I want to find a boundary word that starts with * . I have this regex exp for it,
*(w.*?w)*
It is not working. However, if i replace asterisk with underscore , it is working.
How can i make it work for asterisk, such that it matches with :
This is a *test* example.
I have a JS function that is susposed to toggle word wrap on and off in a textarea. It works fine in IE but does not work in FireFox or Opera.
Does anyone know what the trick is to get it to work in FF and Opera?
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<script type="text/javascript">
[Code]....
Activities other than copying, distribution and modification are not covered by this License; they are outside its scope. The act of running the Program is not restricted, and the output from the Program is covered only if its contents constitute a work based on the Program (independent of having been made by running the Program). Whether that is true depends on what the Program does.
1. You may copy and distribute verbatim copies of the Program's source code as you receive it, in any medium, provided that you conspicuously and appropriately publish on each copy an appropriate copyright notice and disclaimer of warranty; keep intact all the notices that refer to this License and to the absence of any warranty; and give any other recipients of the Program a copy of this License along with the Program.
You may charge a fee for the physical act of transferring a copy, and you may at your option offer warranty protection in exchange for a fee.
2. You may modify your copy or copies of the Program or any portion of it, thus forming a work based on the Program, and copy and distribute such modifications or work under the terms of Section 1 above, provided that you also meet all of these conditions:
I have an assigment of statistics formulas in java i have calculated the classes class intervals and boundry but i am unable to find out the frequency.........
String ans;
I would like to replace all the characters within a string with asterisk using javascript.
Could you please let me know how i can implement this using Regex within javascript.
this code work well but i want that password appear in asterisk..
<SCRIPT language="JavaScript"><!--
function check() {
// Prompt user for the password ...
[code]....
Working with TinyMCE to enable editor to toggle off html mode, what I'm struggling with is converting list items into asterisks [code]...
View 4 Replies View RelatedI am trying to find a word inside a string.the search his going fine but I need to know which word has been found in the string.
Code:
Code:
Now in the string only one value can be found at a time.So its either a1 or a2 or so on.....
I have a drop down box in HTML using SELECT and OPTION tags:
<select title="Choose a number" onchange="obscure()" name="Digit1"
ID="Digit1">
<OPTION VALUE=""> </OPTION>
<OPTION VALUE="0"> 0</OPTION>
<OPTION VALUE="1"> 1</OPTION>
<OPTION VALUE="2"> 2</OPTION>
<OPTION VALUE="3"> 3</OPTION>
</select>
Using the 'onchange' event I can fire a javascript function obscure().
How can I hide the selected number with an Asterisk (like a password)?
I've tried several different Googles but I can't find a method that
works.
I'm not very good with javascript. My knowledge is very limited.
See, this code is going to check if a user has inputted an empty field or not. As of now, Im testing it on 'first name' text field. If the user didn't input anything (the text field is empty) and clicks submit, an asterisk will be displayed at the right side of the text field. The asterisk is only temporary. If the user clicks the text field or refreshes the page, the asterisk at will disappear.
I've googled it already and I've tried every technique I can find but I can't get this code to obey. code...
I Use the regular expression to find the html tags present in the input box, It works properly in IE & FF but in chrome it works fine when use first time for an input box but not again, below my code...
function IsWithinTags(inputString) {var regExp = /</?[^>]+(>|$)/g;
inputString = inputString.replace(/&(lt|gt);/g, function (strMatch, p1) {
return (p1 == "lt") ? "<" : ">";
});
[Code]....
I have a long paragraph and I have been asked to display words in red and green in such a way that that fist word should be red, 2nd word should be green, 3rd word should be red and 4th word should be green and so on. For example: this is just a sample.
View 3 Replies View Relatedielementfrompoint () gets an element at a given position (x,y). how can I get a single word (if it exists) from a given position? to sum up i need this: f(x,y)=word ( or null - in case there is no word). x, y is given NOT obtained with some mouseover event.
View 1 Replies View RelatedAssume we have this html:
<span>the quick brown fox</span>
and the mouse is hovering over the word "fox". Using javascript, is it possible to determine the word under the mouse *without* introducing additional elements such as an anchor?
I have what seems to
be a robust, working word counter script. I post it here to benefit
others that might want this in the future and so that if I ever lose
my copy I can come back here to find it :) Some other scripts that I
used for inspiration failed when confronted with whitespace before the
string or miscalculated when encountering linefeeds and other
non-space spaces, so I made mine better. Definition of words for this
exercise is contiguous groups of characters separated by whitespace. Code:
This JavaScript is a "Word Filter". It is a type of form validator. When the user submits some text, the validator will check the text for words that has to be filtered.
The words that have to be filtered must be added to the array swear_words_arr. When the user types the text and hits the submit button, if the text contains any word that is present in the array swear_words_arr, the form will not be submitted.
The script can be used for validation of swear words etc.
<html>
<head>
<title>Word Filter</title>
<!--BEGIN WORD FILTER JAVASCRIPT-->
<script language="JavaScript1.2">
// Word Filter
// (c) 2002 Premshree Pillai
// http://www.qiksearch.com
// http://javascript.qik.cjb.net
var swear_words_arr=new Array("bloody","war","terror");
var swear_alert_arr=new Array;
var swear_alert_count=0;
function reset_alert_count()
{
swear_alert_count=0;
}
function validate_user_text()
{
reset_alert_count();
var compare_text=document.form1.user_text.value;
for(var i=0; i<swear_words_arr.length; i++)
{
for(var j=0; j<(compare_text.length); j++)
{
if(swear_words_arr[i]==compare_text.substring(j,(j+swear_words_arr[i].length)).toLowerCase())
{
swear_alert_arr[swear_alert_count]=compare_text.substring(j,(j+swear_words_arr[i].length));
swear_alert_count++;
}
}
}
var alert_text="";
for(var k=1; k<=swear_alert_count; k++)
{
alert_text+="
" + "(" + k + ") " + swear_alert_arr[k-1];
}
if(swear_alert_count>0)
{
alert("The form cannot be submitted.
The following illegal words were found:
_______________________________
" + alert_text + "
_______________________________");
document.form1.user_text.select();
}
else
{
document.form1.submit();
}
}
function select_area()
{
document.form1.user_text.select();
}
window.onload=reset_alert_count;
</script>
<!--BEGIN WORD FILTER JAVASCRIPT-->
</head>
<body bgcolor="#FFFFFF">
<!--BEGIN FORM-->
<table cellpadding="10" style="border:2 solid #FF9900" width="200" align="center"><tr><td>
<form name="form1" method="post" action="post.cgi">
<center><font face="Times New Roman" size="6pt" color="#606060"><b><i>Word Filter</i></b></font></center>
<table><tr><td></td></tr></table>
<textarea rows="3" cols="40" name="user_text" style="border:2 solid #808080; font-family:verdana,arial,helvetica; font-weight:normal; font-size:10pt" onclick="select_area()">Enter your text here...</textarea>
<table><tr><td></td></tr></table>
<center><input type="button" style="background:#EFEFEF; border:2 solid #808080; width:100%; cursor:pointer" value="Submit" onclick="validate_user_text();"></center>
</form>
</td></tr></table>
<!--END FORM-->
</body>
</html>
Filter out words from multiple fields:
<html>
<head>
<title>Word Filter</title>
<!--BEGIN WORD FILTER JAVASCRIPT-->
<script language="JavaScript">
// Word Filter 2.0
// By Premshree Pillai
// http://www.qiksearch.com
var swear_words_arr=new Array("bloody","war","terror");
var swear_alert_arr=new Array();
var swear_alert_count=0;
function reset_alert_count()
{
swear_alert_count=0;
}
function wordFilter(form,fields)
{
reset_alert_count();
var compare_text;
var fieldErrArr=new Array();
var fieldErrIndex=0;
for(var i=0; i<fields.length; i++)
{
eval('compare_text=document.' + form + '.' + fields[i] + '.value;');
for(var j=0; j<swear_words_arr.length; j++)
{
for(var k=0; k<(compare_text.length); k++)
{
if(swear_words_arr[j]==compare_text.substring(k,(k+swear_words_arr[j].length)).toLowerCase())
{
swear_alert_arr[swear_alert_count]=compare_text.substring(k,(k+swear_words_arr[j].length));
swear_alert_count++;
fieldErrArr[fieldErrIndex]=i;
fieldErrIndex++;
}
}
}
}
var alert_text="";
for(var k=1; k<=swear_alert_count; k++)
{
alert_text+="
" + "(" + k + ") " + swear_alert_arr[k-1];
eval('compare_text=document.' + form + '.' + fields[fieldErrArr[0]] + '.select();');
}
if(swear_alert_count>0)
{
alert("The form cannot be submitted.
The following illegal words were found:
_______________________________
" + alert_text + "
_______________________________");
return false;
}
else
{
return true;
}
}
</script>
<!--END WORD FILTER JAVASCRIPT-->
</head>
<body bgcolor="#FFFFFF">
<!--BEGIN FORM-->
<font face="verdana,arial,helvetica" size="-1">
<form name="form1" method="get" action="" onSubmit="return wordFilter('form1',['name','email','subject','message']);">
<table>
<tr><td>Name :</td><td><input type="text" name="name"></td></tr>
<tr><td>E-mail :</td><td><input type="text" name="email"></td></tr>
<tr><td>Subject :</td><td><input type="text" name="subject"></td></tr>
<tr><td>Message</td><td><textarea name="message" rows="5" cols="30"></textarea></td></tr>
</table>
<input type="submit" value="Submit Form">
</font>
</form>
<!--END FORM-->
</body>
</html>
I know how to do a regular word count where it splits at the " ", but is there a way to split it at " " and " " [space and double space] in the same code so it accounts for people that double space also?
View 6 Replies View Relatedthe title basically sums it up. how can i see if a word is in a url and then if it is, do something with it.
View 9 Replies View RelatedHow do I check if a certain word exists in a text box? For example, if I set the word to be found to "word1", if the text box is "This is word1", and alert would come up saying that "word1" was found.
View 2 Replies View RelatedI have in javascript a text say I am an idiot
I want to do it. "I am...." and on mouseover it shows up I am an idiot.
How can I do it?
Is there any way for me to capture the DocumentBeforeSave event with an ActiveXObject("Word.Application") via Javascript in IE?
View 1 Replies View RelatedI am facing the following problem while exporting data to Word.
The current implementation is as described below:
I have a JSP file which has a link that enables you to export the data to Word.
Clicking on the link invokes a javascript function: .....
Is this possible in javascript? How do you do it?
View 2 Replies View RelatedI have a div I want to delete any word start by /art and finish by les/ inside the div content.Here an example below :
Before :
<div id="article" class="article">
Du texte, du texte /articles sur les boucles/ du texte ... du texte.
</div>
After :
<div id="article" class="article">
Du texte, du texte du texte ... du texte.
</div>
I have a web form. I use a simple function to generate a letter ouput based on the form fields and populate them into a word doc for printing. Below is a basic example, but you get the idea.
function createDocument() {
strDoc = "
"
strDoc += "Hello there!
[Code]....
Note this is only intended to be used on IE8. As it stands, the ouput generates and formats exactly as I want bar two things:
1) Does anyone know how I can get some of the text to bold? I've tried everything I can think of (html tags, escape characters etc etc). Is there a way to open a word window in rtf perhaps?
2) Does anyone know how I can insert a small image (a signature in gif or jpg) into the document?
I can use a browser window instead of word, which formats, bolds, images etc, however I then get the issue of headers/footers when printing. I cannot disable headers everytime I want to print a letter, it's not practical.
Suppose I've made my range so that it covers a word, using range.expand('word'). Typically to add the next word, I would write range.moveEnd('word', 1). But this seems not to work in Webkit. Perhaps it should be implemented differently?
View 4 Replies View Related