by the cycle plugin. The other two DIVs are positioned as expected, however the DIV that cycle is handling has positioning CSS added to it inline that is pulling it out of my page flow. (When I disable the cycle code the single image I load first displays as expected.) Here is the code from that particular DIV:
Is there a parameter or method for positioning thickbox? The center of the page is usually ideal, but not always. I assumed something like this would work, but it doesn't seem to have any affect.
I am trying to arrange 15 divs into a 5x3 grid.The divs have an id of piece1, piece2, piece3 etcI figured I could run a loop wherein each div is positioned to the right of the last.For each div, I'm trying to store the current position and width into variables then move it to the right by the number of pixels the div measures widthwise.This would position 5 divs horizontally and I am still unsure of how to get the next row of 5 divs positioned under the first and so on.This is what I have so far:
JQuery for (var i=0; i<x; i++) { var pos = $("#piece" + i).offset();
I'm trying to create a sliding panel using css and jQuery, sliding up from the footer of our page. The panel is acitvated by clicking the "newsletter" link (will be used to display a subscription form) in the footer. Functionality looks good, but there is a problem with the look and the positioning. First of all, the positioning is off. It fits seemlesly in the FF I used for creating this effect, but on various browsers and resolutions, the div is displayed higher or lower in stead of "glued" to the top of the footer div. Secondly, I'd like this div to be 100% wide, just like the footer below, with a 940px centered div within to include the content.
If the screen resolution is small enough, or the window is small enough the calendar that appears when a user clicks the textbox for the datepicker appears on top of the textbox - usually it appears below.
I have some text links at the top-right of my page, and if the window is small enough, the datepicker calendar goes underneath these text links.
Is there a way to have the popup calendar ALWAYS on top of every element on the page? If not, is there a way to have the datepicker popup calendar ALWAYS appear below the textbox?
I've seen several posts around this issue but nothing that seems like a definitive resolution.Cycle defaults to positioning the slides at top:0 and left:0 within the container div. I want them to be bottom:0 and left:0 within the container div.
