I have several comments embedded in my website and I would like to be able to get the ID or the Jquery object refrence of the parent in which they are contained, for example, in the following code I would like to get the ID "container" just by locating the html comment as a string within the page[code]...
I am driving an html site from my network drive in my office that can be viewd on LAN. I need to put a blog kind of section on my site so people who visite this site can leave there comments on it and all can see thses comments.
how it is possible to append HTML in an textarea of an iframe's parent window.
First of all, i would like to give you an short overview about the related files:
* insert_media.php (a PHP file, which represents a self-made filebrowser) * article.php (a PHP file, which inherits logic to edit and create articles) ** <textarea id="content"> (the textarea which should accept HTML from "insert_media.php")
I'm using CKEditor for my project and wanted to add a selfmade filebrowser for including media into my articles. Therefore i created a "insert_media.php", which inherits all necessary logic to retrieve media items from a database.
The "insert_media.php" is opened inside "article.php" via TopUp (JS library) in form of a lightbox iframe - for sure "article.php" has jQuery loaded in its header.
Now, when I'm clicking on a media item (inside "insert_media,php"), i want to have the content of my textarea "#content" (inside "article.php") being appended by the necessary HTML code.
I'm able to retrieve the val of #content ("article.php") inside my iFrame ("insert_media.php") via $("#form_content_content", window.parent.document).val(); but i can't manage to have access to it into the other direction.
I'm trying to use the ajax load() method to load a file from a parent directory, e.g.
But that doesn't work. I can load a simple html file from the same directory as my html file or a descendant directory, but not an ancestor directory. Nor can I load from an external server.
I'm doing my testing on my PC and I'm not running a server (apache or otherwise). Just using it as a simple client. Is that possibly the problem? Or is there something else I'm missing? If that is the problem, is there a workaround?
Using 1.4.1. A comments app. Clicking certain links fetches a comment form which displays below. The button then becomes a "cancel" link. Clicking that removes the form and sets the button back to its original state. Or so it should. I'm seeing some strange behavior. Some strange, but understandable, some not so much.
After removing the form, my code fetches it again and re-displays it. The problem appears to be that click event isstill "happening" and so live() fires immediately. I tried using stopPropagation(), which keeps the form from re-loading but for some reason also keeps displayFormHandler from being run on subsequent clicks.
I saw a hint in the comments for stopPropagation() and added, in cancelFormHandler:
Again, this keeps the form from re-displaying but, bizarrely, causes displayFormHandler to always return false (the console.log() line runs every time). I can understand why the original problem happens but this doesn't make any sense at all. If the class has been removed, subsequent clicks should proceed normally because hasClass() is being evaluated at the time of the click, not when live() is called.
I am working on a page that will load in other pages using AJAX and the .html method. Something like this :
<span id = "edit">Edit</span> <div id = "cont"> </div> //the click edit script
Unfortunately this does not seem to work, entirely. It does trigger the click event but it messes up the post for some reason. I have played around with it for the last 45 minutes or so and it seems like the click event trigger is what is messing things up, if I comment it out it works fine. Could anyone tell me why they think this is? note this is an over simplified version of my actual code, but the structure is the same.
How to test if a html page has a parent page?Let me explain: I use the (great) Colorbox plugin and I like to apply jquery functions only if a page is in an Colorbox iframe.So, basically, I'd like to know how to determine with jQuery if a page has a parent page (= is in a Colorbox iframe).
HTML parsing error:unable to modify the parent container element before the child element is closed(kb927917) My page is not getting displayed In IE although running good in chromr and mozilla.... And after refreshing in IE it is displayed properly.
I am trying to create a conditional comment scenario that is based on a web address. I am working with an ecommerce site that I want to put a nav menu promotion on all the pages except the home page. The system we are using only allows a post promotion to ALL or one specified URL.
I have tried everything I can think of to create a URL condition based comment but nothing has worked. I tried modifying the code below to change the if output to a variable comment tag and then write the variable further in the script with a document.write.
var allowedChars = /^[a-zs]+$/i;
to specify that I only want characters and so on. Is there a way to reverse that to say this html input field CAN NOT contain any of the following? I want to check against a comment box to make sure no url address is entered (http:www.) because most spam contains urls in this field. Is there a simple solution?
I am really new to JS (literally just starting looking into it) and I was wondering if anybody could help me or give any suggestion as to how build a comment box which appear when a user click on the comment button.Now I had a stab at that but my JS skills are still really poor. Here's what I came up with after sometime looking around on the net and getting (or at least trying to) action some suggestions I managed to get here and there:
HTML Code: <html> <head> <style type="text/css">[code]......
I'm trying to make a comment field that only appears once you've clicked the "Add comment link". I'd like it to replace the add comment link. I assume this is an onclick event of some sort, but I'm not sure quite how to go about doing it.