JQuery :: Form Functionality That Compares Value Submitted To Hidden Fields
Jun 21, 2010
I have a form I'm going to present to visitors. The goal is that when a visitor enters a Zip Code, for the form to compare that Zip Code submitted to Zip Codes that I'll hide in the form. I'm not sure if it's better to have the hidden zip code values as comma separated or just let them have their own individual hidden input fields. When the form is submitted, I need it to check and find out if the submitted zip code matches any of the hidden zip codes. If any of the hidden values match the submitted value, I want to be able to have a hidden div be shown, but if the form is submitted and there are no zip codes that match, show another div.
I am re-developing my website and want to use some Ajax/jQuery in it (so I am learning as I go) and I am not sure if this is possible so that is my first question:I have a registration form and I would like to know if after the person registering has completed their first and surname and the 2 sections of their postcode if I can use jQuery to run a PHP script to see if they are already registered before waiting for the form to be submitted and running a script then.I am thinking onkeyup (or similar) after the last field is completed but I don't know how that would work needing to also use 3 other field values.If this is possible, can anyone give me any ideas of examples that do this or how I can go about passing all the variables and running the scripts at the correct time.
I have a form with an inputbox and the value of that input box needs to be also assigned to a hidden field.[code]Here is the hidden field I need the above value assigned to.[code]
The problem is that when you click the link, the page simply reloads to a blank page with the only code being the hidden field. This is not what I want, I want the hidden field code to be passed along, and then for the form to submit. So, what should have is that the hidden field code is added, and then the form submits.
I'm trying to combine 3 form input fields into 1 that is hidden (Date of Birth). The input fields are DOB-MM, DOB-DD, and DOB-YYYY and the hidden field is DOB which will store the Date of Birth in the following format 'YYYY-MM-DD'. Unfortunately I don't know javascript write a quick script that will combine these 3 fields and arrange them in the format required.
I have a form that has 50 text fields and a corresponding hidden field for each of these. i.e. textfield1 hiddenfield1 etc. When the textfield has data entered it calls a script but I want the script to change the corresponding hidden field but am stuck as to how to do this. I have the following function which gets called: function addOptions(currentRole) { document.addGroup.['use_role_'+currentRole].value='Y'; } How to get this work work. Where I have ['use_role_'+currentRole] the currentRole should be replaced with the number (1 - 50) so as to change use_role_23 if currentRole is 23.
I have a flash file that calls this JS function. It basically adds a number to a comma separated string. this works fine.
var select = ""; function selectCounty (cid){ select = cid + "," + select; } The flash also calls this function to remove a value from the string. The removeVal() function works. though, the *select* variable is not reforming into a string. I'm missing how to then put the array into a form that this is part of.
function unSelectCounty (cid){ // split the *select* string into an array var select_array = select.split(/,/);
// remove *cid* value from array unselect = removeVal(select_array, cid);
// reset *select* var select = ""; for (i=0;i<unselect.length;i++){ if (unselect[i] != ''){ select = unselect[i] + "," + select; } } } function removeVal(arr, valToRemove){ // Normalize to a string like !val!!val!!val! var s = '!' + arr.join('!!') + '!' // Remove targeted values with delimiters s = s.replace(new RegExp('!' + valToRemove + '!', 'g'), ''); // Remove delimiter added to end in step 1 s = s.replace(/^!/, ''); // Remove delimiter added to start in step 1 s = s.replace(/!$/, ''); // Convert to array return s.split('!!'); } Please help with these two problems-
1) i cant get the *select* string in unSelectCounty() to reform correctly. 2) i am unsure what to write so that the value of *select* is passed in POST form array. it can accept it either as an array or a string.
so I am working on getting the file names that are uploaded through uploadify entered into a database table - I am using the method posted here . Supposedly after all the uploads complete, a hidden form field should be appended to my form (form1) with the name of the file that was just uploaded (in the onComplete call) - the problem is after the file is uploaded, I don't see any hidden form fields in the page source, and also the filename that is being returned is not the unique name (in the upload script). Here is the code:
I am pretty new at javascript and I am trying to create a payment form that has both fields for payment by check and payment by credit card.I am wondering how I would go about having a radio button that asks the user how they would like to pay "credit card" or "check" and depending on which one they pick it shows the fields pertaining to that type of payment.the fields in the form look like this:Credit Card Fields:
var inputCounter = 0; function addInput(divName){ var newdiv = document.createElement('div');
[Code].....
was working perfectly, until i did some minor changes to the script that was not even related to that part of the script, and it now shows Notice: Undefined index: f1 in C:Apache2.2htdocs sindex.php on line xxx meaning that the data is not set anymore. everything else is working perfectly. the fields are still added as before, but the data does not post. what might cause this not to work all of a sudden?
I have multiple fields in a form with the same name. Lets call the fields with the same name "junk_array". My first field of junk_array is a input type=hidden. All the others fields in junk_array that follow are type=text. I can reference this first hidden field in IE with document.form.field[0].value. In, fact my form works absolutely wonderful in IE 6. However, netscape 4.7 does not recognize my first field in the array as the hidden field. Netscape sees the first visible text field as the first field in the array, subscript 0. What totally and utterly perplexes me, is that, from a previous thread, I can do this and get 9999 back in an alert box in Netscape and IE. So, this proves Netscape doesn't have some evil code that disregards hidden fields. I guess...
I even copied these fields directly below the opening <form> tag in my form and both Netscape and IE see the first hidden field as as subscript 0.
However, my form is much more complicated. I have tables within tables and about 30 other fields. In my form I cannot for the life of me get Netscape to recognize the first hidden field of junk_array to zed as index 0.
Somehow, If I make the first type=hidden fields visible, netscape does work nicely. Why when I toggle type=hidden to type=text does Netscape cooperate. What is happening here? Anyone else have this problem with hidden fields in Netscape? I could post the code to my form but it is big.
There are two input fields in a form, but only one of them is required, they are not required at the same time. Either A or B is required. ( A is required OR B is required). In other words, a user can input data to field A, or he can input data to filed B, but he can not input data to Both A and B at the same time. How to implement this constraint in Jquery form validation?
I have some function to fire when I click a submit button. When I do that a form does not submit anything, it just fire my function etc. Here is my code: $("#hm-submit-form").click(function () { $("#nav ul li.products").delay(200).fadeIn(); $("#nav ul li.agel-tour").delay(600).fadeIn(); $("#nav ul li.compensation").delay(1000).fadeIn(); $("#thanks-box").delay(200).fadeIn(); $("#thanks-box").delay(1500).fadeOut(); $('#target').submit(); //this I guess should submit a form
What I want to do is replace a form with the submitted content. As an example, The form is submitted using the jquery.form plugin. The content is saved to the DB and a rendered comment is passed back to the client, and the success callback then replaces the form with the content. Simple enough. However, if server-side validation fails, I want to render the form, along with validation error messages, and insert that back into the client page, i.e. replace the first form with the second (which also contains the submitted content). Also straightforward, except that, on a truly successful submission, I'll need to do some other things on the page. If validation fails I only need to display the form with errors. I can think of two approaches. One is to search the returned data for some string (e.g., "<form") to decide if the other tasks are to be run.
The other is to send back the data encapsulated in a JSON object, eg: { 'status': 'FAIL', 'data': '<form ...' messages: '...' }
I've an input field in the form which is displayed based on the user selection. Initially it is set to 'display:none' and I do have a validation rule for that field.
How do I skip validation on this hidden input field and only validate when its displayed on the page.
In my application,there are several autocomplte field is available.When I type "pank" and then it list out the several matching in the autocomplete field and select one and then hit the enter then it submitted the entire form, which will cause the error message. Because there are several more mandatory field are there, which i need to fill up.I was trying to restrict in this way, but i believe this is the wrong way.
I have email, password and some other fields, and I'm using $.post to send data.
In Ajax form submission, I don't want to submit a particular field. The serializeArray() method returns all the fields in the form. So, I tried something like this to prevent the password field being serialized.
This works great but the ajax submission doen't work.
I have a page which displays a list of resources in the database. For each of these resources I have a comment form. I am using jQuery form plugin to submit the form through ajax. After submitting I want to display the comment which was just submitted w/o reloading the page. But how do I know which form was submitted? I attach the resource ID as a GET variable to the action url of the form. If I can get the action url then I think I'm saved.
How can I target a specific <div> to display the result of a form? I would like to be able to specify the target div on a per-form basis, and have the target independent of the <div> that contained the actual form.
So for example I may have a form in <div id="left"> <form>.....</form></div>, that I want to post the data to somepage.php, and load somepage.php into <div id="right">
I'm trying to add jQuery validate plugin functionality to a D7 form. Here's what I've done so far: Enabled jQuery update module, so we're using jQuery 1.4.2 validate plugin in my theme's script folder Created form.js & called both it, and the validate plugin, in my .info file
Here's the initial contents of form.js:
(function ($) { $(document).ready(function() { // validate signup form on keyup and submit var validator = $("#webform-client-form-53").validate({
[Code].....
The error is an unexpected "(". This is the syntax shown in the documentation, so I don't see what’s wrong here. After some checking, I was able to determine that it's the 2nd "(" that in line 6 that is being flagged.
I have a form which has a few submit buttons, all named SubmitButton so I can pass the clicked button's value through to the submission processor and then act according to which button is pressed. However on the jquery form submit even, I also want to check certain things before I fire the submission off. As the button isn't a "conventional" input I can't check the document object to see which one was clicked, so I need to check the form contents that are about to be submitted, can I do this from the submission event or will I have to bind to each button individually?
I use unordered list item (<ul>) to replace select type <select> (select) in my form. I have problem on bind the value after submit the form. Because <ul> is not a form element. May i know how should I overcome it?
What i intend to do is similar effect as google contact book: 1. User click ADD button, then <ul> and <textbox> will be appended into the form. 2. After form submitted, user can see what are the value he has entered earlier. I can bind the textbox, post the unorder list item with hidden element. but i have no clue how to bind the unordered list item..
Kindly refer to my code as below. It is working except cannot bind unordered list item... p/s: I am using PHP + JQuery.
