JQuery :: Passing More Than 2 Variable From Php File Dint Work?
Jun 4, 2011
i am devloping a website in php(5.3.5) mysql(5.0) jquery(1.6.1) i have syntax problem while transferring more than 2 values from jquery to php file ..but code dint work...when i try to transfer only 1 variable it works but not with more than 1 variable....here is the codes and the data syntax i tried to send:
I few sites said to (in the js file) put the varible in <%= %> these tags but thats not doing any good. Is there some other part needed to this I'm missing. The javascript I'm using is in a file I included in my VS project.
Ok, so I've built a member search using ajax to change the results each time a filter is changed. It works great, except one minor issue that I'm struggling with...I just can't specify dynamically in the parent file that linkclass$id opens linkclasscontent$id as I don't know of any way to pass that $id variable back over to the parent.
Code:I am having problems with the following. I am wanting to hide <tr> in my table (employees) and only show employees that are in the selected department (selected via dropdown box).I need to set a javascript array to a php array. I am looping and assigning the array and am wanting to pass a javascript variable as the index in php array. I have marked my problem lines in red. Thanx for any help.
<script type="text/javascript" > function display_elements() { var departments = new Array;
If I switch the w3schools' file with the same local file, it will not work with firefox.Does anybody know why the local file is not displayed correctly?
I want to pass a variable between dialogue boxes but can't get it to work:
<script type="text/javascript"> function deleteE(v,m,f){ if(v == true) { $.prompt('Enquiery Deleted.',{callback: del, buttons: {OK: true}, persistent: true}) ;
[Code].....
I have got the process for removing the record from the database to work fine, it's just getting this value from the first box to the last and into the php file.
I'm having a tough time trying to add the "zip" variable to my YQL statement.
var zip = $(this).attr('zip'); $.YQL("select * from rss where url='http://weather.yahooapis.com/forecastrss?p=' ' "+ zip +" ' ", function(data){ var w=data.query.results.item;
[Code].....
I've tried as many different ways as I could imagine. Simply putting the literal zip code in the query works perfect.
if this is such a obvious question, but i'm kind of newbie in JQuery, i am using a lightpop plugin, & i want to pass 'image_path' via html. lightpop plugin code is something like this:
Basically I want the field name to be a variable but it is taking it as a literal.When I print back the POST array with PHP I get:- Array ( [field_name] => Whatever I typed )So if the text field has a name of 'username' then I want the PHP to print back
Array ( [username] => Whatever I typed )
$(function(){//on DOM.load $('.register-field').blur(function() { var field_val = $(this).val();
I'm trying to pass a var via object to .load() ... .load(URL, {"myname":var}, function) { ... This will not work unless the var is in quotes and therefore not a variable anymore. I want to be able to use a form to feed data to the program that loads the data.
This is my very first post! so please be kind Ok, i am very novice to jQuery. But what i am trying to do is use the jQuery attribute selector to select an input with a specific name. I can select an input of name type fine by doing the folowing:
I've used jquery to create a tabbing system and I want to be able to use it on multiple pages. I want to be able to pass a variable containing the number of items in the list from the html to the js file. Inside the js file I have this function:
I've looked extensively for the answer to this but suspect my inexperience means I'm using the wrong "keywords" in searches, or the answer involves jquery beyond my comprehension.
I have script experience and have plug-in galleryView working but have no jQuery experience which is the problem.
The script:
<script type="text/javascript"> name = getValue("name"); $(document).ready(function(){
[Code]....
Variable name contains data stripped from the page URL (www.url.com?name=3). I want to use this variable in the jquery array/list passed into the galleryView instead of the number 3. How can this be achieved? I suspect this could be done entirely in jquery (if I had the experience) or via the getdata script used above?
I am trying to pass a variable from gsp to jquery. But I have a problam.I have variable a which contains 635 element. like this a = [2,555,43,32,43,........]Here I am grabing this value fromgsp to jquery..
I have this image gallery in which clients should be able to determine the order in which their images are shown. The sortable part works. Then I want to pass the new order to the next page called act_writeneworder.cfm (i am using coldfusion) I just started with jQuery and it is driving me nuts:-) Each time I think I am having it well i am testing and the variable passed through gives an empty string. My code:
I can't seem to get a variable declared from within a post callback, so that I could manipulate my script accordingly. I have delete.php, that deletes an id from a mysql db. If it fails, I want the script to stop and display the error. The .php script echos an "ok" if everything went fine, if not - it echos the error.var abort_error; // set the error variable
I've made a made a lovely form which is loaded into a dialog upon clicking a link. Works fine, but I want something which identifies they URL clicked on initially (e.g. /stats.php?id=bob ) to end up as a hidden form field. Should be easy but I can't get the syntax/logic right.
I'm passing a variable to a selector. I have found a few resources and tried to implement them but they're just not working for me. I am trying to find href that match my variable and am working with the following:
var itemLink = /site/Mario-Kart..etc. $("a[href=" + itemLink + "]").......etc.
I receive an error "Uncaught Syntax Error unrecognized expression: [href=/site/Mario-Kart..etc. ]" I have been placing the quotes in different places to correct the syntax but to no avail. Also, this works with JQuery v1.44 and earlier but not after.