OnChange= Multiple Times On One Page

Nov 10, 2007

I got a very good select script that produces multiple values and it works fine by itself but I have two other instances of the same script on the same page. I know that multiple scripts don't work on the same page unless you execute the onChange for all three. But I dont have a clue how to do that. Code:

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I have a javascript that displays couple of buttons, which are
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gif file. What's the most effecient way to do this?

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Nov 27, 2007

I had help with the following script. But, it only works with specific ID, which I have to specify in the javascript code. If I wanted to have multiple sets of selection lists, I would have to duplicate the entire javascript block, which I do not want to do.

My question is, how can I make this script not have hardcoded IDs, and let those be declared where my onchange is? Is this possible? Code:

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Dec 5, 2010

I cannot call a function more than one time in my page, the function is:

Code:
<script>
function seeBig(_this) {
document.all.view_img.src=_this.parentNode.getElementsByTagName("img")[0].src;
}

[Code]....

what problem I am facing is, if I want to build another table as the same as the one above, the function will not work. I know I might need give the function an ID

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Nov 10, 2011

My goal: I'm trying to to create a configuration dialog and persist it so the user can edit it later. Since the configuration is long and has Datepickers, Sliders, different types of inputs and such, I'm loading a new page for the configuration and using ID to get values from them. For example, the page has a datepicker text input "startDate" and a datepicker for it.My problem:1) I load theconfigurationpage into a div of home page make a dialog out of it. jQeury moves that div to it's own div that it created in the body of home page. So when I add multiple dialogs, datepicker doesn't work anymore since there are two "#starDate" input fields in the page now. I also plenty of other cases where I use the ID directly to do other tasks. Is there a way for me to go forward with this.

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How To Run Multiple OnChange Events On Page

May 27, 2010

I've done extensive searching, but each example or explanation I come across is too different from my own, so it's ultimately no use. The problem is that I barely know anything when it comes to Javascript, but yet I'm trying to use it. I have a form on a page. This form contains 6 <select> elements, each with its own <option>Other</option> element. If something isn't listed, the user can choose "Other" and then type into a textbox which appears.

I have the following code, which works great if only applied to one <select> element.
<select name="How did you hear about us?" id="How did you hear about us?" onchange="makeBox1()">
<option value="0" selected="selected">-- Select --</option>
<option value="1">Search Engine</option>
<option value="2">Referral</option>
<option value="3">Trade Publication</option>
<option value="4">Vendor Web Site</option>
<option value="5">Your Company Website</option>
<option value="6">Direct Mail</option>
<option value="7">Other</option>
</select><div id = "inputBox1"></div>
<script type = "text/javascript">
function makeBox1() {
var a = "<input type = 'text' name = 'box1' id = 'box1' class='form popup'>"
if (document.getElementById("How did you hear about us?").value==7) {
document.getElementById("inputBox1").innerHTML = a;
} else {
document.getElementById("inputBox1").innerHTML = "";
}}
</script>

I've read that you have to combine onchange events, but I have no idea how to do this (I've done plenty of trial and error, trying to make every item unique, but to no avail.

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JQuery :: Onchange On Checkboxes Fires N Times?

Sep 1, 2010

I have a series of 6 checkboxes with the same name. The purpose is that whenever one of these is checked or unchecked, another part of the page is filled again based on an AJAX query, that has the values of all the checked checkboxes as input.

I added an onchange event handler like this: $('[name!=stage]').change(refillActionsParameters); what happens is that this handler function gets called 6 times when I check or uncheck any of the checkboxes. As a remedy, I put the onchange handler on the form that contains the checkboxes, but that didn't help, still 6 times.

Also: is there a quick way to retrieve the values or the ids of the checked boxes?

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May 25, 2006

This is my first post to this forum. When a button in parent window is clicked multiple times, more than one popup window is opened. This problem is occurring in linux firefox and mozilla browsers. In windows the code is working fine. Is there any option in window.open() method to open a popup window once. s there any known issue regarding this case?. Need a workaround to fix this issue.

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May 24, 2006

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Apr 15, 2009

I'm currently working on a browser based 2d multiplayer rpg using PHP and ajax. As the number of beta testers has increased, I have found that there is a significant amount of lag involved in changing maps (maps are 480x480px ea consisting of multiple images. What I would *like* to do, ideally, is only load each image once. So the first time I encounter "grass1.png", for example, it is loaded into div id "grass1", and never needs to be loaded again. My question is this, is it possible, to do the above, and then call div id "grass1" for each instance of the image?

This way, I could store all images encountered thus far. When the player left a map, all images would be positioned off-screen, and moved into the field of view as needed. I am already doing this, but there is a div for each unique object. (meaning there could be 10+ divs for the same image, for just one single map!). This would be much more efficient if I were able to call and store just one div per image, and just display it multiple times in multiple places.

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May 20, 2011

I made a sort of typewriter script that shows every next character of a text in a particular DIV, each milisecond. (testing in IE, not tested in other browsers yet)

Now, after the function has run, I cannot run it again. It stops all completely.
I have put some variable in it to see it's running or not. But that doesn't help it anyway.

Has this something to do with event bubbling or something else?

Code JavaScript:
<html>
<head>
<meta http-equiv="Content-type" content="text/html;charset=UTF-8">
<title>Test</title>

[Code].....

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Jul 21, 2011

We have a webpage setup to alpha page individual people with pagers at work. It is a simple form that submits to a php file on the pager server. I am working on creating a script that submits a alpha-page to everyone at once. There are about 120 different ppl in the company, I want the script to submit the form once for each persons pager. I'm new to javascript but have alittle programming understanding.

[Code]....

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Jul 23, 2009

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[Code]...

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Apr 13, 2010

I'm currently working on my first ever javascript and have run into an issue.
Source:
Code:
<script language="JavaScript">
img_width = 0;
img_height = 10;
timer = null;

function imageGrow(bar_len) {
growImg = document.getElementById('imageResize').style
growImg.width= img_width;
if(img_width != bar_len) {
img_width += 10;
timer = setTimeout('imageGrow()', 20);
} else {
clearTimeout('timer');
}}
</script>

<img onLoad="imageGrow(100);" src="img/graph.jpg" border="0" width="1" height="10" id="imageResize" align="center"><br />
<img onLoad="imageGrow(50);" src="img/graph.jpg" border="0" width="1" height="10" id="imageResize" align="center"><br />

I have 2 issues. First, the second image does not call the javascript and I assume this is because both images have the same ID? Can I associate code to 2 elements? Is it even possible to call the function multiple times in the way I'm trying to? Second, as the script is written above, the image never stops growing even when it reaches '100' as specified in the script. If I change 'if(img_width != bar_len)' to if(img_width != 100) it does stop growning when it reaches 100. I am unsure why, as bar_len = 100 when I call the function! I don't know if it makes any difference, but the HTML in my final code will be dynamically generated with ASP.

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Oct 18, 2011

I have a problem when I use the .live() function that I can't figure out. It's something I've run across several times and it keeps confusing me.

My jQuery:

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[code]....

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For example :
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[Code]...

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Code:
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live demo: [url]

HTML

JS

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