I'm trying to submit form data to mysql database. The POST form action calls a javacript/ajax httpRequest. My php script has a redirect at the end of it on completion of data submission. My problem is after submitting the form, the redirection works, but no data is entered into database. I'm wondering if there is a problem with my httpRequest.
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I've built a form in a mobile app where the user chooses a photo from the camera roll, they hit an upload button and the image is submitted to my server. The file is renamed by the PHP script and moved to the correct folder. All this works great.
I need a way to send the new filename back to my app and I'm not sure how exactly to do that.
The reason I need the name back from the PHP script is because I will then ask my users of the app to fill in a title and description and then i just want to submit all of the data together.
I have a form that submits a POST request when data is submitted.
A Servlet then processes this POST request and a JavaBean is used to make some calculations. The HTML response is not generated within the Servlet but instead I forward the request to a JSP to generate the response. - This all works fine.
However, I am stupidly suck trying to validate the form on the client side with a Javascript function before the form is submitted.
Here is my index.jps:
Regardless of whether incorrect input is given, the data is still POSTed to the server and calculated on or a Server Side error is given.
Am I correct in calling the function onclick?
The validation essentially needs to be so that:
- Student field contains a string
- Score1, Score2, Score3 and Score 4 contain a number between 0 and 100
I am trying to create a form that writes text to an HTML canvas when submitted. Eventually, the function that writes the text will be more complex. The problem is the text only appears briefly, because the function is only called once when the form is submitted. I want the function to be called continuously after the form is submitted.How do I do this? I have had very little experience with JS.A lame (failed) attempt...
<html>
<head>
</head>[code]......
I am re-developing my website and want to use some Ajax/jQuery in it (so I am learning as I go) and I am not sure if this is possible so that is my first question:I have a registration form and I would like to know if after the person registering has completed their first and surname and the 2 sections of their postcode if I can use jQuery to run a PHP script to see if they are already registered before waiting for the form to be submitted and running a script then.I am thinking onkeyup (or similar) after the last field is completed but I don't know how that would work needing to also use 3 other field values.If this is possible, can anyone give me any ideas of examples that do this or how I can go about passing all the variables and running the scripts at the correct time.
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View 1 Replies View RelatedI have a form,
It has multiple submit buttons (Save/Quit)
I want my form calidation to run when I save and not when I quit.
I still want to submit the form when I quit.
So how do I conditionally run the validation?
i have tried using submit() command to submit the form but the form does not get submitted. I wonder why.I am using lotus designer to develop the form:
var f= document.forms[0];
var answer = confirm('Do you want to referback?')
if(answer ){
[code]....
I have a form called "theForm". How can I tell if the user has submitted the form or hit the submit button?? Is it..
if(document.theForm.onsubmit()){
do something
}else{
}
Here is my Javascript / HTML:
javascript Code:
Original
- javascript Code
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I am relatively new to web programming (1.5 years) and this question just occurred to me.
I use jquery form validation to validate forms on my site. If my browser has javascript disabled, what is stopping someone from submitting crap through my form?
I tried disabling javascript and submitting a form on my site and it posted.
Is there a way to make it so if the user does not have javascript enabled the form cannot post?
I was wondering if there was a way to keep a form from being submitted with erroneous information.
View 3 Replies View RelatedI have this form which opens a new page after submitting the info. I would like to be able to clear the form after it's submitted.
HTML Code:
<form name="login" method="post" action="https://www.domain.com/register" target="_blank">
<input type="hidden" name="iso" value="gb" />
<input type="text" name="username" value="" />
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Suppose I have a form as follows:
<script>
functionABC()
{ alert("Hello world")}
</script>
<form name="form1" action="test.php" method="post">
<input type="submit" value="submit" onclick = "functionABC">
</form>
My question is : When I press the submit button, after the
onclick function is executed, will the form be submitted too following
the execution of onclick function?
I'm trying to submit the form normally as well as by pressingCtrlEnter. Yepp, the same task.What I'm doing is the following:
var validator=$
"#myform"
.validate
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I have a form on page 2 and I want the information submitted on the form to be sent to page 3. How do i do that?
View 7 Replies View RelatedI have a form with fields created dynamically using javascript. But these are not submitted. The submitting shows only these:
selectedProvider yahoo
email mittiprovence@yahoo.se
password nesquick
formSubmitted 1
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I'm trying to display information submitted by a form using javascript. I have this code but it only works for the first question and it doesnt work on click (it works when you select the arial button). I want my users to be able to select a button from every question and then press submit and the infomation will display what they have selected if that makes sense?
Code:
<style type="text/css">
.noprint {[code].....
I want to use Javascript to submit one of two forms, "myform" and "myotherform" If the value of TotalMinutes is greater then 0, I want to submit MyOtherForm, if it is 0(empty), I want to submit MyForm The code I am using:
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I have a requirement. I have to submit a form [which will open a new window once it is submitted], and immediatly I have to close the orginal page. Currently I am using window.close() statement after formName.submit(). But it closes the window before submit completes. So I tried with window.setInterval("window.close()",1000); It worked for some time, but when the form submition takes long ... same old repeats :(
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I have some function to fire when I click a submit button. When I do that a form does not submit anything, it just fire my function etc. Here is my code:
$("#hm-submit-form").click(function () {
$("#nav ul li.products").delay(200).fadeIn();
$("#nav ul li.agel-tour").delay(600).fadeIn();
$("#nav ul li.compensation").delay(1000).fadeIn();
$("#thanks-box").delay(200).fadeIn();
$("#thanks-box").delay(1500).fadeOut();
$('#target').submit(); //this I guess should submit a form
What I want to do is replace a form with the submitted content. As an example, The form is submitted using the jquery.form plugin. The content is saved to the DB and a rendered comment is passed back to the client, and the success callback then replaces the form with the content. Simple enough. However, if server-side validation fails, I want to render the form, along with validation error messages, and insert that back into the client page, i.e. replace the first form with the second (which also contains the submitted content). Also straightforward, except that, on a truly successful submission, I'll need to do some other things on the page. If validation fails I only need to display the form with errors. I can think of two approaches. One is to search the returned data for some string (e.g., "<form") to decide if the other tasks are to be run.
The other is to send back the data encapsulated in a JSON object, eg:
{
'status': 'FAIL',
'data': '<form ...'
messages: '...'
}
I have 3 options in my dropdown box. In the onchange event of the dropdown, i am submitting the form.User selects a value in the dropdown and when the form gets submitted, the selected data in the dropdown is not getting retained, it is always going to first one. How to set the selected data in the dropdown after the page is reloaded?Below is the code i have used.
Code:
<html>
<head>
[code]....
I've got a <div> inside a <form> which I show/hide when a user clicks on a show/hide link. That div holds several form options which I DON'T want to submit with the form when the div is hidden.
At the moment, even when my div is hidden, the values within it are still being submitted with the form.
Is it possible to / how do I - hide the div so any values enclosed in it do NOT get submitted along with the form?
I have added this validation script to a form, works well but the form is submitted after the alert with errors is closed anyway.
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