I have to find google co=ordinates from given address. so i am displaying google map in popup box but i don't know why google map not loading in popup. but it is working fine in new page.when i am trying to display in popup then only google map diplaying half. i think it is loading problem of google map in popup. how to solve this issue.
Here is my page please check it any one.
[url]
Here is the link without pop-up. Its working fine. But above link is not working properly.
I've copied and customized a script to display a css popup in my little website. The script should display a popup in the middle of the browser window, graying out the background, Everything seems to work fine except that at the end of the script, the page is displayed from the top. This means that if you click on the popup link from a position down in the page, you'll miss it because you will be taken to the top of the page, where you can't see it.
This is the HTML and CSS code:
HTML Code:
And the js:
Code:
I've been debugging with alert boxes and everything seems to be fine until the script ends execution. Then the user is brought again at the top of the page...
In my final site the only thing I would like to show in the popup is a Flash movie.
Do you know any workaround? I would even implement a completely different solution if I knew which...
By the way: At this stage I am using Chrome but I would like my solution to work in any browser, that will the next issue.
I am trying to dynamically open a popup window but ie8 blocks it with the popup blocker. basically within a ajax fuction I have a confirm button and if the user clicks yes it opens a popup window. now I tried it with a javascript function but it got blocked, so I have tried it by creating a form with a button in it and instead of calling the popup function direct I call document.form.button.click and in the form my button has onclick"popup('<? echo url; ?>')" but this also is detected as a unwarranted popup and is blocked.
now I understand that the popup blocker works when a popup is called without user interaction, but allows popups on say button clicks. how can I get the popup to work
Does anyone have a sizeable popup that will work in google chrome? I have tried several scripts for this with no success, they all open full page. Here is an example of what I am looking for. The problem with this is it opens a new page plus a full page popup
<script type="text/javascript"> <!-- function popup(url) { var is_chrome; var width = 1020; var height = 600; var left = (screen.width - width)/2; var top = (screen.height - height)/2; var params = 'width='+width+', height='+height; params += ', top='+top+', left='+left; params += ', directories=no'; params += ', location=no'; params += ', menubar=no'; params += ', resizable=yes'; params += ', scrollbars=yes'; params += ', status=no'; params += ', toolbar=no'; newwin=window.open(url,'windowname5', params); is_chrome= navigator.userAgent.toLowerCase().indexOf('chrome') > -1; if (is_chrome) {newwindow.parent.blur();} if (window.focus) {newwin.focus()} return false; } // --> </script>
To open I am using: onclick=popup(mypage.php?id=".$row->id."
In my application i use window.showmodaldialog() to pop up a window. When i run it in IE pop up blocker wont blocks the window... But when run it in FireFox pop up blocker will blocks the pop up window.. is there any way to open a window with out blocking(avoiding ) by the pop up blocker?
I have a problem since three days about google map. I want to use jQuery to dynamically load the map in a page. Here is the code: In left side page, a script that loads the page into the right one: <script type="text/javascript"> $( document ).ready( function(){ $( "a" ).each( function(){ var ajaxOptions = {};
In the right side page: <? php $content .= '<script type="text/javascript">' ." "; $content .= " ". 'function initialize() {'
When I call the right page without ajax (by its url), I get the map entirely displayed. Nevertheless, when using the jquery load method in order to load dynamically the right page, for the first time, the card was well displayed. But later, by clicking the same link, I get a problem: The card is displayed only one-third. I thought it was the cache that was originally because when I empty the browser and I reconnected, everything goes well. Then in jQuery, I changed the load method by adding the option cache: false.
I am trying to display a map with Google maps. The code listed below is located at http:[url]....
Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">[code]....
I find another example where some uses a CDATA tag, but it still doesn't work. http:[url]...I finally remove the DOCTYPE and it works. http:[url]....My problem is I want the DOCTYPE.
Right I have google maps connected to a database which holds stockists and their information. The user enters their postcode and radius and markers are put on the map of stockists in the radius of their postcode. I have this all working fine and the database chucks the information into an xml file fine. The problem im having is displaying the information in the pop up window of the marker.
Example Xml:
The only information displayed in the sidebar entry is the name and distance and on the marker just the name.
I found the following 'Cut & Paste Google Internal Site Search script' in the Javascriptkit.com library - it works well and provides an easy solution for adding a search function to a website - code below
<script type="text/javascript"> // Google Internal Site Search script- By JavaScriptKit.com (http://www.javascriptkit.com) // For this and over 400+ free scripts, visit JavaScript Kit- http://www.javascriptkit.com/ // This notice must stay intact for use //Enter domain of site to search. var domainroot="www.javascriptkit.com" [Code]...
I have a popup window which has the search form in. What I want to do is for the popup window to close once the form is submitted, and to post the form data to a page on the main window.
Is anyone able to advise. As the main page is dynamic, it is not possible to give the page a name.
Im trying to create a hidden form field in a parent window from within a child window (popup). I am trying to use jQuery, but unfortunately the hidden field does not get created.
I have a couple of utility windows - a calculator and a calendar that popup from my main window. I would like them to always stay in front of the parent window until they are shut down with there own close buttons. As it is, when you click back to the parent window, of course it comes in front of the child windows. Can I do this?
I need to open a popup window from a PHP site and pass in some parameters to use in the pop up window. I have the params in an input box and need to get the val of the box into a param and pass it to the new popup window. All pages are local and in the same folder. The id of the input box is 'ddutykey'. The name of the new window would be showduty.php if possible.
I have the code below in my popup window which currently brings up a blank page in the background as the main window. Instead I want the popup to come up but the original page I left is in the background as the main window. Does anyone know how I can do that with the code I currently have.
<html> <head> <title>JavaScript Popup Example 3</title>
I have a form that is in a popup window. I need the form to submit to the opener window. Is is possible to do that? The opener window is the main window so it is does not have a name and there are no framesets.
<form action="something.php" method="post" target="????"> I'd like to use window.opener in the target but that's JavaScript...
I know somebody has done this before and has the code.
I am trying to insert the value of a variable gathered from a popup window as an option in a <select> menu on the main window. This is the code I have so far:
Code: var newOption = document.createElement("option"); newOption.value = '<?=$userfile_name?>' newOption.appendChild(document.createTextNode('<?=$userfile_name?>')); select.insert(newOption);
How do I do the rest? I just want to add this new value to the end of the list.
I need the most efficient way of passing a variable from a parent window to a popup window.The reason i say "most efficient" is because i currently do it like this from the parent:[code]But this is inefficient because at times it randomly alerts "undefinded".Anyways, can someone tell me a more fail safe way to pass a var to a popup so that i will be able to access it 100% correctly.
how I can populate the value of an input field on a parent window from a selected item (of a form - listmenu) on a pop-up window? Basically, I need to pass the value of one form to another form located on a different page...
I have a popup window that comes up when a user doesn't have access to a certain page within my site. The problem is when a user clicks on something the popup window comes up but the bigger sized window of that popup comes up in the background as well. I am trying to have my popup window come up while the original page I clicked from is still focused/seen in the background. This is the code I currently am using, can anyone help me with what I am missing. I have a back button but I won't need that if I want to maintain the original page in the background. Instead I will use a close button.
I am building a CMS and will have an Image browser built with it. When articles are added the will be able to open up the image browser when they find the image they want to insert I would like to send it(and ID from my database) into that textarea where the article is in(in the main window). So basically sending a value from popup to the main window(textarea). Is there a way i can do it.
how to pass a value from radio button in a window to a popup window using asp javascript?n in the popup window,there is a textfield to enter data to search from database.. the value from the textfield then is used to generate report.
I need to show popup only once a day per user! The Problem is that the users of my blog gets mad when the popup displays, so i only want to show it once a day. add the codes to it fully and send it back over.
