Dear friends, I'm using Jquery like this
$('#ArtechGallery,#DomaineGallery').click(function () {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "FetchGallery.asmx/GetGallery",
data: '{ "FolderName" : "' + DivID + '"}',
dataType: "json
[Code]...
how to prevent it, I need to remove this line before it creates second time..
I am developing a web application in which user can change the theme of the page.
So for this i am changing href attribute of the link tag on selection of the perticular theme.
Problem is that when i change the theme whole page gets messed up till the new css fileis fully loaded.
So how can I check if the CSS file is completely loaded or not?
I want to know if there is a possibilty to check with JQuery if an image can be loaded or not? Because when an imgae can't be loaded the Jqzoom should not work, because the big image (which is for the zoom) could not be loaded. Imagin I have hundreds of pictures, how can I check if this big image could be loaded or not?
View 4 Replies View RelatedI'm trying to use cluetip jquery plugin inside a message_container div which will be updated once in a while through ajax. The plugin works just fine in any other div, but it seems that in message_container div the already loaded external javascripts are not present ie the plugin doesn't work. Do you have any ideas what would be a proper solution for this issue?
View 1 Replies View RelatedWe have to login to a http page so that I can surf the net. But, that login page also requires me to keep that page open which is very irritating. The page have javascript that checks if the page is loaded every 180 seconds, it its not loaded, I am logged out.
I want to simulate a browser using a programming language like python or using curl or anything so that I am not forced to keep the webpage open.
How can I do that? I have uploaded the source code of the webpages of login_page, javascript and ajax scripts used.
I am not actually sure as to how it is being accomplished so I dont know how to simulate it. note the sendLiveRequest function in javascipt script.
[URL]
I'm creating an AJAX page that is built using a PHP Class, ie the php looks a bit like this: PHP Code:
$wp_page->addjs('../var/savepolicies.js')
$wp_parser->page = "userpolicywindow.php";
$wp_parser->addlink("Home","../index.php","");
$wp_parser->addlink("Logout","javascript:logout();","");
$wp_parser->getpageid("501");
[Code]...
within this page that has been created, there is an AJAX tree folder which calls another page to be loaded into a DIV by AJAX again. Code:
[Code]...
I don't know why it doesn't work because the page has been loaded with the JS file, but as soon as the link is added afterwards it doesn't work. I take it this is because it doesn't know where to find the JS, but how can I overcome this?
i need a javascript code to check whehter the particular swf file has been loaded or not.Is it possible using javascript?
View 3 Replies View RelatedI was wondering if anyone has figured out a near-perfect way to check if the client has all the elements fully loaded? Not talking about all the css and text loading and the event triggers while the client is viewing images load: I mean the event auto-triggers after all the images are fully loaded, along with the css, text content, etc.
(P.S. Not talking about AJAX. Literally when somebody visits a page itself, the elements all completely load first, then the event fires.)
I'm trying to bind an event handler to a button in a page loaded via Ajax. This procedure should apply to every page I have to load via Ajax. I have tried two things: first, I declared the 'click' event handler for the button like this, and just did my ajax request. Here's the code:
$("#close_button").click(function(){
alert("This should popup");
});
$.ajax({
url: 'js/ajax/text.html',
[Code]...
what i'm trying to do is to acces the content loaded via AJAX but in an other way than by a callback function.i have a div where the data will be loaded via ajax, the data is represented by a list of folders and when i click one of them i want to load then the subfolders and so on, but if i use the callback function this is not gonna be dynamic..cause i don;t know how deep is gonna be the tree.[code]but if i do in this way....first time it works....so id i click <ahref="folder_1">folder_1</a> it loads the subfolders...and if i click then on of the subfolders loaded with ajax it wont work anymore to see the subfolders in the respective folder.
View 5 Replies View RelatedFor starters i'm new to jquery and javascript, hence my post here. I've tried to do research but I'm not finding the answers. Here is the problem. the web page i'm working on has 2 area's or panes. one that changes dynamically via ajax and one that stays the same to control the dynamic area. The dynamic content is loaded with the following function to load a given page into the <div>.
[Code]...
When the content is loaded into the div jquery does not work. More specifically i'm using the jquery ui datepicker. The page that is loaded via loadPage() work fine if its not called by the function. but once it is it seems all javascript does not function.
I've got the following code:
[Code]...
I have question about JQUERY. Im using
[Code]...
For example I have a page: [URL] On this page I use $.ajax:
$.ajax({
type: "GET",
data: "data=123456",
dataType: 'html',
[Code].....
where temp.php - [URL] On temp.php I use requests for DB with param from $.ajax - data=123456. How I can protect page temp.php? For example, somebody typing [URL] and then he can get all results. I found one solution - using if($_SERVER['HTTP_REFERER'] == "http:// mysite.com/content/") {....} But Am not shure that it can realy protect my page?
$('#food_rate').load('/ajax.php?x=get_food');
$('#tax_rate').load('/ajax.php?x=get_tax');
$('#mood').html(function(){
return ($('#food_rate').html()-$('#tax_rate').html())*10;
});
$('#mood').html always contains the value of the values food_rate and tax_rate had before I loaded the new values in. (Before Line 1 and 2 happen)I already red, about event bubbling and event delegation, but the html-elements fax_rate and food_rate exist from the beginning, and only their innerHTML does change.
So, I'm working on a website that has tabs and nested tabs. So far they all work perfectly, there is just one thing I can't seem to figure out. There is a tab on the main site that is for members, so they click on it and it brings them to a login screen. Then when the user enters in the username and password, I want it to load another page with more tabs, but in the current tab. The page (with tabs) to be loaded is in a password protected part of the site.
View 3 Replies View RelatedI'm loading some content on a page with ajax. After it's loaded I can't seem to perform any more jquery on it. How do you get around this?
View 3 Replies View RelatedI load data to a div dynamically $.get(test.php, { cmd: cmd, id: id},function(data){$('#files '').html(data);});
The retrieveddatais in a table and looks like this
test.php
<table class="files_table">
<tr eID='1'>
<td> Content # 1</td>
[Code]....
I have some simple tooltips on my site that load the content of the "title" tag into the tooltip. I am currently using this plugin[URL].. I have tried several others. They all work fine for static elements, but the main content of my pages are loaded by an ajax load() call. The tooltips don't work on any this content loaded via ajax. Why is this happening and is there a way to fix this? Or maybe a tooltip plugin that will work for this?
View 4 Replies View RelatedI have an ajax function which works fine.
On the call back i append a div with an ID of full_detail.
The HTML generated via ajax include images. I would need to know to call a function once all images are fully downloaded, something similar to [code]...
Of course using the above example does not work as the window is already loaded and its content is changed.
I have a problem in the jQuery in executing a method. The Method is executing more than one when i load(via Ajax) the contents(Button) in to a jquery tab.It happens when i close the currently loaded tab and reloading the same without refresh the page. If the do the same (loading more than one) the method for a button is executing the no of time the contents loaded.
View 17 Replies View RelatedI am using the code below to load a resource via AJAX that contains a <ul id="photoCollection"> . That list has an image in each of its <li> tags. This markup and images are getting loaded as expected into the target Div#photoCollectionWrapper.
$('#photoCollectionWrapper').load('/photo_collections/1/photos', photosLoaded());
Once the images are loaded into the target div with AJAX I need to select them so I can alter their widths and heights. So far, I have been unable to select them as expected once they are loaded. However, If I just load them in a new page with NO AJAX, then buy using a simple .load() event handler I am able to select them after they have completely loaded as expected. No problem.
But when loading the resource via AJAX I am unable to select them at all. I am using a callback that gets fired after the AJAX is loaded. Then in there it seems "logical" to call my .load() handler on the images loaded in via AJAX. Here's a sample of some code just to illustrate the idea. The code below actually will not run at all. If I remove the .load() bit it will, but then Alert always returns null.
function photosLoaded() {
$('#photoCollection li img').load(function() {
alert($('#photoCollection li img').height());
}
}
I have also tried many css selector variations to try and select the target images, but to no avail. I know for sure photosLoaded() is getting called. I just can't select the elements that the AJAX call brought in.
I want to activate an image slider that is placed in a div loaded through an Ajax request. I'm using the JQuery Plugin Anythingslider. I've tried to use code similar to this without success:[URL].. The slide script works if loaded together with main page.But how do I activate a slider placed in a div that has been loaded through an Ajax request?
View 3 Replies View RelatedI've googled the heck out of this, and although I'm finding plenty of solutions, I'm having trouble understanding them. I'm very new to jquery, and brand new to ajax. My problem is, I have a php application using several jquery effects. I've just started learning ajax and it is going really well, this stuff is incredible! But all the ajax loaded data loses the jquery effects. I get that it is a DOM issue, and I've seen that others have used "live" (i think?) to fix this, but I honestly just have no understanding of how toimplementanything that I'm seeing.
This is part of my ajax...
And this is the main effect I need to get working.
I am trying to assign a value to a java variable inside the script that I am calling via ajax but once the call is over it shows variable as undefined:
$.ajax({
type: "GET",
url: "getdata.js",
dataType: "script",
[Code].....
I'm currently following this tutorial on loading pages with Ajax:[url]...
For some reason when a new page is loaded via Ajax by clicking a link on the left-hand navigation, the new content returned has a large gap that appears on its left-hand side. My question is what's causing this and how can it be fixed?There's not much in the source, so reading the code shouldn't be difficult.