If i remember correctly, even with an ajax call where the method = "get" it should show up in the url but, it doesnt seem to.....what's the issue with the code?
The following makes the arrow disapear when clicked
The following is the ajax call to change the vote
I've experienced have been down to IE (trailing commas in arrays, etc). This latest problem stops a page which works great in IE and chrome working at all in FF.
The code below basically loads a table of data by post request. Then applies various functinalities to the elements contained within the loaded data. In FF the table which should be loaded by post request just does not display at all.
function update_table_row(obj){
var rel = $(obj).attr('rel');
$('input#submit_'+rel).removeAttr('disabled');
$('tr#row_'+rel+' td').css('background-color','pink');
[Code]....
I am new to jQuery and can't get this to work properly. I am loading content form a php page through an AJAX call. Based on the data that is returned I want to fade in a DIV or keep it hidden. Therefore I have a if construction that checks the data that was inserted in a DIV from the PHP page. If the PHP page returned 'No data' the DIV should remain hidden. The loading part works OK, but somehow the hiding or showing of the DIV doesn't work. What am I doing wrong? Is the syntax correct? This is what I have now:
<head>
<script type="text/javascript">
$(document).ready(function() {
[code]....
I've been having great difficulty with this simple script. From every thing I've read this should work.
$(document).ready(function(){
$(".add_to_profile").css("background-color", "yellow");
$('a.bookmark').click(function (){
var addedbookmark = function (data) {
[Code]....
Below is my code, please ignor the comments etc. its very basic. i have a set of data in a var. i am displaying the highest value in that set of data. however one of my sets of data the highest value has 2 occurancies so i want to display both. atm it just displays the first occurance of the highest value and then stops as opposed to all occurances. if you run my script you will see what i mean.
[Code]...
I am using .ajax() to access cross-domain data using JSONP. Because I need to be able to cache the data I want to use a static name for thejsonpCallback function, so I have set the jsonpCallback option in the .ajax() request. However that appears to requires a global function whereas the auto generated function didn't (well maybe it did but that was all hidden from me).
I definitely need to be able to cache the results. Ideally I wouldn't have a global function handling the data. Is there another way to do this? If not what is the best practice way to go about using a global function these days and how do I provide it with the context of the object/module it was called from - which is where the data is needed?
Relatively new to jQuery but have a problem with getting data to display.Using a webform with 2 forms. User slects and inputs data into the first form, clicks a button then using jQuery .ajax submits the serialized data to a php script. The script processes the input into multiple paragraphs of text which is based on the input from the first form.The data is returned to the webpage and displayed in a text area (of the 2nd form) where the user can edit it to fine tune the wording. The 2 forms are displayed in different tabs so it is easy to move back and forward between the 2 forms.
The problem occurs when the user goes back to the first form and enters or selects different text and then click the submit button to generate a whole new text for insertion into the textarea on the second form. For certain fields the modified text is displayed.However if the whole of the text in the textarea is deleted, then the user clicks the submit button to re-generate the text content area then nothing at all is ever interted into the textarea. If have user alert to check that data is returned from the php handler and this text is correct. BUT when I click on the tab to see the textarea (id is "draftrec") there is no text inserted. The relevant function is below and the line that should insert the text into the textarea is:
$("textarea#draftrec").html(data).show();
//------------------------------------------------------
$("form#form1").submit(function(e){
[code]....
I would like to use jQuery to prepopulate a form - ie make a call to a php program to get data from a database and pre-populatea form with appropriate data for the user. Can anyone point me in the right direction for some examples on the simplest way to do this?
View 3 Replies View RelatedI wonder if i can make the variable data which is [data] in jQuery.post( url, [data], [callback], [type] ) dynamic. for instance, this is the form i want to send,
PHP Code:
<form action="send_xml.php" method="post" enctype="multipart/form-data" id="form_send"><input type="checkbox" id="var_1" class="checkbox"/><input type="checkbox" id="var_2" class="checkbox"/></form>
[Code]...
I am writing a small data entry screen that will post the form data to a page and return a message. But i cannot get the Success or Error functions working properly.
Here's the code where strData is the posted querystring of:
I'm not sure whether it should be in a form and using the onsubmit or click of a button.
I am still new to jQuery and I am trying to figure something out. I have this code:
[Code]...
This is working fine on itself. What is does is when I click a link it loads data into the following div. When done loading it slides out. But I want to change the appearance of the slide. I have tried to do that like this: $(this).show("slide", { direction: "down" }, 1000); But this doesn't work. When I check firebug it says the following: o.easing[this.options.easing || (o.easing.swing ? "swing" : "linear")] is not a function
Im trying to convert the contents of a canvas into a data url and then post it along with other inputs to the controller in order to save an image.
The PHP:
<
formmethod
=
"post"accept
[code]...
I have just started to learn about JQuery and wanted to learn how to retrieve data from an API.
I used the Flickr example provided here [url] and just changed the relevant code to point to the 500px api.
<body>
If I launch the following URL I do get the results properly [url]
Here's a sample of what the result looks like:-
I don't get any results when I run my code page. What am I doing wrong?
I am trying to try jQuery 1.4.3 updated .data() method with HTML5 data attributes. The way I understood these changes is that an element with these attributes would automatically have their data populated by .data(). For example, if I have an element:
<ahref="#" data-cheese="cheddar">DataElement</a>
I can access this with .data('cheddar'). This part works fine. The issue I am having is that calling JUST data like $(this).data() just produces an empty object. Is this how it should be expected to function?
I am interested in creating a footer that always shows on the page even when the user has to scroll down to see the rest of the page. It should be sort like an iframe, but I am interested in a achieving this using a DIV element instead. I am not sure how this kind of effect is called and created.
View 1 Replies View RelatedI installed the Superfish Module and all appears to be workingproperly, My question is The Original Horizontal Nav is still showingup? How do I Disable?Also, The links with drop down's are gray and the links with nodropdown are red?
View 2 Replies View RelatedThis is a strange problem, because I have done this about 50 times, but this time it is not working. I want to show a loading gif when a user submits a form.
<form id="uploadForm" enctype="multipart/form-data" action="" method="POST">
<!-- DOM omitted. The form submits just fine.
<div id="loadgif"></div>
[code]....
I have a hidden DIV, which is going to cover all of the screen as part of a lightbox. I wrote my code based on what I found at [URL]. When I click on the link to run the lightbox, the div isn't showing even through the z-index is the highest on the page. I've also tried seeing if it was a corrupted version of jQuery.
<style type="text/css">
#video1
{
position:absolute;
top:350px;
[Code]....
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "[URL]">
<html><head>
<meta charset="utf-8">
<title>Test</title>
<link rel="stylesheet" href="css/style.css">
<script src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var lastTouched;
var lastType;
var lastContent;
var boxTop = 125;
function resizeElements() { .....
What is happening is that I have an accordion with sublevels, but it's not working properly. When I click on Test1, it should only show test2 and test7, but it is showing test3 and test5 (that are insinde test2), that only should be visible when clicking test2.
The state my code is in, i can only set a timeout for the div to dissapear, but i want it to stick till it loses focus.
$(document).ready(function(){
var img = $("#myPic");
var pos = img.position();
img.hover(function(){$("#floatdiv").show(1000);
[Code]....
I have this code which when you click the delete button of a particular row, it shows up the div .delete over that particular row, and when clicking on the cancel button on the .delete div, it'll close that the .delete row revealing the .row div again (the .row div doesn't actually hide, I handle the overlay with z-index). However, I want it so that if one .delete div is already shown I want it to close it before revealing a new .delete div, so you can never have 2 .delete divs open at any given time. ere's my code at the moment:
$(".deletebutton").click(function() {
$(this).parents(".row").siblings(".delete").show('fast');
});
$(".cancel").click(function() {
$(this).parents(".delete").hide('fast');
[Code]...
I'm trying to work with a jquery dialog, starting with code from a site at [URL]. I set up a small sample php and modified the code to make an ajax call. It all worked correctly, but when I tried to migrate the code to an existing php page, what happens is the back ground changes to the grayed out color, but the dialog box does not appear. I put alerts in each of the jquery procedures, which all fire, but I can't find the reason why the dialog doesn't show.
The code seemed pretty straight forward, but I was modifying an existing php page I didn't write, so I'm not sure if I'm missing something being new to jquery. Here's the code from an called html file that includes the jquery code followed by the php page code I changed to include the dialog div tag. I removed most of the php code leaving just the final page code that includes the div for the dialog. The css is straight from the sample code in the web page listed above.
<html>
<head>
<title>Test Page</title>
<script src="[uRL]" type="text/javascript"></script>
<link rel="stylesheet" href="jdialog.css" type="text/css" media="screen" />
<script type="text/javascript">
$(document).ready(function () {
// if user clicked on button, the overlay layer or the dialogbox, close the dialog
$('a.btn-ok, #dialog-overlay, #dialog-box').click(function () {
$('#dialog-overlay, #dialog-box').hide();
return false;
}); .....
at [URL] I am using jquery cycle in 5 divs. As you will see, in 4 of them it works perfectly, but in the main image it is only showing every second slide and fading to blank on the others.
Yes, all the images are there.
The weird thing is that I essentially copied and pasted this code for the lower areas and they worked perfectly straight off.
I am not sure what I am doing wrong I am using the Jquery.Validateplugin and it has a remote field so I did this
[Code]...
[URL]- that is my site when i hover over the menu it seems to be blocked by the main content. look at the site to see what i mean.
View 1 Replies View RelatedI am using the "jQuery UI Multiselect" from [URL] I need to have it inside a <div> set with "display: none;" from the start. The user then clicks a link and the <div> tag opens op.
The problem is that whenever I open the box the Multiselect does not show up correctly, it shows up as a 3pixel wide stick. You can see an example at: [URL]
here is the eax.html code:
<link rel="stylesheet" href="css/common.css" type="text/css" />
<link type="text/css" rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/themes/base/ui.all.css" />
[Code]....