myform = document.createElement("form"); myform.method = "post"; myform.action = "editdetails.php"; myform.id = "editemail"; myform.name = "editemail"; var a=document.getElementById('editdetailstable').insertRow(2); var b=document.getElementById('editdetailstable').insertRow(3); [Code]....
i have a dropdown list where a user can select, 'Yes','No', and 'Other'. What i need to have happen, is that if a user selects other, i need a textfield to appear so the user can enter a custom variable. does anyone have code for this?? Code:
I want to execute a script when the user clicks the button. Currently in my html doc. i have the button declared. <input type="button" id ="button" onclick='notEmpty() value="Play"/> When the button is clicked, i execute the notEmpty() function and I want to execute a script inside the notEmpty().
It will open when the page comes up, but how do I put it so that it opens when the user clicks a button?
This doesn't seem to work. Am I referencing this.value incorrectly? If so, what's the proper way to get information about what the user clicked?
I am looking for someone who has used jQuery in the capacity of assigning a value to a text area when the user clicks a radio button. Here is the example code I have worked on so far that does not work.
I am trying to set up a toggle to allow users to show more precision when a user clicks a button. I have a function high() that doesn't do anything when it is called. I am fairly new to jQuery so I am not to familiar with the syntax.
I'm looking to have a lightbox pop up when a user clicks the Back button in their browser rather than just navigating back. The purpose is to ask a question with a Yes/No answer, and if they click No, I allow them to go back. The only thing I've found anything like this is the onUnload event, but that doesn't prevent them from going back. How should this be handled?
<form> <input type="button" value="Click here to see" onclick="window.open('http://www.yahoo.com')" />
I guess this case applies to both popup windows opened by window.open() and by showModalWindow().
I have two buttons in popup window, "Cancel" and "Save". If the user clicks either button, there is a "process" at parent window before close() at popup being called. The problem now is, if the user click the "X" sign at top right corner of that popup window, how to trigger the "process"?
I think I can do nothing in popup window since the closure is unexpected programmatically. Can I put some kind of listener in parent window to detect if popup is closed?
I am trying to pop-up a window when the user clicks on an image. The problem is that when the user clicks on the image and the window pops up OK, but the window underneath also proceeds to the image. The desired behavior is that when the pop-up is invoked, I want the underlying window to stay put. Code:
I am looking for a pop up to collect emails when a visitor is leaving my site, I don't which pop up software can provide that.I know how annoying pop up can be but I am sure my visitors will be ok with it, they are even asking for it.
I am trying to get a way by which I'll know exactly when user goes out of my site by clicking on close button in browser, So that w/e user click close button in browser, I can send a signal to server.
This seems to be achievable with body unload events, but it is little too much, as even if user navigate within my site, this event will be generated, this can be avoided by handling onclick of each link, so that I'll know exactly which link is clicked, but honestly this looks over doing to me, any other smart short cut for finding out when user click on X in browser?