Ajax :: Refresh Div - Content Consists Of An Image That Will Change On Insertion Of A Row To SQL Database
Oct 16, 2010
I have got a DIV that I need to refresh, its content consists of an image that will change on the insertion of a row to the SQL Database, however, when I use a refresh on my div it does refresh but does not change the image...
My refresh code is ajax:
And my PHP code contains the MYSQL that has a mysql_num_rows, so that PHP can see if there are rows or not.
I would like my page not to redirect or refresh on my div change.. So I would just like my div to refresh.
I have a php webpage that has a single input box. When ever an item is entered and the Submit button is pressed, the entry is added to a database. Additionally, the database table contents are read and printed directly below the input box and the submit button on the same page, using AJAX. Now, I have decided to add additional functionality to the page. I want a delete button for each entry displayed in the table below. For any button that is pressed, I want to delete that entry from the database.
Here's the problem: I want the database table contents that has been printed below to reflect this change. I can achieve the delete, but in order to show the change in content caused by the delete, the table below must either be replaced or updated via ajax. How can I achieve this? I have been trying to follow these examples using jQuery and Mootools respectively, but I've been having no luck. [URL] I don't want all the fancy looks, I just want the core functionality.
i have a website where i change the content of a div using jquery, however i also want to change the background image at the same time but cant seem to get both to work together, not sure what im doing wriong but i think its something to do with the script and return false
you can also view the page here
button1 changes bg image ok button 2 changes div content ok button 3 doesnt work
i am using ajax to change the banner background while pressing on refresh Note:it must be a background image because i will display data from database. [URL]...
my problem is: when i press refresh button in Firefox browser it changes the background and on pressing refresh again the background will change but in internet explorer 8.0 it changes the background only for the first time and on pressing refresh again the background will not change.
how i can fix this problem ?? i want the user to press refresh at any time and the background will change.not only for the first time at the same time it must be a background image because i will display text from database.
I'm building a site that uses some jQuery but at this point I haven't had to get my hands dirty in the code. I'm hoping to get some pointers on how to best approach this problem, or if a plug-in exists to point me that way. I'm anticipating I'll need to build the code though because of the specific nature of the issue. I have a two very complex MySQL data trees that need to cross reference. To handle the cross referencing I simply have a third table that links the ids of the large tables together. That way I can join data via the linking table. This is all working and established. What I need to do is allow the admin user to navigate through one tree from within the context of a particular element from the other tree and click a toggle icon (tick or cross) to create or delete the cross reference in the linking table. Traditionally I would perform this task using forms but I want the user to be able to make these changes on the fly without needing to reload the page. I also want to stop further toggling until the update or delete has been completed.
I have a script which allow users to chnage there profile image, and it allmost works perfect. The script is set up so when a user uploads a new picture it overrides the previous one, so if a user have an ID, lets say 15, the image would be called 15.jpg. The problem is that when an new upload is finished it still shows the old image, I think by cache, and thats no good. How do I refresh the image with ajax so when the script has done uploading the image is the new one?
im trying to use ajax to change the content in a div when you click on a nav button (6 buttons in nav)...... I build out side using a Ajax book and it did not work...... deleted the project and im trying to start over.....
I have questions related to three operations using jQuery:refresh a div element on page lo append an element on top of the other elements in div change an image (pending/accepted) from the div's elements I know that there are tutorials for that, but i am so short in time.I just finished my PHP courses, and i am too tired to get into the jQuery magic right now.ere is the situation that i am confronting. I have to files: propune.php (which is basically the page that has the form and the div that should be refreshed/appended) and propuneri.php (the file that is handling ajax calls).
On page load it gets content from "recom.php" then it refreshes the content every 9500 milliseconds into an element with the id "recom". How can this code be modified so that it will refresh the content only "x" times? (in my google searches I found that clearInterval should cancel the refresh but I couldn't make it work)
I am new to AJAX and I am trying to create a script that will change content of a div.My scenario I am using is an index page with the list.php script included in the div I want content changed in. The list.php script will pull 8 newest titles from mysql and list them in the div. When you click one of the titles it will redirect you to a new page created by story.php. I would like this to be contained inside the div I have currently have the list.php script in.How my list.php script works is as follows:
// generate and execute query $query = "SELECT id, title, timestamp FROM news ORDER BY timestamp DESC LIMIT 0, 8"; $result = mysql_query($query) or die ("Error in query: $query. " . mysql_error());
var descIg = ""; descIg += rssent[i].descImg; var placeImg = document.createElement('img'); placeImg.src = descIg;
have 4 tabs which are loaded via AJAX, 3 of them from external html files. Within these tabs I have a number of images in a gallery.When the page is loaded initially, the Fancybox works fine, but when I click on another tab, ie pull in external content, and click on an image it loads in another window.Seems like the new content pulled isnt hooked up to the Fancybox trigger..in right direction.The code is detailed below, I need some kind of call on the AJAX to trigger FB???
[code] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
I'm making a somewhat unusual web page that will feature a showroom (this showroom will have images/video/qtvr/etc). If a pre-determined user comes to the page and views the showroom, I am essentially controlling it on my end by changing the database. The page needs to check the database every 2 seconds and refresh if the database value is different from what it currently is. The issue with using iframes or a meta refresh is that if a video is loaded, it will never play, because the page will always be refreshing.
So, that is where the XMLHttpRequest function comes in. I believe I have all of the basic code completed, but it of course does not work and I am probably missing something really simple or perhaps my approach is off. Code:
I want to activate an image slider that is placed in a div loaded through an Ajax request. I'm using the JQuery Plugin Anythingslider. I've tried to use code similar to this without success:[URL].. The slide script works if loaded together with main page.But how do I activate a slider placed in a div that has been loaded through an Ajax request?
I have been trying to figure out how to go about making a table of comments auto-refresh when someone inserts from a comment form without refreshing the whole page.I've tried looking into AJAX for this, but everything I have looked at, in terms of tutorials, just flies right over my head, and I can't really make much sense of it.
I have a client who now wants his website to refresh every so often but also to refresh and have new content each time.Example. On a part of his website he wants there to be a small section of "Random Quotes". His website at the moment is refreshing every 10 minutes. He decided now that he wants when the page refreshes a new quote to appear in the "Random Quotes" section.