I am working on a puzzle that produces a container div.Within that div are produced a grid of 9.16. or 25 tiles.The tiles are positioned absolutely so I can be sure of their relative placement. The container div width and height is calculated according to a preset tile width and height (square actually). So the width of the container should adjust to either 3,4 or 5 tile widths and heights.The trouble is that the offset position of the top left tile is different relative to the container for each different set of tiles (even though it is supposed to be the same position relative to the container for each). I do this so I can apply dragging to the container div.The tiles will follow the container when it is moved and the game will not loose its place when tiles swap locations.(one tile is elected as blank, and tiles, one to left, right, top or bottm, with game content, will swap location with blank when clicked)
I'm just figuring out how to use absolute inside a relative element to shift an image without changing the flow of the rest of the html. It's working for Firefox 4, but not IE 9.
In firefox the div element doesn't cause a hole in the flow. The div and the image inside is simply moved over to where they should be. But in IE, the image is sitting there as part of the flow bumping down the next things (the text and span tags) and the image isn't moving over to the right at all.
I've tried wrapping the div in an another div but that made no difference. Am I crazy to think this is supposed to work? I'm inserting the div and image tags dynamically in the client in javacript.
I'm trying to get the height of an element that contains content which is absolutely positioned. As far as I can tell, because the absolute positioned content is taken out of the page flow, you cannot retrieve the 'visible' height (ie height as seen onscreen) of the element with properties like clientHeight / offsetHeight.
Is there any way to access the visible height of an element like this?
Because of the nature of my page, I would like to animate a div from a fixed postion when someone first visits the site to an absolutely position location using after clicking a menu item using .animate and the easing effects. This part seems to work fine, however, when I click on the "home" button again, the div will not move back to the original fixed position. The div just sticks to the top of the page. My assumption is that the .animate scriptdoesn't' know how to interpret/find the fixed position location. Is there a way to make this work?
I'm working on a website where we're using the jquery.linkselect plugin, and we're running into a situation where we have one of the dropdown linkselect menus happening near the very bottom of the users' window.
Imagine that we have a list of articles with abstracts, authors, etc. running down the left hand side in a div which is set to show a scrollbar if the results list gets long, and each article has a linkselect dropdown menu.
Unexpectedly, if you've scrolled to the bottom of the scrolling div and you're on the last item in the list, linkselect is allowing the menu to drop down extending past the bottom of the scrolling div and outside the boundary of the browser window. This is problematic, as it makes the menu items inaccessible.
We're looking for a way to have it automatically detect the bottom of the screen and reposition the menu accordingly (similarly to the way it does it to make sure it doesn't get positioned off the right hand side of the screen). I might be able to hack it, but was hoping maybe the linkselect team might be able to put something in more quickly and efficiently than I can. :)
Alternately, a way to specify that a menu drops up rather than drops down would also be a great solution to our situation (I didn't see that in the options.
How come when I make a button that's "absolute" position, My dialog overflows and I get the vertical scroll bar if I move the button out of place? I thought it would re size the height accordingly but it doesn't.
If the screen resolution is small enough, or the window is small enough the calendar that appears when a user clicks the textbox for the datepicker appears on top of the textbox - usually it appears below.
I have some text links at the top-right of my page, and if the window is small enough, the datepicker calendar goes underneath these text links.
Is there a way to have the popup calendar ALWAYS on top of every element on the page? If not, is there a way to have the datepicker popup calendar ALWAYS appear below the textbox?
I am trying to make a form where the user is only able to select an option from one of the drop down menus and if they click both then submit an error should pop up telling them to select just one. Now I have found this code:
the first problem is that my menu must be named "id2" which causes a problem due to the bracketed 2 and the 2 after. Is there any way around that?the second problem I forsee is that this will only work with 1 drop down box being unselected. I need a code that will give the warning if nothing is selected OR if something is selected in both drop downs.
This works well with PC's IE. However, when I open this in Mac IE, the dots are either shifted too high up or too low in relation to the US image. Strange thing is, when I resize the browser, the dots literally jump to their correct places.
Is there some possibility with php to put the horizontal scroll bar of the web brwser into the center if the "width" of web page are bigger then the "width" of the web browser screen?So I don't need to scroll to right if I open the page, but the horizontal scroll bar will be positioned in the center.That code should do the same think like I when I take the scroll bar and put it in the center position, but this should be happen when I load the page automatically.
I was wondering if it is possible to set the positioning of an element in CSS? What I am looking to do, is have a set of 3 boxes on the right of the page and base the size of the boxes by %. Problem is, while I can position the first and third boxes relative to the top and bottom of the page, repectively, depending on the size of the browser, i can't firmly set the positioning for the middle box off of the top or bottom.
Ideally, I would like to use JS to determine the height of the first box (which is based on a % of the page size), and then set the top of the second box = the height of the first box + 5px for a buffer. Code:
I'm trying to write the code for an AJAX script. The goal is to let the visitor send a comment through a form (obviously). The form is inside a div that pops up when the visitor clicks on an "add a comment" link and when the form is submitted the result of the form processing apears inside the same div which resizes to fit the size of the result.
The problem I'm trying to solve is that although the resizing and the positioning of the div works for Firefox it doesn't for IE7. In IE7 it does the resizing but the positioning fails Code:
I have problem here I have two div as below: [CODE <div id="left" style="top:0px;left:0px; width:150px;"> <div id="title1" style="top:auto;left:0px; padding: 4px; overflow: auto; background-color: #8EB4E3;"> <table border="0" cellspacing="0" cellpadding="0"> <tr><td></td></tr> <tr> <td>OUR SYSTEM</td><td width="11%" height="10"><div align="right"> <img src="../fleet/images/logos/<?=$fleetID?>.png" width="100" height="50" /></div></td> </tr></table></div> </div> <div id="right" style="top:0px;left:250px; width:800px; height:100%">Map goes here. </div>[/CODE] The problem I am having is that when the div id="left" does not have any inner div then the right div where it contains map is at 0px. But the moment I put id="title1" in the div id="left" then the map in div id="right" does not stay at the top 0px and it goes down by quite many pixels.