JQuery :: Check To See If A Radio Button Is Selected?
Nov 14, 2011
I have some code that runs when a radio button is clicked (and thereby selected) but the problem I am having is that when I refresh the page, the radio button is still selected, but the associated code does not run. How can I check to see if a radio button is selected in this situation so that I can apply the appropriate code?
I have 3 radio buttons with the same name ("myradio"). The value of each is a different URL (eg. value="http:[url]...)I have a link underneath these (<a href="#">Send</a>). I would like the selected radio button's value to be inserted into the href of the link, and if the user selects a different radio button that this changes.
I have a form that will dynamically place a number of radio button groups on the page. I don't want the user to be able to submit the form until a value has been chosen for ALL fields. I have hidden the submit button with the though of showing it again once ALL fields have been checked. My code so far...
$(document).ready(function () { //Hide the submit button $('#MainContent_sbmtButton').hide(); //Change background of question to show clearly which questions have been answered
[code]....
This doesn't work as expected. It shows the submit button when any of the radio buttons are clicked.
I have 4 groups of radio buttons (4 different questions using radio buttons) that I need to be required but only if a check box is selected. Also, is there a way to disable these radio buttons if the check box has not been selected?
I am trying to create a script that will display content based on if aradio button is selected, and if the other is selected would hide thecontent. Now, each of these radio buttons are part of a radio group,so their names are the same. Most examples show nput:radio[@name=item] Since I have 2 items that have the same name, I can't usename, so I thought I would try id or value. It isn't working. If I addonly the show, whenever you select either radio button, it shows, andif I add the hide code, it doesn't work at allHere is what I have right now.
I'm trying to make a form element only appear if a radio button has been selected.I have two buttons (yes and no).If Yes is selected I'd like a text input field to appear.I have the following:
my group of radio buttons are named "scheme". I have tried this from a few angles but can't crack it. Ideally I'd like to use input:radio[value:yes]. It's already a required value due to the JQuery validation plugin, and I simply need it to make the other field visible when yes is clicked on.
I have it set up so that there are three frames (frames and the use of javascript are encourage for practice) "bar" on the left with navigational options, "main" in the center where the body of the drill is presented, and "feedback" along the bottom where the feedback will appear.
My issue is that I have everything working except the form! I'm not sure how to make it so that upon clicking the submit button the feedback is presented in the "feedback" frame. This was suggested to me but isn't working, maybe I have a mistake somewhere? Or is there another way I can do this?
<html> <head> <script type="text/javascript"> function CheckCheckbox() {
So I have a dropdown box and when a certain option is pressed will show other fields... if not they stay hidden. However, I also need it to check a radio button that should remain showing.
Right now I have <script type="text/javascript"> $(document).ready(function(){ $(".dnuHide").hide(); $(".dnuHide input").attr("disabled","disabled"); // If option Other is selected for institution type, show text field for Other $("#region").change(function() { var val = $(this).val(); $(".dnuHide input").attr("disabled",(val=="DNU")?"":"disabled"); (val=="DNU")?$(".dnuHide").show():$(".dnuHide").hide() }); }); </script>
How would I modify that so I can also have ()Option 1 (*)Option 2 (already checked) change to (*)Option 1 ()Option 2
I have set up a JSFiddle to demonstrate what is happening:[URL]... Basically if All content types is checked already and is clicked when checked then searchAjax should not be invoked. It currently invokes the function. When it is not checked and clicked then it should behave as it is now (disable sibling radio button and uncheck all associated checkboxes).
I have three radio buttons and one textbox. If user select one of those radio buttons and type something in the textbox which is the value of the textbox, I want that value to be the value of the radio button that is selected, now the user may enter the value into the text box and then select the radio button or first select a radio button then enter something to the textbox, anyway the value of radio button should be equal to textbox value that user enter!
The first time you click a radio button in IE8, no value is returned at all (tested with document.write of the 'check' value), with an error "'null' is null or not an object". The second (and rest of the times) you click any of the checkboxes the wrong value is returned, it returns the value of the currently checked button (which we checked a moment ago) rather than the one we have checked the second time. Does Internet Explorer have issues with this onchange function method? Or is something wrong with my code?
I am trying to create a javascript that will display a confirmation message when a user submits a form and has specifically selected a particular radio button.
Assuming the user selects the second radio button (Value 2), how would I display a message that states "Are you sure you want to do value 2?" and then also includes a "Submit" and "Cancel" button?
i am making an application on my website using javascript and html. i have knowledge in php and html, but not much at all in javascript. the application is split up by div tabs and inside the tabs is a list of different links to other div tags that have radio button groups inside them. im sure this is very basic but i want the value of the selected
radio button to be displayed in a table on that same page. so if someone select option 1, it would display option 1's value in the table at the bottom of the page. I know i could do this in php when i submit the form but I need the application to not need to refresh the page if possible. Below is a link to where i have the application and here is the code.
Im trying to figure out how to add different radio if its selected or not
example:
Radio_Button1 value="5": Selected Radio_Button2 value="15": Not Selected Radio_Button3 value="25": Selected Radio_Button4 value="35": Selected var addingitup = ??? and im lost??
I have a long list of events and I want somebody to be able to select one of those events & there will be a text box that shows the address pertaining to the event selected. Exactly how this website did here: http://svacpa.com/live-webinars-and-roundtables-with-demo/seminar-registration/
I want to achieve when first radio button is pressed form doesn't validate and when second radio button is pressed it does validate.I tried do it this way by assigning var to radio buttons an then checking that var on form submit but something is wrong:
I have a pair of radio buttons (yes and no) as answers to a question. When the yes radio button is selected, I need a text field to be displayed underneath it. Does anyone know how to do this?
I am brand new to JavaScript and cannot easliy locate JavaScript code to require value in a text box if a specific radio button is selected and validate when user submits the form. Below, if a user chooses the "other" radio button, they must fill in the "othertext" box.
I have a form that has four questions with yes no answers (using radio buttons) - if a user answers yes to any of the questions a textfield is revealed and they have to give details. I've firgured out the show/hide textfield but I want to use some form of form validation so that if a user selects Yes to any questions then the relevant textfields are required and must be filled in - so only the textfields in the questions with a Yes answer are required.
I found this post: [URL]...and the response by JMRKER was almost exactly what I wanted - the only problem I can't figure out how to extend his code to four possible text fields. I don't think I've explained this very well but hopefully you'll know what I mean.